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" If two straight lines cut one another within a circle, the rectangle contained by the segments of one of them, is equal to the rectangle contained by the segments of the other. "
Mathematical Exercises ...: Examples in Pure Mathematics, Statics, Dynamics ... - Σελίδα 184
των Samuel H. Winter - 1877 - 413 σελίδες
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An Easy Introduction to the Mathematics: In which the Theory and ..., Τόμος 2

Charles Butler - 1814 - 528 σελίδες
...If two straight lines cut one another, and the rectangle contained by the segments of one of them, be equal to the rectangle contained by the segments of the other, the circumference which passes through three of the extremities of the two given straight lines, shall...

An Elementary Treatise on the Geometrical and Algebraical Investigation of ...

Daniel Cresswell - 1817 - 454 σελίδες
...be equal to one another. (LXXV.) To divide a given straight line into two parts, so that the square of the one shall be equal to the rectangle contained by the other and a given straight line. (LXXVI.) If a given circle be cut by any number of circles, which...

A Supplement to the Elements of Euclid

Daniel Cresswell - 1819 - 446 σελίδες
...another. PROP. LXXXI. 106. PROBLEM. To divide a given straight line into two parts, so that the square of the one shall be equal to the rectangle contained by the other and a given straight line. Let AB and L be two given finite straight F Gr E lines : It is required...

Geometrical Problems Deducible from the First Six Books of Euclid, Arranged ...

Miles Bland - 1819 - 442 σελίδες
...part ; (m) being whole or fractional. 11. To divide a given line into two such purls, that the square of the one shall be equal to the rectangle contained by the other and a given line. 12. A straight line being given in magnitude and position ; to draw to it,...

Geometrical Problems Deducible from the First Six Books of Euclid, Arranged ...

Miles Bland - 1819 - 444 σελίδες
...part ; (m) being whole or fractional. 11. To divide a given line into two such parts, that the square of the one shall be equal to the rectangle contained by the other and a given line. 12. A straight line being given in magnitude aud position ; to draw to it,...

A companion to Euclid: being a help to the understanding and remembering of ...

Euclides - 1837 - 112 σελίδες
...straight lines within a circle cut each other, the rectangle contained by the segments of one of them is equal to the rectangle contained by the segments of the other. • In case 1st, E is the centre of the 0, and evident that AE x EC = BE x ED. it is Steps of the Demonstration...

The First Six and the Eleventh and Twelfth Books of Euclid's Elements: With ...

Euclid, James Thomson - 1837 - 410 σελίδες
...IF two chords of a circle cut one another, the rectangle contained by the segments of one of them is equal to the rectangle contained by the segments of the other. In the circle ABCD, let the two chords AC, BD cut one another in the point E : the rectangle AE.EC is...

Euclid's Elements [book 1-6] with corrections, by J.R. Young

Euclides - 1838 - 264 σελίδες
...is cut off, containing an angle equal to the given angle D. Which was to be done. PROP. XXXV. THEOR. If two straight lines cut one another within a circle, the rectangle contained by the segments of one of them is equal to the rectangle contained by the segments of the other. Let the two straight...

The Elements of Euclid; viz. the first six books,together with the eleventh ...

Euclides - 1841 - 378 σελίδες
...is cut off, containing an angle equal to the given angle D. Which was to be done. PROP. XXXV. THEOR. If two straight lines cut one another within a circle, the rectangle contained by the segments of one of them is equal to the rectangle contained by the segments of the other. Let the two straight...

A system of practical mathematics; being no.xvi. of a new series of school-books

Scottish school-book assoc - 1845 - 444 σελίδες
...PROPOSITION LXV — THEOREM. If two chords, AB, CD, cut one another in a point E, within a circle A CD, the rectangle contained by the segments of the one...rectangle contained by the segments of the other. That is, the rectangle AE-EB=CE-ED. Join CA and BD, then the Z.CAE is = the Z.BDE ; for they stand...




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