Daboll's Schoolmaster's Assistant, Improved and EnlargedS. Green, 1825 - 240 σελίδες |
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Σελίδα 25
... remainder as 4 dollars subtracted from 6 dollars , the remainder is two dollars . RULE . Place the least number under the greatest , so that units may stand under units , tens under tens , & c . and draw a line under them . 2. Begin at ...
... remainder as 4 dollars subtracted from 6 dollars , the remainder is two dollars . RULE . Place the least number under the greatest , so that units may stand under units , tens under tens , & c . and draw a line under them . 2. Begin at ...
Σελίδα 34
... remainder ; after which , you must seek , multiply and subtract , till you have brought down every figure of the dividend . PROOF . Multiply the divisor and quotient together and add the remainder if there be any to the product ; if the ...
... remainder ; after which , you must seek , multiply and subtract , till you have brought down every figure of the dividend . PROOF . Multiply the divisor and quotient together and add the remainder if there be any to the product ; if the ...
Σελίδα 35
... Remainder . Divisor , Div.Quotient . 29 ) 15359 ( 529 $ 65 ) 49640 ( 136 365 145 Proof by excess of 9's 85 1314 5 58 1095 279 2190 261 2190 18 O Rem . Remains together , according to the order in which they stand in the work ; and this ...
... Remainder . Divisor , Div.Quotient . 29 ) 15359 ( 529 $ 65 ) 49640 ( 136 365 145 Proof by excess of 9's 85 1314 5 58 1095 279 2190 261 2190 18 O Rem . Remains together , according to the order in which they stand in the work ; and this ...
Σελίδα 38
... Remainder . 9182 .0 When there are cyphers at the right hand of the divi- sor ; cut off the cyphers in the divisor , and the same number of figures from the right hand of the dividend , then divide the remaining ones as usual , and to ...
... Remainder . 9182 .0 When there are cyphers at the right hand of the divi- sor ; cut off the cyphers in the divisor , and the same number of figures from the right hand of the dividend , then divide the remaining ones as usual , and to ...
Σελίδα 39
... remainder is found by the last remainder by the first divisor , and irst remainder , mutrp ving cang in the 13. What cost 144 lb. of Indigo , at 2 CONTRACTIONS IN DIVISION . $ 7.
... remainder is found by the last remainder by the first divisor , and irst remainder , mutrp ving cang in the 13. What cost 144 lb. of Indigo , at 2 CONTRACTIONS IN DIVISION . $ 7.
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Συχνά εμφανιζόμενοι όροι και φράσεις
100 dollars 2qrs 3grs acres annex annuity annum answer Anthony Billings arithmetical arithmetical series barter Bought bushels compound interest contain cyphers Deduct demand denomination dimes divide the product dividend divisor dols equal EXAMPLES federal money Find the value gain or loss gallon geometrical series given number given sum hundred improper fraction inches least common multiple left hand measure merchants miles mills milreas mixed numbers months Multiply the given New-England currency New-Jersey NOTE number of shillings number of terms paid payment pence piece pound pound sterling present worth principal quotient rate per cent ratio ready money Reduce remainder Required the interest right hand rods Rule of Three s. d. gr sell separatrix simple interest sold solid feet Sqrs square root Sterling subtract tare third Thomas Grosvenor trett TROY WEIGHT VULGAR FRACTIONS whole numbers wine
Δημοφιλή αποσπάσματα
Σελίδα 80 - ... from the right hand of the quotient, point off so many places for decimals, as the decimal places in the dividend exceed those in the divisor.
Σελίδα 173 - RULE. 1 . Separate the given number into periods of three figures each, by putting a point over the unit figure and every third figure bejond the place of units. 2. Find the greatest cube in the left hand period, and put its root in the quotient. 3.
Σελίδα 183 - The first term, the last term (or the extremes) and the ratio given, to find the sum of the series. RULE. Multiply the last term by the ratio, and from the product subtract the first term ; then divide the remainder by the ratio, less by l,and the quotient will be the sum of all the terms.
Σελίδα 188 - If the errors are alike, divide the difference of the products by the difference of the errors, and the quotient will be the answer. .5. If the errors are unlike, divide the sum of the products by the sum of the errors, and the quotient will bo the answer.
Σελίδα 210 - Ixos being given, to find how many bushels it will contain. RULE. Multiply the length by the breadth, and that product by the depth, divide the last product by 2150,425 the solid inches in a statute bushel, and the quotient will be the answer. EXAMPLE. There is a square...
Σελίδα 190 - To find the number of Permutations or changes, that can be made of any given number of things, all different from each other RULE.
Σελίδα 121 - Cast the interest on the several payments, from the time they were paid, to the time of settlement, and find their amount ; and lastly deduct the amount of the several payments, from the amount of the principal.
Σελίδα 147 - CASE II. , To reduce a mixed number to its equivalent improper fraction. RULE. Multiply the whole number...
Σελίδα 165 - COMPUTE the interest on the principal sum, from the time when the interest commenced to the first time when a payment was made, which exceeds either alone or in conjunction with the preceding payments (if any) the interest at that time due: add that interest to the principal, and from the sum subtract the payment made at that time, together with the preceding payments (if any) and the remainder forms a new principal ; on which, compute and subtract the interest, as upon the first principal: and proceed...
Σελίδα 176 - Alligation alternate is the method of finding what quantity of any number of simples, whose rates are given, will compose a mixture of a given rate ; so that it is the reverse of Alligation medial, and may be proved by it. RULE 1.* 1. Write the rates of the simples in a column under each other.