 | James Bates Thomson - 1848 - 432 σελίδες
...1. Jjivide the dividend by one of the factors of the divisor, then divide the quotient thus obtained by another factor ; and so on till all the factors are employed. The last quotient will be the answer. II. To find the true remainder. If the divisor is resolved into but two... | |
 | James Bates Thomson - 1849 - 438 σελίδες
...Divide tlie dividend by one of tlie factors of tlue divisor, then divide the quotient thus obtained by another factor ; and so on till all the factors are employed. The last quotient mill be the answer. II. To find the true remainder. If the divisor is resolved into but two... | |
 | James Cornwell - 1855 - 380 σελίδες
...WHEN THE MULTIPLIER is GREATEE THAN 10, AND ITS EACTOES ARE KNOWN — RULE. Multiply by one factor, and that product by another factor, and so on till all the factors have been employed. Example.— Multiply 3247 by 56. 56 = 7 X 8. 3247 7 22729 = 3247 X 7 8 181832 =... | |
 | James Bates Thomson - 1860 - 402 σελίδες
...I. Divide the dividend by one of the f acton of the divisor, then divide the quotient thus obtained by another factor, and so on till all the factors are employed. The laxt quotient will be the answer. fins. 1. This contraction depends upon the principle, that if the... | |
 | George Augustus Walton - 1864 - 364 σελίδες
...MULTIPLY BY A COMPOSITE NUMBER, ie, BY A NUMBER THAT is ITSELF THE PRODUCT OF TWO OR MORS NUMBERS. Separate the multiplier into convenient factors, multiply...so on, till all the factors are employed ; the last prod* net is the true answer ; thus, 41 X 25 = 41 X 5 X 5. EXAMPLES. 1. Multiply 368 by 72 ; by 36.... | |
 | George Augustus Walton - 1864 - 376 σελίδες
...MULTIPLY BY A. COMPOSITE NUMBER, í. e., BY A NUMBER THAT is ITSELF THE PRODUCT- OF TWO OR MORE NUMBERS. Separate the multiplier into convenient factors, multiply...so on, till all the factors are employed ; the last prod' uct is the true answer ; thus, 41 X 25 = 41 X 5 X 5. EXAMPLES. 1. Multiply 368 by 72 ; by 36.... | |
 | George Augustus Walton, Mrs. Electra Nobles Lincoln Walton - 1865 - 354 σελίδες
...MULTIPLY BY A COMPOSITE NUMBER, ie, BY A NUMBER THAT is ITSELF THE PRODUCT OP TWO OR MORE NUMBERS. Separate the multiplier into convenient^ factors,...till all the factors are employed; the last product is the true answer ; thus, 41 X 25 = 41 X 5 X 5. EXAMPLES. 1. Multiply 368 by 72 ; by 36. 2. Multiply... | |
 | James Bates Thomson - 1868 - 168 σελίδες
...composite number. Divide the dividend by one of the factors, then divide the quotient thus obtained by another factor, and so on till all the factors are employed. The last quotient will be the answer. 47. Divide 231 by 21, using its factors. Ans. 11. 48. Divide 195 by 16,... | |
 | Henry Bartlett Maglathlin - 1869 - 332 σελίδες
...contained any other convenient set of A 1 ^820 factors, they could have been used in like manner. RULE. Separate the multiplier into convenient factors. Multiply the multiplicand by one of these factors, and the product by another, and so on, until all the factors have been used. The last... | |
 | George Augustus Walton, Electa N. L. Walton - 1871 - 348 σελίδες
...998 = ? (69000 — 69 X 2) Ans. 68,862. 7. 549 X 9990 = ? (5490000 — 549 X 10) Ans. 5,484,510. 693 To MULTIPLY BY A COMPOSITE NUMBER. Separate the multiplier into convenient factors, multiply the multtplv cand by one of the factors, and that product by another factor, and so on till all the factors... | |
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Separate the multiplier into convenient factors, multiply the multiplicand by one of the factors, and that product by another factor, and so on, till all the factors are employed ; the last prod* net is the true answer ; thus, 41 X 25 = 41 X 5 X 5. 
