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" C, and a2 = 62 + c2 — 2bc cos A. 14. In any triangle to prove that the sines of the angles are proportional to the opposite sides, ie that sin A_ sin B _ sin O "~a E ~ — AD In Fig. "
Astronomy Without a Telescope: Being a Guide-book to the Visible Heavens ... - Σελίδα 128
1869 - 104 σελίδες
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Transactions of the Cambridge Philosophical Society

Cambridge Philosophical Society - 1838 - 618 σελίδες
...solutions to the problem enunciated in Art. 1. Their evident analogy to the property of a triangle "that the sines of the angles are proportional to the opposite sides", has suggested another form under which they may be put. 12. The hypothesis and notation of Art. 10....

Report on the examination for admission to the Royal military academy at ...

Woolwich roy. military acad - 1861 - 572 σελίδες
...base. 7. Calculate by logarithms, /42-666N" /-0765Y V T147 / X\l-9432/ 8. In any plane triangle show that the sines of the angles are proportional to the opposite sides. Show that sin (C-30°)=c2 + 2Jc sin (A-30°). 9. The elevations of two mountains in the same line with...

Mechanics and Hydrostatics for Beginners

Sidney Luxton Loney - 1905 - 332 σελίδες
...that C3 = aa + 6!1-2a6cos C, and o* = 6a + ca— 2bc cos A. i,. MH 19 14. In any triangle to prove that the sines of the angles are proportional to the opposite sides, ie that sin A sin B _ sin C a ~ b *»= ,£_ "\ AD In Fig 1. we have — j— = sin C. In Fig. 2, we...

Transactions of the Cambridge Philosophical Society

Cambridge Philosophical Society - 1838 - 612 σελίδες
...solutions to the problem enunciated in Art. 1. Their evident analogy to the property of a triangle " that the sines of the angles are proportional to the opposite sides", has suggested another form under which they may be put. 12. The hypothesis and notation of Art. 10....

Mechanics and Hydrostatics for Beginners

Sidney Luxton Loney - 1953 - 346 σελίδες
...relation. Similarly, we could prove that and o2 = 62 + c2 — 2bc cos A. 14. In any triangle to prove that the sines of the angles are proportional to the opposite sides, ie that In Fig. 1, Art. 13, we have - =aiuB. c AD In Fig. 2, we have - = sin A BD = sin (180' - B)...
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