Algebra for BeginnersMacmillan, 1895 - 188 σελίδες |
Αναζήτηση στο βιβλίο
Αποτελέσματα 1 - 5 από τα 15.
Σελίδα 24
... complete pro- duct is 6a6b7 . This result , however , may be written down at once : for 3a2b2a3b2x ab1 = 6ab7 , and by the rule of signs the re- quired product is positive . Example 4. Multiply 6a3 - 5a2b - 4ab2 by -3ab2 . The product ...
... complete pro- duct is 6a6b7 . This result , however , may be written down at once : for 3a2b2a3b2x ab1 = 6ab7 , and by the rule of signs the re- quired product is positive . Example 4. Multiply 6a3 - 5a2b - 4ab2 by -3ab2 . The product ...
Σελίδα 34
... complete quotient is found by taking the sum of all the partial quotients . By the above process a2 + 11 + 30 is separated into two parts , namely +62 , and 5.r + 30 , and each of these is divided by x + 6 ; thus we obtain the partial ...
... complete quotient is found by taking the sum of all the partial quotients . By the above process a2 + 11 + 30 is separated into two parts , namely +62 , and 5.r + 30 , and each of these is divided by x + 6 ; thus we obtain the partial ...
Σελίδα 46
... complete discussion of the theory of Indices the student is referred to the Elementary Algebra , Chap . XXXI . It will be sufficient here to point out that the rules for combination of indices in multiplication and division given in ...
... complete discussion of the theory of Indices the student is referred to the Elementary Algebra , Chap . XXXI . It will be sufficient here to point out that the rules for combination of indices in multiplication and division given in ...
Σελίδα 78
... the equations we use to complete the solution . Thus , in the present example , if we substitute 3 for y in ( 2 ) , we have 5x + 6 = 16 ; .. x = 2 , as before . Example 2. Solve 7x + 2y = 47 ( 1 78 [ СНАР . ALGEBRA .
... the equations we use to complete the solution . Thus , in the present example , if we substitute 3 for y in ( 2 ) , we have 5x + 6 = 16 ; .. x = 2 , as before . Example 2. Solve 7x + 2y = 47 ( 1 78 [ СНАР . ALGEBRA .
Σελίδα 94
... complete square , and its square root written down at once . Example 1. Find the square root of 2522 - 40xy + 16y2 . The expression = ( 5x ) 2 - 2. 20xy + ( 4y ) 2 = ( 5x ) 2 – 2 ( 5x ) ( 4y ) + ( 4y ) 2 = = ( 5x – 4y ) 2 . Thus the ...
... complete square , and its square root written down at once . Example 1. Find the square root of 2522 - 40xy + 16y2 . The expression = ( 5x ) 2 - 2. 20xy + ( 4y ) 2 = ( 5x ) 2 – 2 ( 5x ) ( 4y ) + ( 4y ) 2 = = ( 5x – 4y ) 2 . Thus the ...
Συχνά εμφανιζόμενοι όροι και φράσεις
a²+b² acres algebraical sum Arithmetic arranged beginner cents CHAPTER coefficient Completing the square compound expressions convenient cube root descending powers difference digits dimes Divide division divisor Elementary Algebra equal examples see Elementary EXAMPLES XVII exceeds Find the highest Find the lowest find the number Find the product Find the square Find the sum find the value following expressions given expressions half-dollars Hence highest common factor lowest common denominator lowest common multiple lowest terms miles an hour miles per hour minute-hand Multiply negative numerator and denominator obtain quadratic equation quotient Reduce to lowest remainder removing brackets Resolve into factors result rule of signs side simple equation simultaneous equations Solve the equations square root Subtract Transposing trinomial unknown quantities walk whence write yards α α
Δημοφιλή αποσπάσματα
Σελίδα 91 - The product is a2+2a6-}-62; from which it appears, that the square of the sum of two quantities, is equal to the square of the first plus twice the product of the first by the second, plus the square of the second.
Σελίδα 107 - Conversely, the difference of the squares of any two quantities is equal to the product of the sum and the difference of the two quantities.
Σελίδα 89 - It is evident from the Rule of Signs that (1) no even power of any quantity can be negative; (2) any odd power of a quantity will have the same sign as the quantity itself. NOTE. It is especially worthy of notice that the square of every expression, whether positive or negative, is positive.
Σελίδα 54 - Transpose all the terms containing the unknown quantity to one side of the equation, and the "known quantities to the other.