Complete Schoolmaster's Assistant: Being a Plain Comprehensive System of Practical Arithmetic: Adapted to the Use of Schools in the United States ...W.&J.Bolles, 1839 |
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Σελίδα 3
... received a greater share of public patronage than Daboll's Schoolmaster's Assistant : But it must be obvious to teachers of Arithmetic , and also to men of business , that Arith- metics written some thirty or forty years ago , however ...
... received a greater share of public patronage than Daboll's Schoolmaster's Assistant : But it must be obvious to teachers of Arithmetic , and also to men of business , that Arith- metics written some thirty or forty years ago , however ...
Σελίδα 4
... received that attention which their importance demands ; being simplified and illustrated in such a manner as to render the study of them pleasing and interesting to the pupil . In Simple Interest several short rules are given . Also ...
... received that attention which their importance demands ; being simplified and illustrated in such a manner as to render the study of them pleasing and interesting to the pupil . In Simple Interest several short rules are given . Also ...
Σελίδα 26
... received 411 dollars , 88 cents and B received just three times as much money as A received ; how much mo- ney did B receive ? Ans . 1235,64 . 12. B paid me $ 98,56 , C paid me just four times as much as B , and D paid me just as much ...
... received 411 dollars , 88 cents and B received just three times as much money as A received ; how much mo- ney did B receive ? Ans . 1235,64 . 12. B paid me $ 98,56 , C paid me just four times as much as B , and D paid me just as much ...
Σελίδα 46
... received 2943 cents for melons that he sold at 9 cents apiece ; how many did he sell ? Ans . 327 . 16. How many times is 7 contained in 6680 , and how many over ? Ans . 954 times , and 2 over . 17. A merchant has $ 5122 to purchase ...
... received 2943 cents for melons that he sold at 9 cents apiece ; how many did he sell ? Ans . 327 . 16. How many times is 7 contained in 6680 , and how many over ? Ans . 954 times , and 2 over . 17. A merchant has $ 5122 to purchase ...
Σελίδα 61
... received $ 51,75 in part payment : how much remains due ? Ans . $ 32 . 5. How many yards of cloth at $ 3 per yard , may be had for 136 bushels of wheat at $ 2 per bushel ? Ans . 90 yards . Find the amount of the following . BILLS . 1 ...
... received $ 51,75 in part payment : how much remains due ? Ans . $ 32 . 5. How many yards of cloth at $ 3 per yard , may be had for 136 bushels of wheat at $ 2 per bushel ? Ans . 90 yards . Find the amount of the following . BILLS . 1 ...
Άλλες εκδόσεις - Προβολή όλων
Complete Schoolmaster's Assistant: Being a Plain Comprehensive System of ... Nathan Daboll Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2016 |
Συχνά εμφανιζόμενοι όροι και φράσεις
2qrs 3qrs acres 3 roods annex annuity answer Arithmetic barrels bought broadcloth bushels called cent per annum ciphers circumference common denominator common difference Compound Interest contained cords cost cube root currency diameter dividend dollars dols equal EXAMPLES farthings Federal money find the amount find the present Find the sum Find the value foot frustrum gain or loss gallons given number given sum greatest common divisor hogshead hundred improper fraction last term leave length lowest terms merchant miles mills mixed number months multiplicand Multiply Note number of terms paid payment pence pint pound present worth principal PROB proportion quantity quarts Questions quotient rate per cent ratio Reduce remainder right hand Rule of Three separatrix shillings sold solid contents square rods square root subtract subtrahend tens third term thousand units VULGAR FRACTIONS weight whole number yards of cloth
Δημοφιλή αποσπάσματα
Σελίδα 205 - Given the first term, last term, and common difference, to find the number of terms. RULE. — Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms.
Σελίδα 189 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Σελίδα 193 - Find the first figure of the root by trial, and subtract its power from the left hand period of the given number. 3. To the remainder bring down the first figure in the next period, and call it the dividend. 4. Involve the root to the next inferior power to that which is given, and multiply it by the number denoting the given power, for a divisor.
Σελίδα 122 - A and B depart from the same, place and travel the same road ; but A goes 5 days before B, at the rate of 15 miles a day . B follows at the rate of 20 miles a . day } what distance must he travel to overtake A ? Ans. 300 miles RULE OF THREE INVERSE.
Σελίδα 181 - ... subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained...
Σελίδα 88 - To reduce an improper fraction to a whole or mixed number. RULE. Divide the numerator by the denominator, and the quotient will be the whole or mixed number sought.
Σελίδα 124 - ... multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination as the third term.
Σελίδα 231 - To measure a Parallelogram, or long square. RULE. Multiply the length by the breadth, and the product will be the area or superficial content.
Σελίδα 173 - Multiply the numerators together for a new numerator, and the denominators together for a new denominator.
Σελίδα 178 - If a footman travel 130 miles in 3 days, when the days are 12 hours long ; in how many days, of 10 hours each, may he travel 360 miles ? Ans. 9|f days. 5. If 120 bushels of corn can serve 14 horses 56 days, how many days will 94 bushels serve 6 horses?