A System of Practical Arithmetic: Applicable to the Present State of Trade, and Money Transactions: Illustrated by Numerous Examples Under Each Rule; for the Use of SchoolsR. Phillips, 1812 - 258 σελίδες |
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Σελίδα 6
... Answer • 66424 is the sum total . PROOF . Add the numbers together in a contrary order , beginning at the top instead of the bottom . NOTES . * Ten on the right - hand line is equal only to one , or unit , in the next line on the left ...
... Answer • 66424 is the sum total . PROOF . Add the numbers together in a contrary order , beginning at the top instead of the bottom . NOTES . * Ten on the right - hand line is equal only to one , or unit , in the next line on the left ...
Σελίδα 7
... answer to the question of how many are 36 and 7 , or 46 and 7 , and so on , ADDITION TABLE . 2 3 4 5 6 7 F 8 9 2 4 5 6 7 8 9 10 11 3 5 6 7 8 9 10 11 12 4 6 7 8 9 10 11 12 13 Cit 5 7 8 9 10 11 12 13 14 6 8 9 10 11 12 12 13 14 15 7 9 10 ...
... answer to the question of how many are 36 and 7 , or 46 and 7 , and so on , ADDITION TABLE . 2 3 4 5 6 7 F 8 9 2 4 5 6 7 8 9 10 11 3 5 6 7 8 9 10 11 12 4 6 7 8 9 10 11 12 13 Cit 5 7 8 9 10 11 12 13 14 6 8 9 10 11 12 12 13 14 15 7 9 10 ...
Σελίδα 11
... : equal to 30 .. The learner must refer to the table of contents of his Bible , to ena-- ble him to answer this and the two following examples . SUBTRACTION . BY SUBTRACTION we find the difference between two ADDITION . II.
... : equal to 30 .. The learner must refer to the table of contents of his Bible , to ena-- ble him to answer this and the two following examples . SUBTRACTION . BY SUBTRACTION we find the difference between two ADDITION . II.
Σελίδα 12
... answer is 17. It will be the same if I sav 8 from 15 and there remains 7 , and then making the 4 into 3 , by taking from it the one I borrowed , I say 2 from 3 and there remains 1 ; the answer is still 17 . I See Table , p . 7 , with ...
... answer is 17. It will be the same if I sav 8 from 15 and there remains 7 , and then making the 4 into 3 , by taking from it the one I borrowed , I say 2 from 3 and there remains 1 ; the answer is still 17 . I See Table , p . 7 , with ...
Σελίδα 15
... answer , in an instant , any possible question that can be formed from it ; and if he has attended to what was said in Addi- tion , p , 8 , the greater part of the difficulty will be already overcome . As soon I. When the Multiplier ...
... answer , in an instant , any possible question that can be formed from it ; and if he has attended to what was said in Addi- tion , p , 8 , the greater part of the difficulty will be already overcome . As soon I. When the Multiplier ...
Άλλες εκδόσεις - Προβολή όλων
A System of Practical Arithmetic, Applicable to the Present State of Trade ... Jeremiah Joyce Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2018 |
A System of Practical Arithmetic, Applicable to the Present State of Trade ... Jeremiah Joyce Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2015 |
Συχνά εμφανιζόμενοι όροι και φράσεις
9 Ex acres aliquot amount annual annuity annum answer arithmetical progression Avoirdupois bill bushels common denominator compound interest containing cost course of exchange cube root cubic cyphers decimal difference ditto divide dividend divisor equal EXAMPLES farthings feet figures find the value fraction gallons geometrical progression geometrical series given number given sum gives guineas per cent hogsheads hundred improper fractions inches insure joint lives last term lease logarithm London measure miles millions mixed numbers months multiplicand Multiply the number neat weight NOTE number of terms ounces paid payment pence person aged piastre pound sterling pounds present value purchase quantity quotient Reduce remainder Rule of Three shews shillings square root sterling subtract supposing tare thousand tons tret Troy TROY WEIGHT whole number wine worth yards
Δημοφιλή αποσπάσματα
Σελίδα 177 - Multiply each payment by the time at which it is due; then divide the sum of the products by the sum of the payments, and the quotient will be the equated time, nearly.
Σελίδα 112 - To reduce a mixed number to an improper fraction, — RULE : Multiply the whole number by the denominator of the fraction, to the product add the numerator, and write the result over the denominator.
Σελίδα 243 - Multiply each term into the multiplicand, beginning at the lowest, by the highest denomination in the multiplier, and write the result of each under its respective term ; observing to carry an unit for every 12, from each lower denomination to its next superior.
Σελίδα 92 - III. finally, multiply the second and third terms together, divide the product by the first, and the quotient will be the answer in the same denomination as the third term.
Σελίδα 150 - The first term, the last term (or the extremes) and the ratio given, to find the sum of the series. RULE. Multiply the last term by the ratio, and from the product subtract the first term ; then divide the remainder by the ratio, less by 1, and the quotient will be the sum of all the terms.
Σελίδα 113 - Multiply each numerator into all the denominators except its own for a new numerator, and all the denominators together for a common denominator.
Σελίδα 243 - In like manner, multiply all the multiplicand by the inches and parts of the multiplier, and set the result of each term one place removed to the right hand of those in the multiplicand...
Σελίδα 55 - Place the numbers so that those of the same denomination may stand directly under each other.
Σελίδα 149 - Given the first term, last term, and common difference, to find the number of terms. RULE. — Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms.
Σελίδα 28 - ... the number in the quotient. Multiply the divisor by the quotient figure, and set the product under that part of the dividend used. Subtract the product, last found, from that part of the dividend under which...