A System of Practical Arithmetic: Applicable to the Present State of Trade, and Money Transactions: Illustrated by Numerous Examples Under Each Rule; for the Use of SchoolsR. Phillips, 1812 - 258 σελίδες |
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Σελίδα 192
... lives 32 years , which he may reasonably expect ? * - Ex . 4. The year 1808 , is that in which the late Mr. Pitt calculated there would be four millions surplus to be applied to the payment of the national debt ; I demand to how much ...
... lives 32 years , which he may reasonably expect ? * - Ex . 4. The year 1808 , is that in which the late Mr. Pitt calculated there would be four millions surplus to be applied to the payment of the national debt ; I demand to how much ...
Σελίδα 195
... live 21 years ? Opposite to 21 years I find 35.719 , which multiplied by 50 , gives 1785.962550 . Answer , 1785l . 19s . 2d . Ex . 2. How much will an annuity of 351. amount to in 83 years ? Ex . 3. To what sum will an annuity of 100 ...
... live 21 years ? Opposite to 21 years I find 35.719 , which multiplied by 50 , gives 1785.962550 . Answer , 1785l . 19s . 2d . Ex . 2. How much will an annuity of 351. amount to in 83 years ? Ex . 3. To what sum will an annuity of 100 ...
Σελίδα 200
... 31 4310 32 4235 75 75 64 65 1712 80 1632 80 Note . 1. Here it must be observed that , of 11650 infants born , 3000 will die in the first year . Of the 8650 who live to be one year old , CASE I. To find , by this Table , the 200.
... 31 4310 32 4235 75 75 64 65 1712 80 1632 80 Note . 1. Here it must be observed that , of 11650 infants born , 3000 will die in the first year . Of the 8650 who live to be one year old , CASE I. To find , by this Table , the 200.
Σελίδα 201
... live to 60 ? The number against 60 The number against 45 For , since the probability of living is equal to or as - 5 : 3 ... lives , as 100 , aged 60 , will , one with another , enjoy 13 years 11 weeks each of existence , some of them ...
... live to 60 ? The number against 60 The number against 45 For , since the probability of living is equal to or as - 5 : 3 ... lives , as 100 , aged 60 , will , one with another , enjoy 13 years 11 weeks each of existence , some of them ...
Σελίδα 202
... live Ex . 4. What chance has a person aged 70 of living 10 years longer ? From the foregoing table is formed TABLE II . Shewing the Expectation of Human Life at every Age , according to the Probabilities found by Table I. Expecta ...
... live Ex . 4. What chance has a person aged 70 of living 10 years longer ? From the foregoing table is formed TABLE II . Shewing the Expectation of Human Life at every Age , according to the Probabilities found by Table I. Expecta ...
Άλλες εκδόσεις - Προβολή όλων
A System of Practical Arithmetic, Applicable to the Present State of Trade ... Jeremiah Joyce Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2018 |
A System of Practical Arithmetic, Applicable to the Present State of Trade ... Jeremiah Joyce Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2015 |
Συχνά εμφανιζόμενοι όροι και φράσεις
9 Ex acres aliquot amount annual annuity annum answer arithmetical progression Avoirdupois bill bushels common denominator compound interest containing cost course of exchange cube root cubic cyphers decimal difference ditto divide dividend divisor equal EXAMPLES farthings feet figures find the value fraction gallons geometrical progression geometrical series given number given sum gives guineas per cent hogsheads hundred improper fractions inches insure joint lives last term lease logarithm London measure miles millions mixed numbers months multiplicand Multiply the number neat weight NOTE number of terms ounces paid payment pence person aged piastre pound sterling pounds present value purchase quantity quotient Reduce remainder Rule of Three shews shillings square root sterling subtract supposing tare thousand tons tret Troy TROY WEIGHT whole number wine worth yards
Δημοφιλή αποσπάσματα
Σελίδα 177 - Multiply each payment by the time at which it is due; then divide the sum of the products by the sum of the payments, and the quotient will be the equated time, nearly.
Σελίδα 112 - To reduce a mixed number to an improper fraction, — RULE : Multiply the whole number by the denominator of the fraction, to the product add the numerator, and write the result over the denominator.
Σελίδα 243 - Multiply each term into the multiplicand, beginning at the lowest, by the highest denomination in the multiplier, and write the result of each under its respective term ; observing to carry an unit for every 12, from each lower denomination to its next superior.
Σελίδα 92 - III. finally, multiply the second and third terms together, divide the product by the first, and the quotient will be the answer in the same denomination as the third term.
Σελίδα 150 - The first term, the last term (or the extremes) and the ratio given, to find the sum of the series. RULE. Multiply the last term by the ratio, and from the product subtract the first term ; then divide the remainder by the ratio, less by 1, and the quotient will be the sum of all the terms.
Σελίδα 113 - Multiply each numerator into all the denominators except its own for a new numerator, and all the denominators together for a common denominator.
Σελίδα 243 - In like manner, multiply all the multiplicand by the inches and parts of the multiplier, and set the result of each term one place removed to the right hand of those in the multiplicand...
Σελίδα 55 - Place the numbers so that those of the same denomination may stand directly under each other.
Σελίδα 149 - Given the first term, last term, and common difference, to find the number of terms. RULE. — Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms.
Σελίδα 28 - ... the number in the quotient. Multiply the divisor by the quotient figure, and set the product under that part of the dividend used. Subtract the product, last found, from that part of the dividend under which...