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" ... term. Divide the product of the second and third terms by the first term, and the quotient will be the answer required. "
A Practical Treatise on Arithmetic ...: Combining the Useful Properties of ... - Σελίδα 337
των George Leonard (jr.) - 1841 - 340 σελίδες
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A New and Complete System of Arithmetick: Composed for the Use of the ...

Nicolas Pike - 1822 - 536 σελίδες
...term ; and that, which is of the same name or quality with the answer required, the second term. 2. Divide the product of the second and third terms by the first term and Ihe quotient will be the answer. .Vote. The directions under the General Rule, as well as...

The Western Practical Arithmetic: Wherein the Rules are Illustrated, and ...

1838 - 218 σελίδες
...by the first, the product shall be equal to the product of the second and third terms, hence if we divide the product of the second and third terms by the first term, we shall get the fourth term. In this manner let the fourth term be found in each of the following...

A Practical Treatise on Arithmetic, [etc.].

George Leonard - 1841 - 354 σελίδες
...the third term, make the larger of the other two numbers the second term, and the smaller the first term, but if the answer must be smaller than the third...examples, however, it is by the rule difficult or impossible to state the question, that is. to write down the proper numbers for the third, second,...

A Practical Treatise on Arithmetic: Wherein Every Principle Taught is ...

George Leonard - 1841 - 356 σελίδες
...the second term, and the smaller the first term, but if the answer must be smaller than the tJiird term, make the smaller of the other two numbers the...Afterwards. to get the answer, divide the product oft/ie second and third terms by the first. In many examples, however, it is by the rule difficult...

Arithmetic on the Productive System: Accompanied by a Key and Cubical Blocks

Roswell Chamberlain Smith - 1841 - 324 σελίδες
...to the same denomination, and reduce the second tern to the lowest denomination mentioned in it. 3. Divide the product of the second and third terms by the first term ; the quotient will be the answer to the question, in the same denomination with the second term,...

Practical and Mental Arithmetic: On a New Plan in which Mental Arithmetic is ...

Roswell Chamberlain Smith - 1841 - 306 σελίδες
...to the same denomination, and reduce the aecond term to the lowest denommation mentioned in it. 3. Divide the product of the second and third terms by the first terra; tha quotient will he the answer to the qnestion, in the same denomination with the second term,...

A Practical Treatise on Arithmetic: Wherein Every Principle Taught is ...

George Leonard - 1843 - 356 σελίδες
...of the other two numbers the second term, and the smaller the first term, but if I IT answer must ie smaller than the third term, make the smaller of the...product of the second and third terms by the first. • Algebraic proportion can also be employed in solving many of the examples in Percentage, Commission,...

Arithmetic on the Productive System: Accompanied by a Key and Cubical Blocks

Roswell Chamberlain Smith - 1843 - 320 σελίδες
...third terms may be of the same name. and the second term of the same name with the answer, or thmg 3. Divide the product of the second and third terms by the first term; the quotient mil be the answer to the question, in the same denomination with the second term,...

The Elements of Arithmetic ... in which Decimal and Integral Arithmetic are ...

Pliny Earle Chase - 1844 - 164 σελίδες
...less the first term. If less, make the less number the second term, and the greater the first term. Divide the product of the second and third terms, by the first term, and you will obtain the fourth term, which will be the Answer. 1. If 11 yards of flannel are...

The University Arithmetic: Embracing the Science of Numbers, and Their ...

Charles Davies - 1846 - 370 σελίδες
...first term ? How many times will the fourth term be greater or less than the third 1 When we come to divide the product of the second and third terms by the first, it is found the £10 does not contain 25. We then reduce to the next lower denomination, and divide...




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