| Thomas Perronet Thompson - 1833 - 168 σελίδες
...demonstrated. PROPOSITION XLVIII. THEOREM. — If the square described on one of the sides of a triangle, be equal to the sum of the squares described on the other two sides of it; the angle made by those two sides is a right angle. Let ABC be a triangle, which is such that... | |
| Adrien Marie Legendre - 1838 - 372 σελίδες
...PROPOSITION XI. THEOREM. The square described on the hypothenuse of a right angled triangle is equivalent to the sum of the squares described on the other two sides. • Let the triangle ABC be right angled at A. Having described squares on the three sides, let fall... | |
| Charles Davies - 1840 - 262 σελίδες
...90 degrees; This is evident, since A + B+C= 180 degrees, and 4=90 degrees. 10. In every right angled triangle, the square described on the hypothenuse, is equal to the sum of the squares described on the other two sides. Thus, if ABC be a right angled triangle, right angled at... | |
| Scotland free church, gen. assembly - 1847 - 554 σελίδες
...it makes the alternate angles equal. 2. If the square described on one of the sides of a triangle be equal to the sum of the squares described on the other two sides, these sides contain a right angle. 3. Divide a given line into two parts, so that the rectangle contained... | |
| Nicholas Tillinghast - 1844 - 110 σελίδες
...PROP. VII. THEOREM. The square described on the hypotenuse of a right-angled triangle is equivalent to the sum of the squares described on the other two sides. Let the triangle be Fig. 64. KDI, right angled at I. Describe squares on KD, KI, DI ; then we have... | |
| James Bates Thomson - 1844 - 268 σελίδες
...BC^AB'-f-AC". Therefore, The square described on the hypolhcnuse of a right-angled triangle, is equivalent to the sum of the squares described on the other two sides. Cor. 1. Hence, by transposition, the square of one of the sides of a right-angled triangle is equivalent... | |
| James Bates Thomson - 1846 - 354 σελίδες
...principle in geometry, that the square described on the hypothenuse of a right-angled triangle, is equal to the sum of the squares described on the other two sides. (Leg. IV. 11. Euc. I. 47.) Thus if the base of the triangle ABC is 4 feet, and the perpendicular 3... | |
| James Bates Thomson - 1847 - 426 σελίδες
...10342656. 30. 34967ft-. 371 578. The square described on the hypothenuse of a rightangled triangle, is equal to the sum of the squares described on the other two sides. (Thomson's Legendre, B. IV. 11, Euc. I. 47.) The truth of this principle may be seen from the following... | |
| James Bates Thomson - 1847 - 434 σελίδες
...contains 25 sq. ft. Hence, the square described on the hypothenuse of any right-angled triangle^ is equal to the sum of the squares described on the other two sides. OBS. Since the square of the hypothenuse BC, is 25, it follows that the , or 5, must be the hypothenuse... | |
| James Bates Thomson - 1848 - 434 σελίδες
...contains 25 sq. ft. Hence, the syitffre described on Hie hypothenuse of any right-angled triangle, is equal to the sum of the squares described on the other two sides. OBS. Since the square of the hypothenuse BC, is 25, it follows that the ^/ 25, or 5, must be the hypothenuse... | |
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