A Common School ArithmeticCowperthwait & Company, 1871 - 336 σελίδες |
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Σελίδα 21
... ? 27. A merchant bought at one time 513 barrels of flour ; at another , 763 barrels ; and at another , 1347 barrels . How many barrels did he buy in all ? Ans . 2623 . 28. A gardener took from one tree 348 pears ;. ADDITION . 17 21.
... ? 27. A merchant bought at one time 513 barrels of flour ; at another , 763 barrels ; and at another , 1347 barrels . How many barrels did he buy in all ? Ans . 2623 . 28. A gardener took from one tree 348 pears ;. ADDITION . 17 21.
Σελίδα 22
... bought a house for 6236 dollars ; I paid 869 dollars for repairs , and 300 dollars for painting it . For what price must it be sold to gain 325 dollars ? Ans . 7730 dollars . 35. The sailing distance from New Orleans to Charleston is ...
... bought a house for 6236 dollars ; I paid 869 dollars for repairs , and 300 dollars for painting it . For what price must it be sold to gain 325 dollars ? Ans . 7730 dollars . 35. The sailing distance from New Orleans to Charleston is ...
Σελίδα 26
... bought a plantation for 14630 dollars , and sold it for 15750 dollars . How many dollars did he gain by the operation ? Ans . 1120 . CASE II . When the Units of one or more Orders of the Subtrahend Ex- ceed those of the Same Orders of ...
... bought a plantation for 14630 dollars , and sold it for 15750 dollars . How many dollars did he gain by the operation ? Ans . 1120 . CASE II . When the Units of one or more Orders of the Subtrahend Ex- ceed those of the Same Orders of ...
Σελίδα 27
... bought goods for 9363 dollars , and sold them for 10382 dollars . How much did I gain by the transaction ? Ans . 1019 dollars . 60. Rule for Subtraction.— Write the subtrahend under the minuend , so that figures of the same order shall ...
... bought goods for 9363 dollars , and sold them for 10382 dollars . How much did I gain by the transaction ? Ans . 1019 dollars . 60. Rule for Subtraction.— Write the subtrahend under the minuend , so that figures of the same order shall ...
Σελίδα 29
... bought 63100 bushels of corn , and sold 17734 bushels . How many bushels had he left ? 34. I bought a piece of property for 95565 dollars , and sold it for 100000 dollars . What was the gain ? Ans . 4435 dollars . 35. In a certain ...
... bought 63100 bushels of corn , and sold 17734 bushels . How many bushels had he left ? 34. I bought a piece of property for 95565 dollars , and sold it for 100000 dollars . What was the gain ? Ans . 4435 dollars . 35. In a certain ...
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60 days acres amount angle apples arithmetical series bill bought bushels cask cents ciphers common fraction compound numbers contained cost cube root cubic contents cubic feet cubic foot decimal point denominator denoted diameter difference Divide dividend division dollars equal exact divisor expressed feet long figures foot gain gallons given number greatest common divisor Hence hundred hundredths improper fraction integer interest least common multiple length longitude measures meters miles mills minuend mixed number months Multiply ounces paid payable payment pennyweights pints pounds prime factors principal Principles.-1 PROBLEMS profit proportion quarts quotient ratio Reduce remainder result Rule for Finding SECTION selling similar numbers sold SOLUTION SOLUTION.-The square miles square rods square root subtract subtrahend tens tenths term of credit TEST QUESTIONS thick third thousands thousandths tons triangle worth write WRITTEN EXERCISES yards
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Σελίδα 134 - Square Measure 144 square inches (sq. in.) = 1 square foot (sq. ft.) 9 square feet = 1 square yard (sq. yd.) 30| square yards = 1 square rod (sq. rd.) 160 square rods = 1 acre (A.) 640 acres = 1 square mile (sq. mi.) Cubic Measure 1728 cubic inches (cu.
Σελίδα 135 - Cubic Measure 1728 cubic inches (cu. in.) =1 cubic foot (cu. ft.) 27 cubic feet = 1 cubic yard (cu. yd.) 128 cubic feet = 1 cord (cd...
Σελίδα 132 - Measure 12 inches (in.) = 1 foot (ft.) 3 feet = 1 yard (yd.) 5$ yards or 16$ feet = 1 rod (rd.) 320 rods or 5280 feet = 1 mile (mi.) Square Measure 144 square inches (sq.
Σελίδα 90 - Reduce the fractions to a common denominator and divide the numerator of the dividend by the numerator of the divisor.
Σελίδα 46 - Rule. — I. Draw curved lines at both sides of the dividend, and place the divisor at the left. II. Divide the number expressed by the fewest terms at the left that will contain the divisor, and place the quotient at the right. III. Multiply the divisor by this quotient, write the product under the partial dividend, subtract, and to the remainder annex the next term of the dividend. IV. Divide as before, and thus continue until all the terms of the dividend have been used. V. If any partial dividend...
Σελίδα 202 - RULE. Find the amount of the principal to the time when the payment, or the sum of the payments, equals or exceeds the interest due.
Σελίδα 59 - A multiple of a number contains all the prime factors of that number ; and the common multiple of two or more numbers contains all the prime factors of each of the numbers.
Σελίδα 205 - The true present worth of a debt payable at a future time without interest, is such a sum as, being put at legal interest, will amount to the debt when it becomes due.
Σελίδα 73 - Multiplying or dividing both terms of a fraction by the same number does not change its value.
Σελίδα 59 - The Least Common Multiple of two or more numbers is the least number that...