 | Charles Davies - 1833 - 284 σελίδες
...&c. for the other terms. But 2x2=23,2x2x2=23, and 2x2x2x2=2*. Therefore, any term of a progression is equal to the first term multiplied by the ratio raised to a power" 1 less than the number of the term. CASE I. § 230. Having given the first term, the common ratio,... | |
 | Charles Davies - 1835 - 378 σελίδες
...find the values of all those which precede it. That is, the last term of a geometrical progression is equal to the first term multiplied ' by the ratio raised to a power whose exponent is one less than the number of terms. For example, the 8lh term of the progression 2... | |
 | Charles Davies - 1838 - 292 σελίδες
...the other terms. But2x2 = 22, 2x2 x 2 = 23, and 2x2x2x2=2*. Therefore, any term of the progression is equal to the • first term multiplied by the ratio raised to a power 1 less ' than the number of the term. Q. In every Geometrical Progression, how many things are considered?... | |
 | 1838 - 372 σελίδες
...obliged to find all the terms which precede it. That is, the last term of a geometrical progression is equal to the first term multiplied by the ratio raised to a power whose exponent is one less than the number of terms. 1. Find the 5th term of the progression 2 : 4... | |
 | Calvin Tracy - 1840 - 316 σελίδες
...3, 3 is evidently to be taken as multiplier, or factor, eleven times ; that is, any term of a series is equal to the first term multiplied by the ratio raised to a power one less than the number of terms. Thus, 2 x 3 x 3 x 3x3x3x3x3x3x3x3x3" = 3x2= 354294, Ans-. or twelfth... | |
 | Charles DAVIES (LL.D.) - 1843 - 348 σελίδες
...&c. for the other terms. But 2x2=22, 2x2x2=23, and 2x2x2x2=2*. Therefore, any term of the progression is equal to the first term multiplied by the ratio raised to a power 1 less than the number of the term. Q. In every Geometrical Progression, how many things are considered... | |
 | William Scott - 1844 - 568 σελίδες
...1. Whence the exponent of q in any term is indicated by the number of preceding terms, and any term whatever is equal to the first term multiplied by the ratio raised to a power marked by the number of the terms which precede the term proposed. The formula l=aq~~l 1 is called... | |
 | Charles Davies - 1844 - 356 σελίδες
...&c. for the other terms. But2x2=22, 2x2x2=23, and 2x2x2x2=24. Therefore, any term of the progression is equal to the first term multiplied by the ratio raised to a power 1 less than the number of the term. Q. In every Geometrical Progression, how many things are considered... | |
 | Charles Davies - 1845 - 382 σελίδες
...being obliged to find all the terms which precede it. That is, Any term of a geometrical progression is equal to the first term multiplied by the ratio raised to a power whose exponent denotes the number of preceding terms. EXAMPLES. 1. Find the 5th term of the progression... | |
 | Charles Davies - 1846 - 378 σελίδες
...x 2 = 2*, 2 x 2 x 2 = 23, and 2 x 2 x 2 x 2 = 2". Therefore, any term of the progression is ecyjal to the first term multiplied by the ratio raised to a power 1 less than the number of the term. CASE I. Having given the first term, the common ratio, and the... | |
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Therefore, any term of the progression is equal to the first term multiplied by the ratio raised to a power 1 less than the number of the term. 
