15. Is there any common length of side for which the area of a regular dodecagon is twice that of a regular hexagon? Three times? Four times? Prove your answer. 16. Solve a problem similar to that of Ex. 15 if the side of the dodecagon is twice that of the hexagon. 17. The nineteen small circles in the accompanying figure are of the same size. The centers of the twelve outer circles lie on a circle with center at O, as do the six circles between these and the innermost one. The centers of these small circles divide the large circles on which they lie into equal arcs. = If is the radius of the small circles, then OB 2 r, BD 2 r, and DG = 1 r. (a) Find AB and CD in terms of r. (b) Find DE. (c) What part of the circle OG is contained within the nineteen small circles? (d) If the radius of the large circle is 36 inches, find the radii of the small circles so that they shall occupy half its area. (e) If the radius of the large circle is r inches, find the radii of the small circles so they shall occupy one half the area of the large circle. (f) Under (d) how far apart will the outer twelve centers be? The inner six? (g) Under (e) how far apart will the outer twelve centers be? The inner six? In Exs. (f) and (g) it is understood that the distances are measured along straight lines. 18. In the figure ABC is an equilateral triangle. A, B, C are the centers of the arcs BC, CA, and AB. Semicircles are constructed on the diameters AB, BC, CA. Let AB = a. (See Ex. 11, p. 93.) Circles are constructed tangent to the various arcs as in the figure. (a) Find the radius r'. SUGGESTION. Find in order BM, MN, BN, HO", BO". (b) Find the radius r'. SUGGESTION. BN is known from the solution of (a). But BN BO'+r' and BO' = 2 KO'. Hence KO' = BN - r'. = 2 a KB = √3. B0' = } √3 (BN – r') and HO' r'. HK2 2 HO* =HK* +KO = (@ - KB) +KO. 2 Substituting for HO', KB and KO' in (1) we may solve for r'. (c) Find the radius r. (1) SUGGESTION. Use A BLO and HLO and proceed as under (b). (d) Using the radii thus found, show how to construct the figure. (e) What fraction of the whole area is contained in the circles? 19. ABCD is a parallelogram with fixed base and altitude. the locus of the intersection points of the bisectors of its interior base angles. 20. Find the locus of a point P such that the sum of the squares of its distances from two fixed points is constant. P Find C B SUGGESTION. By § 440, AP2 + PB2 = 2 AC2 + 2 CP2. Solve for CP. 21. Find the locus of a point P such that the ratio of its distances from two fixed points is equal to the constant ratio m: n. Show by the converses of §§ 250, 253 that PP' bisects ▲ APB and BPK, and hence P'P and PP form a right angle. PP" bisects P from which the segments AB and CD subtend the same angle. CDP have a common altitude, and hence their Hence A B C From these equations show that AP: PD is a constant ratio. 24. ABC is a fixed isosceles triangle. With center C and radius less than AC, construct a circle, and from A and B draw tangents to it meeting in P. Find the locus of P. SUGGESTIONS. (a) Show that part of the locus is the straight line PP'. (b) Show that 21=22 and hence that ZAP"B is constant. P B 268 445. Definitions. MAXIMA AND MINIMA. Of all geometric figures fulfilling one is certain conditions it often happens that some greater than any other, in which case it is called a maximum. Or it may happen that some one is less than any other, in which case it is called a minimum. E.g. of all chords of a circle the diameter is the maximum, and of all segments drawn to a line from a point outside it the perpendicular is the minimum. In the following theorems and exercises the terms maximum and minimum are used as above defined. However, a geometric figure is often thought of as continuously varying in size, in which case it is said to have a maximum at any position where it may cease to increase and begin to decrease, whether or not this is the greatest of all its possible values. Likewise it is said to have a minimum at any position where it may cease to decrease and begin to increase. A B C E E.g. if in the figure a perpendicular from a point in the curve to the straight line be moved continuously parallel to itself, the length of this perpendicular will have maxima at A, C, and E, and minima at B, D, and F. Certain simple cases of maxima and minima problems. have already been given. in the following exercises. 446. Some of these will be recalled EXERCISES. 1. If from a point within a circle, not the center, a line-segment be drawn to meet the circle, show that this segment is a maximum when it passes through the center and a minimum when, if produced in the opposite direction, it would pass through the center. 2. Show that of all chords through a given point within a circle, not the center, the diameter is a maximum and the chord perpendicular to the diameter is a minimum. 3. Of all line-segments which may be drawn from a point outside a circle to meet the circle, that is a maximum which meets it after passing through the center, and that is a minimum which, if produced, would pass through the center. 4. Show that if a square and a rectangle have equal perimeters, the square has the greater area. SUGGESTION. If s is the side of the square and a and b are the altitude and base of the rectangle respectively, then 2 b+ 2 a = 4s or (b − a)2. That is, s2 is greater than ab by 4 5. Use the preceding exercise to find that point in a given linesegment which divides it into two such parts that their product is a maximum. 6. Find the point in a given line-segment such that the sum of the squares on the two parts into which it divides the segment is a minimum. SUGGESTION. If a and b are the two parts and k the length of the segment, then a + b = k and a2 + 2 ab + b2 = k2, or, a2 + b2 = k2 - 2 ab. Hence, a2 +b2 is least when 2 ab is greatest. Now apply Ex. 5. 7. In the preceding exercise show that a2 + b2 increases as b grows smaller, that is, as the point of division approaches one end. When is this sum a maximum? 8. Two points A and B, on opposite sides of a straight stream of uniform width, are to be connected by a road and a bridge crossing the stream at right angles. Find by construction the location of the bridge so as to make the total path from A to B a minimum. |