Plane Geometry: With Problems and ApplicationsAllyn and Bacon, 1910 - 280 σελίδες |
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Σελίδα 19
... middle point of the base bisects the vertex angle and is perpendicular to the base . 5. What parts of a triangle have been found sufficient to determine it ? In each case how many parts are needed ? 43. The three tests for congruence of ...
... middle point of the base bisects the vertex angle and is perpendicular to the base . 5. What parts of a triangle have been found sufficient to determine it ? In each case how many parts are needed ? 43. The three tests for congruence of ...
Σελίδα 22
... point D shall not lie within the angle BAC ? In that case does the ray AD ... point in it . 5. Construct a perpendicular to a segment at one end of it without ... middle point is called the perpendicular bisector of the segment . 51 ...
... point D shall not lie within the angle BAC ? In that case does the ray AD ... point in it . 5. Construct a perpendicular to a segment at one end of it without ... middle point is called the perpendicular bisector of the segment . 51 ...
Σελίδα 27
... point . For if they have two points in common , then by Ax . II they are the same line . 63. All straight angles are equal . § 20 , Ex . 1 . 64. All right angles are equal . See Ax . VI . 65. Every line - segment has one and only one middle ...
... point . For if they have two points in common , then by Ax . II they are the same line . 63. All straight angles are equal . § 20 , Ex . 1 . 64. All right angles are equal . See Ax . VI . 65. Every line - segment has one and only one middle ...
Σελίδα 32
... middle point of BC . Find E by the construction for bisecting a line - segment ( § 51 ) . Draw AE and prolong it , making EF = AE , and draw BF . In the two △ ACE and FBE , we have by construction CE EB and AE = EF . Also Z CEA = BEF ...
... middle point of BC . Find E by the construction for bisecting a line - segment ( § 51 ) . Draw AE and prolong it , making EF = AE , and draw BF . In the two △ ACE and FBE , we have by construction CE EB and AE = EF . Also Z CEA = BEF ...
Σελίδα 33
... middle point of AB . Draw CH and prolong it to K , making CH = HK . Let the student draw the figure for the second part of the proof and give it in full . Hereafter more and more of the details of the proofs will be left for the student ...
... middle point of AB . Draw CH and prolong it to K , making CH = HK . Let the student draw the figure for the second part of the proof and give it in full . Hereafter more and more of the details of the proofs will be left for the student ...
Άλλες εκδόσεις - Προβολή όλων
Plane Geometry With Problems and Applications H. E. Slaught Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2015 |
Συχνά εμφανιζόμενοι όροι και φράσεις
ABCD accompanying design altitude apothem arcs area bounded axes of symmetry axioms base and altitude bisectors bisects central angle chord circumference congruent corresponding sides definite diagonal diameter divided Draw drawn equal angles equal circles equilateral triangle EXERCISES exterior angle feet Find the area Find the locus Find the radius fixed point geometric Give the proof given circle given point given triangle greater Hence hypotenuse inscribed intersect isosceles triangle length line-segment measure meet middle points number of sides Outline of Proof parallel lines parallelogram perimeter perpendicular proof in full Prove quadrilateral radii ratio rectangle regular dodecagon regular hexagon regular octagon regular polygon regular triangle respectively rhombus right angle right triangle secant semicircle Show shown straight angle straight line strip subtend SUGGESTION tangent THEOREM tile trapezoid triangle ABC unit vertex vertices width
Δημοφιλή αποσπάσματα
Σελίδα 215 - If two triangles have two sides of the one equal to two sides of the other...
Σελίδα 35 - An exterior angle of a triangle is equal to the sum of the two opposite interior angles.
Σελίδα 22 - Any side of a triangle is less than the sum of the other two sides...
Σελίδα 113 - Sines that the bisector of an angle of a triangle divides the opposite side into parts proportional to the adjacent sides.
Σελίδα 273 - This textbook may be borrowed for two weeks, with the privilege of renewing it once. A fine of five cents a day is incurred by failure to return a book on the date when it is due. The Education Library is open from 9 to 5 daily except Saturday when it closes at 12.30.
Σελίδα 52 - The straight line joining the middle points of two sides of a triangle is parallel to the third side and equal to half of it 46 INTERCEPTS BY PARALLEL LINES.
Σελίδα 174 - The areas of two regular polygons of the same number of sides are to each other as the squares of their radii, or as the squares of their apothems.
Σελίδα 153 - The formula states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the base and altitude.
Σελίδα 219 - Find the locus of a point such that the difference of the squares of its distances from two fixed points is a constant.
Σελίδα 202 - The area of a rectangle is equal to the product of its base and altitude.