Conversations on Arithmetic, with Demonstrations to Each RuleLincoln & Edmands, 1823 - 156 σελίδες |
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Σελίδα 32
... Hence it follows , that in order to simplify a fraction we must divide its two terms by one of the numbers 2 , 3 , 4 , & c .; but by this mode of proceeding it will often be nec- essary to perform a great number of operations . by 3 ...
... Hence it follows , that in order to simplify a fraction we must divide its two terms by one of the numbers 2 , 3 , 4 , & c .; but by this mode of proceeding it will often be nec- essary to perform a great number of operations . by 3 ...
Σελίδα 36
... hence it follows that are equivalent to one and two fourths expressed 12 equal to 11 , which added to 15 make 161 , which is 3 of 22 . From the preceding examples it will appear evident that contains unity , or a whole one , and 2 over ...
... hence it follows that are equivalent to one and two fourths expressed 12 equal to 11 , which added to 15 make 161 , which is 3 of 22 . From the preceding examples it will appear evident that contains unity , or a whole one , and 2 over ...
Σελίδα 37
... Hence the following rule for multiplying one fraction by another . Multiply the numerators together for a numerator , and the de- nominators together for a denominator . Ans . 1 . Multiply by . Multiply by T Ans .. 72 Multiply 25 by 18 ...
... Hence the following rule for multiplying one fraction by another . Multiply the numerators together for a numerator , and the de- nominators together for a denominator . Ans . 1 . Multiply by . Multiply by T Ans .. 72 Multiply 25 by 18 ...
Σελίδα 38
... Hence it follows that to divide by , the quotient must be double the dividend . From what has here been said , and from the relation which division has to multipli- cation , it appears that the division of fractions must be the reverse ...
... Hence it follows that to divide by , the quotient must be double the dividend . From what has here been said , and from the relation which division has to multipli- cation , it appears that the division of fractions must be the reverse ...
Σελίδα 40
... Hence we have the following rule . แ Any number of fractions are reduced to a common denomina- tor , by multiplying the two terms of each by , the product of the denominators of all the others . " Or by multiplying each numer- ator by ...
... Hence we have the following rule . แ Any number of fractions are reduced to a common denomina- tor , by multiplying the two terms of each by , the product of the denominators of all the others . " Or by multiplying each numer- ator by ...
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Conversations on Arithmetic, with Demonstrations to Each Rule Leonard Pierce Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2016 |
Conversations on Arithmetic, with Demonstrations to Each Rule Leonard Pierce Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2016 |
Συχνά εμφανιζόμενοι όροι και φράσεις
addition alligation annexed answer arithmetic blocks borrowed called carats cents and mills cents per bushel ciphers circumference compound interest compound number contained cost cube root currencies to Federal debt decimal fractions diameter difference dimes discount divide dividend division dollars double Duodecimals equal Examples for Practice expressed Federal Money feet find the price following numbers following rule gain gallons give given number grains greatest common divisor Hence higher denomination hundred weight improper fraction inches last quotient figure left hand period lower denomination manner miles minuend mixed number months multiplicand number of tens ounces payment pennyweights perform place of tens pound present worth proceed proportion quantity reduce remainder required to multiply right hand figure share simple number square root subtrahend supposed number tenths tion triple quotient TROY WEIGHT understand units vulgar fractions whole numbers write
Δημοφιλή αποσπάσματα
Σελίδα 153 - EF or his certain attorney, his executors, administrators or assigns, to which payment, well and truly to be made, I bind myself, my heirs, executors and administrators, firmly by these presents ; Sealed with my seal.
Σελίδα 37 - To change a mixed number to an improper fraction, multiply the whole number by the denominator of the fraction and add the numerator.
Σελίδα 118 - RULE.—Multiply each payment by the time at which it is due; then divide the sum of the products by the sum of the payments, and the quotient will be the equated time.* • , EXAMPLES.
Σελίδα 126 - Distinguish the given number into periods of two figures each, by putting a point over the place of units, another 'over the place of hundreds, and so on, which points show the number of figures the root will consist of. 2. Find the greatest square number in the first or left hand period...
Σελίδα 155 - SP his heirs, and assigns, a certain tract and parcel of land, bounded as follows, viz. [Here insert the bounds, together with all the privileges and appurtenances thereunto belonging.'} To have and to hold the same unto the said SP his heirs and assigns, to his and their use and behoof for ever.
Σελίδα 109 - If 248 men, in 5 days, of 11 hours each, can dig a trench 230 yards long, 3 wide, and 2 deep, in how many days, of 9 hours each, will 24 men dig a trench 420 yards long, 5 wide, and 3 deep ? Here the number of days, in which the proposed work can be done, depends on five circumstances, viz.
Σελίδα 127 - Double the figures already found in the root for a new divisor, (or, bring down your last divisor for a new one, doubling the right hand figure of it,) and from these find the next figure in the root, as last directed, and continue the operation in the same manner, till you have brought down all the periods.
Σελίδα 131 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Σελίδα 156 - Lord eighteen hundred and , with lawful interest for the same until paid, then this deed, as also a certain bond [or note, as the case may be] bearing even date with these presents given by me to the said RS conditioned t...
Σελίδα 107 - A and B depart from the same, place and travel the same road ; but A goes 5 days before B, at the rate of 15 miles a day . B follows at the rate of 20 miles a . day } what distance must he travel to overtake A ? Ans. 300 miles RULE OF THREE INVERSE.