Elements of GeometryGinn, Heath & Company, 1884 |
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Σελίδα 23
... and the same straight line . 6. Show that the two straight lines which bisect the two pairs of vertical angles are perpendicular to each other . PROPOSITION IX . THEOREM . 61. At a point in PERPENDICULAR AND OBLIQUE LINES . 23.
... and the same straight line . 6. Show that the two straight lines which bisect the two pairs of vertical angles are perpendicular to each other . PROPOSITION IX . THEOREM . 61. At a point in PERPENDICULAR AND OBLIQUE LINES . 23.
Σελίδα 47
... bisect the ZACB . In the ACE and BCE , AC = BC , CE CE , ZACE ZBCE ; = = ..AACE ABCE , ( two are equal when two sides and the included respectively to two sides and the included Hyp . Iden . Cons . § 106 of the one are equal of the ...
... bisect the ZACB . In the ACE and BCE , AC = BC , CE CE , ZACE ZBCE ; = = ..AACE ABCE , ( two are equal when two sides and the included respectively to two sides and the included Hyp . Iden . Cons . § 106 of the one are equal of the ...
Σελίδα 48
... bisects the base . C B E Let the line C E bisect the ACB of the isosceles ДАСВ . We are to prove I. A ACE = · ABCE ; II . line CEL to AB ; III . A E = BE . I. In the ACE and BCE , CE CE , AC = = BC , Hyp . Iden . Cons . = ABCE , § 106 ...
... bisects the base . C B E Let the line C E bisect the ACB of the isosceles ДАСВ . We are to prove I. A ACE = · ABCE ; II . line CEL to AB ; III . A E = BE . I. In the ACE and BCE , CE CE , AC = = BC , Hyp . Iden . Cons . = ABCE , § 106 ...
Σελίδα 50
... bisect EBC . In the AEBF and CBF Draw E F. EB = BC , = BF BF , LEBF - LCBF , .. the AEBF and CBF are equal , Hyp . Iden . Cons . § 106 ( having two sides and the included of one equal respectively to two sides Now and the included ..EF ...
... bisect EBC . In the AEBF and CBF Draw E F. EB = BC , = BF BF , LEBF - LCBF , .. the AEBF and CBF are equal , Hyp . Iden . Cons . § 106 ( having two sides and the included of one equal respectively to two sides Now and the included ..EF ...
Σελίδα 54
... bisects the L B. Draw the Is OK , O P , and O H. · In the rt . AOC K and OCP , OC = OC , - LOCK LOCP , ..A OCK = △ OCP , Iden . Cons . $ 110 ( having the hypotenuse and an acute of the one equal respectively to the hypotenuse and an ...
... bisects the L B. Draw the Is OK , O P , and O H. · In the rt . AOC K and OCP , OC = OC , - LOCK LOCP , ..A OCK = △ OCP , Iden . Cons . $ 110 ( having the hypotenuse and an acute of the one equal respectively to the hypotenuse and an ...
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A B C AABC ABCD adjacent angles alt.-int altitude apothem arc A B bisect centre circumference circumscribed coincide COROLLARY describe an arc diagonals diameter divided Draw equal arcs equal distances equal respectively equiangular polygon equilateral equilateral polygon equivalent exterior angles figure given line given point given polygon greater homologous sides hypotenuse isosceles triangle Let A B Let ABC limit line A B Mailing price measured by arc middle point number of sides parallelogram perimeter perpendicular PHILLIPS EXETER ACADEMY plane PROBLEM prove Q. E. D. PROPOSITION quadrilateral radii radius equal ratio rect rectangles regular inscribed regular polygon required to construct rhombus right angles right triangle SCHOLIUM segment sides of equal sides of similar similar polygons subtend tangent THEOREM third side triangle ABC vertex vertices Wentworth