Elements of GeometryGinn, Heath & Company, 1884 |
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Σελίδα 37
... ISOSCELES . EQUILATERAL . 83. DEF . A Sealene triangle is one of which no two sides are equal . 84. DEF . An Isosceles triangle is one of which two sides are equal . 85. DEF . An Equilateral triangle is one of which the three sides are ...
... ISOSCELES . EQUILATERAL . 83. DEF . A Sealene triangle is one of which no two sides are equal . 84. DEF . An Isosceles triangle is one of which two sides are equal . 85. DEF . An Equilateral triangle is one of which the three sides are ...
Σελίδα 46
... acute angle of the one are equal respectively to an homologous side and acute angle of the other . of the one are equal of the other ) . Q. E. D. PROPOSITION XXVIII . THEOREM . 112. In an isosceles triangle 46 BOOK I. GEOMETRY .
... acute angle of the one are equal respectively to an homologous side and acute angle of the other . of the one are equal of the other ) . Q. E. D. PROPOSITION XXVIII . THEOREM . 112. In an isosceles triangle 46 BOOK I. GEOMETRY .
Σελίδα 47
George Albert Wentworth. PROPOSITION XXVIII . THEOREM . 112. In an isosceles triangle the angles opposite the equal sides are equal . A E B Let ABC be an isosceles triangle , having the sides AC and CB equal . We are to prove ZA ZB ...
George Albert Wentworth. PROPOSITION XXVIII . THEOREM . 112. In an isosceles triangle the angles opposite the equal sides are equal . A E B Let ABC be an isosceles triangle , having the sides AC and CB equal . We are to prove ZA ZB ...
Σελίδα 48
... isosceles triangle divides the triangle into two equal triangles , is perpendicular to the base , and bisects the base . C B E Let the line C E bisect the ACB of the isosceles ДАСВ . We are to prove I. A ACE = · ABCE ; II . line CEL to ...
... isosceles triangle divides the triangle into two equal triangles , is perpendicular to the base , and bisects the base . C B E Let the line C E bisect the ACB of the isosceles ДАСВ . We are to prove I. A ACE = · ABCE ; II . line CEL to ...
Σελίδα 49
... isosceles . A B Ꭰ In the triangle ABC , let the B = L C. We are to prove = AB AC . Draw A D1 to BC . In the rt . A A D B and A D C , AD = AD , LB = LC , .. rt . △ A D B = rt . △ A D C , Iden . § 111 ( having a side and an acute △ of ...
... isosceles . A B Ꭰ In the triangle ABC , let the B = L C. We are to prove = AB AC . Draw A D1 to BC . In the rt . A A D B and A D C , AD = AD , LB = LC , .. rt . △ A D B = rt . △ A D C , Iden . § 111 ( having a side and an acute △ of ...
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A B C AABC ABCD adjacent angles alt.-int altitude apothem arc A B bisect centre circumference circumscribed coincide COROLLARY describe an arc diagonals diameter divided Draw equal arcs equal distances equal respectively equiangular polygon equilateral equilateral polygon equivalent exterior angles figure given line given point given polygon greater homologous sides hypotenuse isosceles triangle Let A B Let ABC limit line A B Mailing price measured by arc middle point number of sides parallelogram perimeter perpendicular PHILLIPS EXETER ACADEMY plane PROBLEM prove Q. E. D. PROPOSITION quadrilateral radii radius equal ratio rect rectangles regular inscribed regular polygon required to construct rhombus right angles right triangle SCHOLIUM segment sides of equal sides of similar similar polygons subtend tangent THEOREM third side triangle ABC vertex vertices Wentworth