Elements of GeometryGinn, Heath & Company, 1884 |
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Αποτελέσματα 1 - 5 από τα 18.
Σελίδα 73
... subtends two arcs whose sum is the cir- cumference . Thus the chord AB , ( Fig . 3 ) , subtends the arc AMB and the arc AD B. Whenever a chord and its arc are spoken of , the less arc is meant unless it be otherwise stated . 167. DEF ...
... subtends two arcs whose sum is the cir- cumference . Thus the chord AB , ( Fig . 3 ) , subtends the arc AMB and the arc AD B. Whenever a chord and its arc are spoken of , the less arc is meant unless it be otherwise stated . 167. DEF ...
Σελίδα 78
... subtend equal angles at the centre . R S A B Α ' R P S BI P In the equal circles ABP and A'B ' P ' let . arc RS = arc R ' S ' . We are to prove LROS = Z R ' O'S ' . Apply ABP to O A'B ' P ' , so that the radius O R shall fall upon O ' R ...
... subtend equal angles at the centre . R S A B Α ' R P S BI P In the equal circles ABP and A'B ' P ' let . arc RS = arc R ' S ' . We are to prove LROS = Z R ' O'S ' . Apply ABP to O A'B ' P ' , so that the radius O R shall fall upon O ' R ...
Σελίδα 79
... subtended by equal chords . Ꭱ . B A R S ཁོ BI P P In the equal circles ABP and A'B ' P ' let arc RS = arc R ' S ' . We ... subtend equal at the centre ) . ( two sides and the included of the one being equal respectively to two sides ..A ...
... subtended by equal chords . Ꭱ . B A R S ཁོ BI P P In the equal circles ABP and A'B ' P ' let arc RS = arc R ' S ' . We ... subtend equal at the centre ) . ( two sides and the included of the one being equal respectively to two sides ..A ...
Σελίδα 80
... subtend equal arcs . R R A B A BI P PI In the equal circles ABP and A'B ' P ' , let chord RS = chord R'S ' . We are to prove = arc Ꭱ Ꮪ arc R ' S ' . Draw the radii O R , O S , O ' R ' , and O'S ' . In the ROS and R ' O'S ' RS = R'S ...
... subtend equal arcs . R R A B A BI P PI In the equal circles ABP and A'B ' P ' , let chord RS = chord R'S ' . We are to prove = arc Ꭱ Ꮪ arc R ' S ' . Draw the radii O R , O S , O ' R ' , and O'S ' . In the ROS and R ' O'S ' RS = R'S ...
Σελίδα 81
... subtended by it . B M S Let A B be the chord , and let the radius CS be per- pendicular to AB at the point M. We are to prove A M = BM , and arc A Sarc B S. Draw CA and C B. CA 1 C B , ( being radii of the same O ) ; ..AAC B is ...
... subtended by it . B M S Let A B be the chord , and let the radius CS be per- pendicular to AB at the point M. We are to prove A M = BM , and arc A Sarc B S. Draw CA and C B. CA 1 C B , ( being radii of the same O ) ; ..AAC B is ...
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Συχνά εμφανιζόμενοι όροι και φράσεις
A B C AABC ABCD adjacent angles alt.-int altitude apothem arc A B bisect centre circumference circumscribed coincide COROLLARY describe an arc diagonals diameter divided Draw equal arcs equal distances equal respectively equiangular polygon equilateral equilateral polygon equivalent exterior angles figure given line given point given polygon greater homologous sides hypotenuse isosceles triangle Let A B Let ABC limit line A B Mailing price measured by arc middle point number of sides parallelogram perimeter perpendicular PHILLIPS EXETER ACADEMY plane PROBLEM prove Q. E. D. PROPOSITION quadrilateral radii radius equal ratio rect rectangles regular inscribed regular polygon required to construct rhombus right angles right triangle SCHOLIUM segment sides of equal sides of similar similar polygons subtend tangent THEOREM third side triangle ABC vertex vertices Wentworth