The Theory and Practice of Gauging, Demonstrated in a Short and Easy Method ...H. Woodfall, 1740 - 283 σελίδες |
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Σελίδα 12
... last put in the Quotient , would give an Index more diftant from Unity , than the Index of the lowest Place required in the Quotient , I fay all fuch may be omitted by only confidering the Increase to be brought from them to the first ...
... last put in the Quotient , would give an Index more diftant from Unity , than the Index of the lowest Place required in the Quotient , I fay all fuch may be omitted by only confidering the Increase to be brought from them to the first ...
Σελίδα 35
... the Order of the Numbers on this Line are 2 ( or 200 ) 10 , 9 , 8 , 7 , 6 , 5 , 4 , 3 , 2 , 1 , 9 , 8 , 7 , 6 , 5 , 4 , 3 , and the last Divifion is 2,15042 , by D 2 which Ch . III . which dividing 215 , you have PRACTICE of GAUGING . 35.
... the Order of the Numbers on this Line are 2 ( or 200 ) 10 , 9 , 8 , 7 , 6 , 5 , 4 , 3 , 2 , 1 , 9 , 8 , 7 , 6 , 5 , 4 , 3 , and the last Divifion is 2,15042 , by D 2 which Ch . III . which dividing 215 , you have PRACTICE of GAUGING . 35.
Σελίδα 52
... last Propo- 2150,42 bxq 2150,42 fition q is against 1 on MD , therefore by Propofition 3 , foregoing , if 2150,42 on A De fet to q on B , then opposite b on A is on B. But we ob- ferved above , that 2150,42 on A , is oppofite 1 on MD ...
... last Propo- 2150,42 bxq 2150,42 fition q is against 1 on MD , therefore by Propofition 3 , foregoing , if 2150,42 on A De fet to q on B , then opposite b on A is on B. But we ob- ferved above , that 2150,42 on A , is oppofite 1 on MD ...
Σελίδα 70
... last Example , the Side of a Pentagon was 50 Inches , therefore because the Number in the fifth Column oppofite Pentagon is 1.720477 , I fet 1 on D to 1.72 on C , then oppofite 5 on D ( for 50 is of the Rule ) is 43.01 on C , and ...
... last Example , the Side of a Pentagon was 50 Inches , therefore because the Number in the fifth Column oppofite Pentagon is 1.720477 , I fet 1 on D to 1.72 on C , then oppofite 5 on D ( for 50 is of the Rule ) is 43.01 on C , and ...
Σελίδα 85
... last Term 1 , viz . anml , then s = DEMONSTRATION . am m + For if s = xn + 1 , when the Number of , - MI Terms is n , that when this is diminished by 1 , ( the G 3 laft laft Term ) or the Number of Terms is n PRACTICE of GAUGING . 85.
... last Term 1 , viz . anml , then s = DEMONSTRATION . am m + For if s = xn + 1 , when the Number of , - MI Terms is n , that when this is diminished by 1 , ( the G 3 laft laft Term ) or the Number of Terms is n PRACTICE of GAUGING . 85.
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The Theory and Practice of Gauging, Demonstrated in a Short and Easy Method ... Robert Shirtcliffe Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2018 |
The Theory and Practice of Gauging, Demonstrated in a Short and Easy Method Robert Shirtcliffe Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2018 |
The Theory and Practice of Gauging, Demonstrated in a Short and Easy Method Robert Shirtcliffe Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2023 |
Συχνά εμφανιζόμενοι όροι και φράσεις
Abfciffa againſt Ale Gall alfo alſo Angle Area Bafe Baſe becauſe betwixt Breadth Bung-Diameter Cafk called Caſk Chap Circle circular Segment Cone Conic Conic Sections Conoid Content Corol correfponding Curve Decimal denote Diam Diſtance divided Divifion Divifor dry Inches Ellipfe equal Example expreffed faid fame fecond fhall fhew fhewn Figure fimilar fince firft firſt fome Fruftum ftand fuch fufficient fuppofe fure Gauging given gives Height hence Hoof Hyperbola Hyperbolic Segment laft laſt Lemma Length Logarithms mean Diameter Meaſure Method multiplied muſt Number oppofite Ordinate orems parabolic parallel perpendicular Plane Points Product Prop Propofition Quotient Radius Reaſon refpectively Root Rule Scholium Section Segment ſhall Side Sliding-Rule Solid Spheroid Spindle Square taken Terms thefe Theorem thereof theſe thofe thoſe thro tranfverfe Axis Triangle Ullage uſe verfed Sine Vertex wet Inches whence whofe Wine Gallons
Δημοφιλή αποσπάσματα
Σελίδα 59 - The circumference of every circle is supposed to be divided into 360 equal parts called degrees, and each degree into 60 equal parts called minutes, and each minute into 60 equal parts called seconds, and these into thirds, fourths, &c.
Σελίδα 7 - In multiplication of decimals, we know that the number of decimal places in the product is equal to the sum of those in both the factors.
Σελίδα 97 - J of the square of their difference, then multiply by the hight, and divide as in the last rule. Having the diameter of a circle given, to find the area. RULE. — Multiply half the diameter by half the circumference, and the product is the area ; or, which is the same thing, multiply the square of the diameter by .7854, and the product is the area.
Σελίδα 282 - Sort is, to multiply the two Weights together, and extract the Square Root of. the Product, which Root will be the true Weight.
Σελίδα 283 - Backs time ufed, and become more and more uneven as they grow older, efpecially fuch as are not every where well and equally fupported ; many of them...
Σελίδα 187 - Sum of thofe next to them, C the Sum of the two next following the laft, and fo on ; then we (hall have the following fables of Areas, for the feveral Numbers of Ordinates prefixt againft them, viz.
Σελίδα 86 - Progreflion from o, is equal to the Product of the laft Term by the Number of Terms, and this divided by the Index (m) plus Unity.
Σελίδα 272 - To half the Sum of the Squares of the Top and Bottom Diams.
Σελίδα 95 - The latter being taken from the former, leaves 3.14.15.9265.5 for the Length of half the Circumference of a Circle whofe Radius is Unity : Therefore the Diameter of any Circle is to its Circutuftrence as I is to 3.1415.9265.5 nearly.
Σελίδα 86 - Numbr infinitely greAt, therefore the firft Term of the above Value of /, muft be infinitely greater than any of the...