Complete Arithmetic, Μέρος 2Ginn, 1909 |
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Σελίδα 28
... will be a little larger balance in the treasury at the end of the year . In the examples in Exercise 17 consider the collector's commission only when told to do so . 32. Tax Table . Assessors usually prepare a table like 28 PERCENTAGE.
... will be a little larger balance in the treasury at the end of the year . In the examples in Exercise 17 consider the collector's commission only when told to do so . 32. Tax Table . Assessors usually prepare a table like 28 PERCENTAGE.
Σελίδα 34
... balance , $ 9350 . What was the cost of the mill ? 31. A bank clerk started work at a salary of $ 900 a year . The second year his salary was raised 20 % , the third year 25 % , and the fourth year 333 % . What was his salary then ? 32 ...
... balance , $ 9350 . What was the cost of the mill ? 31. A bank clerk started work at a salary of $ 900 a year . The second year his salary was raised 20 % , the third year 25 % , and the fourth year 333 % . What was his salary then ? 32 ...
Σελίδα 52
... balance due , interest at 6 % . Time from Aug. 16 to June 25 is 10 mo . 9 da . Time from Nov. 4 to June 25 is 7 mo ... Balance due June 25 , 1914 The Merchants ' Rule is used by bankers and business men on notes running only a few months ...
... balance due , interest at 6 % . Time from Aug. 16 to June 25 is 10 mo . 9 da . Time from Nov. 4 to June 25 is 7 mo ... Balance due June 25 , 1914 The Merchants ' Rule is used by bankers and business men on notes running only a few months ...
Σελίδα 53
George Wentworth, David Eugene Smith. EXERCISE 33 Find the balance due : 1. Note of $ 230 given May 9 , 1910 , bearing interest at 6 % . Payments : July 1 , 1910 , $ 40 ; Sept. 16 , 1910 , $ 75 ; Jan. 2 , 1911 , $ 50 . Settlement Feb. 24 ...
George Wentworth, David Eugene Smith. EXERCISE 33 Find the balance due : 1. Note of $ 230 given May 9 , 1910 , bearing interest at 6 % . Payments : July 1 , 1910 , $ 40 ; Sept. 16 , 1910 , $ 75 ; Jan. 2 , 1911 , $ 50 . Settlement Feb. 24 ...
Σελίδα 75
... balance ? 5. How much pressure will you have to exert on the handles of a pair of shears just 3 in . from the fulcrum ( screw or bolt ) , in order to exert a pressure of 5 lb. at a point 5 in . from the fulcrum ? EXERCISE 46 PROBLEMS ...
... balance ? 5. How much pressure will you have to exert on the handles of a pair of shears just 3 in . from the fulcrum ( screw or bolt ) , in order to exert a pressure of 5 lb. at a point 5 in . from the fulcrum ? EXERCISE 46 PROBLEMS ...
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30 days 60-day note acres altitude Arithmetic assessed B. H. Roberts balance bank base bill bought brokerage butter fat called Casting out Nines cent commission common fraction compound interest cube root cubic foot dealer decimal places deposit diameter divide dividend divisor draft duty equal example exchange EXERCISE Express extract the square face factor figures Find the amount Find the area Find the cost Find the interest Find the rate find the volume gain geometric geometric progression inches indorse July June June 20 list price marked price merchant multiply myriameter paid Payments pounds premium principal PROBLEMS promissory note proportion radius ratio received rectangular remainder repeating decimal selling price Sept sold specific gravity sphere square root subtract surface term units varas weight yard
Δημοφιλή αποσπάσματα
Σελίδα 205 - CUBIC MEASURE 1728 cubic inches (cu. in.) = 1 cubic foot (cu. ft.) 27 cubic feet = 1 cubic yard (cu. yd.) 128 cubic feet = 1 cord (cd...
Σελίδα 79 - Which proves that the square of a number composed of tens and units contains, the square of the tens plus twice the product of the tens by the units, plus the square of the units.
Σελίδα 207 - Time 60 seconds (sec.) = 1 minute (min.) 60 minutes = 1 hour (hr.) 24 hours = 1 day (da.) 7 days = 1 week (wk.) 365 days = 1 common year...
Σελίδα 204 - SQUARE MEASURE 144 square inches (sq. in.) = 1 square foot (sq. ft.) 9 square feet = 1 square yard (sq. yd.) 30| square yards = 1 square rod (sq. rd.) 160 square rods = 1 acre (A.) 640 acres = 1 square mile (sq.
Σελίδα 94 - Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the operation as before, until all the periods are brought down. NOTE.
Σελίδα 84 - In a right triangle the square of the hypotenuse equals the sum of the squares of the other two sides or legs.
Σελίδα 54 - THE UNITED STATES RULE. Find the amount of the principal to the time when the payment, or sum of the payments, equals or exceeds the interest.
Σελίδα 84 - In a right triangle, the side opposite the right angle is called the hypotenuse and is the longest side.
Σελίδα 67 - If 8 men can do a piece of work in 9 days, how long will it take one man to do the same work ? 17.