Complete Arithmetic, Μέρος 2Ginn, 1909 |
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Σελίδα 35
... month amounted to $ 675 . How much did he remit to the owner ? 43. A workman in a factory received $ 1350 the first year . The second year his wages was advanced 10 % , and the third year 10 % . The fourth year it was reduced 10 % . How ...
... month amounted to $ 675 . How much did he remit to the owner ? 43. A workman in a factory received $ 1350 the first year . The second year his wages was advanced 10 % , and the third year 10 % . The fourth year it was reduced 10 % . How ...
Σελίδα 38
... month , which means 360 da . to the year . EXERCISE 21 Given the principal , rate , and time , find the interest : 1. $ 250 , 5 % , 4 mo . 10 da . 2. $ 520 , 6 % , 2 yr . 9 mo . 25 da . 3. $ 760 , 5 % , 4 yr . 6 mo . 15 da . 4. $ 875 ...
... month , which means 360 da . to the year . EXERCISE 21 Given the principal , rate , and time , find the interest : 1. $ 250 , 5 % , 4 mo . 10 da . 2. $ 520 , 6 % , 2 yr . 9 mo . 25 da . 3. $ 760 , 5 % , 4 yr . 6 mo . 15 da . 4. $ 875 ...
Σελίδα 41
... month of the year , and April the fourth , the work is arranged as here shown . We then subtract as with other compound numbers ; 5-16 is impossible , but 35 16 19. Proceeding in the usual manner , the result is 1 yr . 9 mo . 19 da . In ...
... month of the year , and April the fourth , the work is arranged as here shown . We then subtract as with other compound numbers ; 5-16 is impossible , but 35 16 19. Proceeding in the usual manner , the result is 1 yr . 9 mo . 19 da . In ...
Σελίδα 42
... months and days are involved , this is the simplest of all methods . Thus , to find the interest on $ 720 for 10 mo . 10 da . at 6 % , we have $ 7.20 for 2mo . , 5 x $ 7.20 , or $ 36 , for 10 mo . , of $ 7.20 , or $ 1.20 , for 10 da ...
... months and days are involved , this is the simplest of all methods . Thus , to find the interest on $ 720 for 10 mo . 10 da . at 6 % , we have $ 7.20 for 2mo . , 5 x $ 7.20 , or $ 36 , for 10 mo . , of $ 7.20 , or $ 1.20 , for 10 da ...
Σελίδα 44
... month to the cor- responding day of any month within a year is found opposite the first month and under the second . For example , from August 7 to Decem- ber 7 is 122 da .; from November 16 to April 23 is 158 da . , since to April 16 ...
... month to the cor- responding day of any month within a year is found opposite the first month and under the second . For example , from August 7 to Decem- ber 7 is 122 da .; from November 16 to April 23 is 158 da . , since to April 16 ...
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Συχνά εμφανιζόμενοι όροι και φράσεις
30 days 60-day note acres altitude Arithmetic assessed B. H. Roberts balance bank base bill bought brokerage butter fat called Casting out Nines cent commission common fraction compound interest cube root cubic foot dealer decimal places deposit diameter divide dividend divisor draft duty equal example exchange EXERCISE Express extract the square face factor figures Find the amount Find the area Find the cost Find the interest Find the rate find the volume gain geometric geometric progression inches indorse July June June 20 list price marked price merchant multiply myriameter paid Payments pounds premium principal PROBLEMS promissory note proportion radius ratio received rectangular remainder repeating decimal selling price Sept sold specific gravity sphere square root subtract surface term units varas weight yard
Δημοφιλή αποσπάσματα
Σελίδα 205 - CUBIC MEASURE 1728 cubic inches (cu. in.) = 1 cubic foot (cu. ft.) 27 cubic feet = 1 cubic yard (cu. yd.) 128 cubic feet = 1 cord (cd...
Σελίδα 79 - Which proves that the square of a number composed of tens and units contains, the square of the tens plus twice the product of the tens by the units, plus the square of the units.
Σελίδα 207 - Time 60 seconds (sec.) = 1 minute (min.) 60 minutes = 1 hour (hr.) 24 hours = 1 day (da.) 7 days = 1 week (wk.) 365 days = 1 common year...
Σελίδα 204 - SQUARE MEASURE 144 square inches (sq. in.) = 1 square foot (sq. ft.) 9 square feet = 1 square yard (sq. yd.) 30| square yards = 1 square rod (sq. rd.) 160 square rods = 1 acre (A.) 640 acres = 1 square mile (sq.
Σελίδα 94 - Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the operation as before, until all the periods are brought down. NOTE.
Σελίδα 84 - In a right triangle the square of the hypotenuse equals the sum of the squares of the other two sides or legs.
Σελίδα 54 - THE UNITED STATES RULE. Find the amount of the principal to the time when the payment, or sum of the payments, equals or exceeds the interest.
Σελίδα 84 - In a right triangle, the side opposite the right angle is called the hypotenuse and is the longest side.
Σελίδα 67 - If 8 men can do a piece of work in 9 days, how long will it take one man to do the same work ? 17.