The Tutor's Assistant: Being a Compendium of Arithmetic and a Complete Question-book, to which is Added an Appendix on Circulating Decimals...T. Allman, 1832 - 208 σελίδες |
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Σελίδα 23
... ( allowing thirteen months to a year , and 28 days to a month ) , when his first child was born ; between the eldest and next born was 1 year , 11 months , 14 days ; between the second and third were 2 years , 1 month and 15 days ...
... ( allowing thirteen months to a year , and 28 days to a month ) , when his first child was born ; between the eldest and next born was 1 year , 11 months , 14 days ; between the second and third were 2 years , 1 month and 15 days ...
Σελίδα 53
... pend in 8 days ? men . £ . men . * 12 : 160 :: 32 days days . * 4 : 12x4 : 160 :: 32 × 8 = £ 853 . 6s . 8d . If a garrison of 6000 men have provisions for 5 days , allowing F each man 12 oz . per day , how many Double Rule of Three . 53.
... pend in 8 days ? men . £ . men . * 12 : 160 :: 32 days days . * 4 : 12x4 : 160 :: 32 × 8 = £ 853 . 6s . 8d . If a garrison of 6000 men have provisions for 5 days , allowing F each man 12 oz . per day , how many Double Rule of Three . 53.
Σελίδα 70
... allowing for cloff 2 lb , per 3 cwt . and what is the value of the whole , if 1 lb. 3 oz . be worth 6s . 9d . ? 16. What is the neat weight of 136 cwt . 3 qr . 20 lb. gross , allow- ing for tare 7 lb. В oz . per cwt . tret 4 lb. per 104 ...
... allowing for cloff 2 lb , per 3 cwt . and what is the value of the whole , if 1 lb. 3 oz . be worth 6s . 9d . ? 16. What is the neat weight of 136 cwt . 3 qr . 20 lb. gross , allow- ing for tare 7 lb. В oz . per cwt . tret 4 lb. per 104 ...
Σελίδα 142
... allowing 5 per cent . to the purchaser ? 5 × 5,05-5,05 + 2X5 5 × , 05 × 2 + 2 - = 4,4 × 150 = - 660 Ans . £ 550 . - = 500 . 4x , 05 + 1 75. What is the present worth of a lease of £ 50 per annum . to continue 4 years , but is not to ...
... allowing 5 per cent . to the purchaser ? 5 × 5,05-5,05 + 2X5 5 × , 05 × 2 + 2 - = 4,4 × 150 = - 660 Ans . £ 550 . - = 500 . 4x , 05 + 1 75. What is the present worth of a lease of £ 50 per annum . to continue 4 years , but is not to ...
Σελίδα 143
... allowing 5 per cent . to the purchaser , what was the yearly income ? Ans . £ 150 . 550 × 4,05 + 550 = 660 , then 5X , 5 + 1 5 × 3 × , 05—5,05 + 5 × 2 = , 113636 × 660 × 2 = £ 150 . 79. There is a lease of a house taken for 4 years ...
... allowing 5 per cent . to the purchaser , what was the yearly income ? Ans . £ 150 . 550 × 4,05 + 550 = 660 , then 5X , 5 + 1 5 × 3 × , 05—5,05 + 5 × 2 = , 113636 × 660 × 2 = £ 150 . 79. There is a lease of a house taken for 4 years ...
Συχνά εμφανιζόμενοι όροι και φράσεις
acres amount annuity annum answer barrels Bought bushel circle circumference compound interest crowns cube root debt decimal denominator desire to know diameter discount ditto Divide dividend divisor dozen ells equal EXAMPLES Facit farthings feet 6 inches figure Flemish fourth Fucit gain gallons gentleman given number given to find gross guilders guineas half half crowns half-yearly hogsheads hundred improper fraction Integer London lowest terms MEASURE miles milrea moidores Multiplicand Multiply neat weight Note number of days number of terms ounce oxen paid payable pence pension piece pound sterling present payment present worth proper quantity proportion put to interest quarters quotient rate per cent rebate Reduce remainder repetend shews shillings single fraction sold square root subtract subtrahend Table tare third tret TROY WEIGHT vulgar fraction whole number wine yards cost yards of cloth yearly rent
Δημοφιλή αποσπάσματα
Σελίδα 98 - To reduce a mixed number to an improper fraction. RULE. Multiply the whole number by the denominator of the fraction, and to the product add the numerator for a new numerator, and place it over the denominator. 1. Reduce 127T^ to an improper fraction.
Σελίδα 103 - Reduce compound fractions to simple ones, and mixt numbers to improper fractions ; then multiply the numerators together for a new numerator, and the denominators for. a new denominator.
Σελίδα 156 - ... under its respective term ; observing to carry an unit for every 12, from each lower denomination to its next superior.
Σελίδα 86 - Add the several parts of the result together, and if it agrees with the given sum it is right. EXAMPLES. 1. A schoolmaster, being asked how many scholars he had, said, If I had as many, half as many, and one quarter as many more, I should have 264: how many had he?
Σελίδα 124 - RULE 1. Point every third figure of the cube given, beginning at the unit's place ; seek the greatest cube to the first point, and subtract it therefrom ; put the root in the quotient, and bring down the figures in the next point to the remainder for a RESOLVE NII.
Σελίδα 91 - I. When it is required to find how many of the first sort of coin, weight or measure, mentioned in the question, are equal to a given quantity of the last.
Σελίδα 92 - A man is to travel from Boston to a certain place in 12 days, and to go but 3 miles the first day, increasing every day by an equal excess, so that the last day's journey may be 58 miles : what is the daily increase, and how many miles distant is that place from Boston ? Ans.
Σελίδα 46 - Multiply the first and second terms together, and divide the product by the third ; the quotient will be the answer in the same denomination as the middle term was reduced into.
Σελίδα 122 - RULE. Reduce the fraction to its lowest terms, then extract the square root of the numerator for a new numerator, and the square root of the denominator for a new denominator. If the fraction be a surd, (ie) a number whose root can never be exactly found, reduce it to a decimal, and extract the root from it.
Σελίδα 125 - To extract the Square Root of a Vulgar Fraction. RULE, Reduce the fraction to its lowest terms, then extract the square root of the numerator for a new numerator, and the square root of the denominator for a new denominator.