The course of arithmetic as taught in the Pestalozzian school, Worksop. [With] Answers1854 |
Αναζήτηση στο βιβλίο
Αποτελέσματα 1 - 5 από τα 27.
Σελίδα 9
... shillings ; my father gives me seven shillings and my mother five shillings more . How many shall I have altogether ? To find the answer I have to put these three numbers of shillings together , or to add them up ; and the process is ...
... shillings ; my father gives me seven shillings and my mother five shillings more . How many shall I have altogether ? To find the answer I have to put these three numbers of shillings together , or to add them up ; and the process is ...
Σελίδα 18
... 1827. Find the age of each person , the differences , and the sum of their ages in 1853 . MULTIPLICATION . 64. A person spends seven shillings daily . 18 COURSE OF ARITHMETIC . Properties upon which this method is based Ternary period.
... 1827. Find the age of each person , the differences , and the sum of their ages in 1853 . MULTIPLICATION . 64. A person spends seven shillings daily . 18 COURSE OF ARITHMETIC . Properties upon which this method is based Ternary period.
Σελίδα 19
... shillings , in three days 7 + 7 + 7 shillings , & c .; therefore , it is evident that we have to repeat as many times as there are days , or as many times as there are units in 6 . Then the expenses are 6 times 7 or 42 shillings , which ...
... shillings , in three days 7 + 7 + 7 shillings , & c .; therefore , it is evident that we have to repeat as many times as there are days , or as many times as there are units in 6 . Then the expenses are 6 times 7 or 42 shillings , which ...
Σελίδα 26
... shillings , for which he paid 12337 shillings . How much has he yet to pay ? 13. Reckoning every year of 365 days 6 hours , 26 COURSE OF ARITHMETIC ,
... shillings , for which he paid 12337 shillings . How much has he yet to pay ? 13. Reckoning every year of 365 days 6 hours , 26 COURSE OF ARITHMETIC ,
Σελίδα 81
... shillings . .375s . = . 375 × 12d . = 4.500 pence . .5d . = . 5 x 4f . = 2.0 farthings . Or briefly thus : £ .86875 20 17.37500 12 4.500 4 2.0 Therefore , £ .86875 = 17s . 44d . Example Convert .00213 of a day to positive terms : Here ...
... shillings . .375s . = . 375 × 12d . = 4.500 pence . .5d . = . 5 x 4f . = 2.0 farthings . Or briefly thus : £ .86875 20 17.37500 12 4.500 4 2.0 Therefore , £ .86875 = 17s . 44d . Example Convert .00213 of a day to positive terms : Here ...
Περιεχόμενα
11 | |
12 | |
14 | |
15 | |
16 | |
17 | |
18 | |
19 | |
168 | |
169 | |
170 | |
171 | |
172 | |
173 | |
175 | |
176 | |
20 | |
21 | |
22 | |
24 | |
25 | |
28 | |
29 | |
30 | |
31 | |
33 | |
34 | |
35 | |
37 | |
38 | |
39 | |
40 | |
41 | |
42 | |
53 | |
54 | |
57 | |
58 | |
60 | |
63 | |
71 | |
72 | |
75 | |
76 | |
77 | |
78 | |
79 | |
80 | |
82 | |
87 | |
88 | |
89 | |
90 | |
92 | |
94 | |
95 | |
96 | |
97 | |
98 | |
99 | |
100 | |
102 | |
103 | |
104 | |
105 | |
106 | |
108 | |
111 | |
112 | |
113 | |
115 | |
117 | |
118 | |
119 | |
121 | |
122 | |
123 | |
124 | |
125 | |
126 | |
127 | |
128 | |
130 | |
131 | |
133 | |
134 | |
135 | |
136 | |
138 | |
139 | |
140 | |
141 | |
142 | |
143 | |
144 | |
145 | |
146 | |
147 | |
149 | |
159 | |
160 | |
164 | |
167 | |
177 | |
178 | |
179 | |
180 | |
181 | |
182 | |
183 | |
184 | |
185 | |
188 | |
189 | |
190 | |
191 | |
192 | |
193 | |
197 | |
199 | |
201 | |
202 | |
203 | |
204 | |
205 | |
206 | |
207 | |
208 | |
209 | |
210 | |
211 | |
212 | |
213 | |
214 | |
215 | |
217 | |
219 | |
228 | |
232 | |
233 | |
234 | |
235 | |
236 | |
237 | |
238 | |
239 | |
240 | |
241 | |
242 | |
243 | |
244 | |
245 | |
246 | |
247 | |
248 | |
249 | |
255 | |
256 | |
257 | |
258 | |
259 | |
260 | |
261 | |
262 | |
263 | |
264 | |
265 | |
266 | |
267 | |
268 | |
270 | |
271 | |
274 | |
275 | |
276 | |
278 | |
279 | |
280 | |
281 | |
282 | |
283 | |
284 | |
285 | |
286 | |
288 | |
289 | |
290 | |
291 | |
292 | |
293 | |
Άλλες εκδόσεις - Προβολή όλων
The Course of Arithmetic as Taught in the Pestalozzian School, Worksop ... J L Ellenberger Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2016 |
Συχνά εμφανιζόμενοι όροι και φράσεις
1st method 2nd method acres amount annum avoirdupois bought bushel called cent ciphers circumference common difference common fraction compound quantity contained cost cube root cubic inches decimal places denominator diameter discount divide a fraction dividend division divisor dwts equal example exchange EXERCISES Express factors farthings feet Find the number Find the sum Find the value florins francs gain gallon given greatest common measure guinea Hence hundreds improper fraction integer interest logarithms miles minutes mixed quantity months multiplicand number of terms operation paid pence performed person piastres piece pounds present worth principal quotient receive recurring decimal Reduce remainder result Rix-dollars rubles selling share shillings sold square root sterling subtracted tare tens thousandths Troy weight units vulgar fractions weight whole number Worksop yards of cloth
Δημοφιλή αποσπάσματα
Σελίδα 238 - ... one grain of wheat for the first square, two for the second, four for the third, and so on, doubling...
Σελίδα 40 - To reduce a mixed number to an improper fraction, Multiply the whole number by the denominator of the fraction, and to the product add the numerator; under this sum write the denominator.
Σελίδα 238 - Sessa requested that he might be allowed one grain of wheat for the first square on the chess board, 2 for the second, 4 for the third, and so on, doubling continually, to 64, the whole number of squares. Now, supposing, a pint to contain 7680 of these grains, and one quarter or 8 bushels to be worth yja 6d, it is required to compute the value of all the corn ? Ans.
Σελίδα 128 - XV — 24, as shown in the operation. 2. 5 compositors, in 16 days, of 14 hours each, can compose 20 sheets of 24 pages in each sheet, 50 lines in a page, and 40 letters in a line; in...
Σελίδα 286 - The real resistance to a plane, from a fluid acting in a direction perpendicular to its face, is equal to the weight of a column of the fluid, whose base is the plane...
Σελίδα 53 - Multiply the numerator of the dividend by the denominator of the divisor...
Σελίδα 48 - To Multiply a Fraction by a Whole Number. Multiply the numerator by the whole number and divide the product by the denominator.
Σελίδα 43 - Divide the given number by any prime factor ; divide the quotient in the same manner, and so continue the division until the quotient is a prime number. The several divisors and the last quotient will be the prime factors required.