Percentage. 221. APPLICATION OF ART. 220 TO "LOSS AND GAIN." NOTE.-In speaking of the per cent of loss or of gain the cost is regarded as the base unless otherwise specified. Find the per cent of loss or gain in each of the following: 1. Bought for 25¢ and sold for 30¢. 2. Bought for 25¢ and sold for 234. 3. Bought for 25¢ and sold for 274. 4. Bought for 25¢ and sold for 214. 5. Bought for $40 and sold for $48. 6. Bought for $40 and sold for $35. 7. Bought for $40 and sold for $52. 8. Bought for $40 and sold for $36. 9. Sold for 65¢ that which cost 50¢. 10. Sold for 18¢ that which cost 204. 11. Sold for 30¢ that which cost 364. 12. Sold for 354 that which cost 304. 13. Sold for $50 that which cost $40. 14. Sold for $40 that which cost $50. 15. Sold for $30 that which cost $40. 16. Sold for $40 that which cost $30. 17. Mr. Watson bought 60 lbs. of tea at 32¢ a pound and sold it at 50¢. What was his per cent of gain if he sold as many pounds as he bought? If he lost 4 lb. by "downweights" and wastage, how much money did he gain? What was his real per cent of gain? 18. Mr. Jenkins bought gloves at $4.50 per dozen and sold them at 50¢ a pair. What was his per cent of gain? 19. Mr. Warner bought apples at 40¢ a bushel. He lost 25% of them by decay and sold the remainder at 50¢ a bushel. Did he gain or lose by the transaction? What was his per cent of gain or loss? Percentage. 222. PERCENtage ProbleMS UNDER CASE I, IN WHICH THE PER CENT IS MORE THAN 100. Find 175% (11% or 1.75) of $632.60. 175% = 175 = 7. 1 of $632.60 = $158.15. of $632.60 = 7 times $158.15 or $1107.05. PROBLEMS. 1. Find 175% of 356; of 276; of 540.20 2. Find 155% of 356; of 276; of 540.20 of 276; of 540.20 of 540.20 of 276; of 540.20 (a) Find the sum of the twenty-one results. 8. David's money is equal to 150% of Henry's money. Henry has $240. How much has David? 9. If goods cost $260, and the profit on them is 125%, what is the selling price? 10. If a Chicago lot at the beginning of a certain year was worth $8000 and during the year increased in value 50%, what was it worth at the end of the year? What would it have been worth at the end of the year had it increased 250% ? Percentage. 223. PERCENTAGE PROBLEMS UNDER CASE II, IN WHICH THE PER CENT IS MORE THAN 100. $1107.05 is 175% of how much money? Percentage. 224. PERCENTAGE PROBLEMS UNDER CASE III, IN WHICH THE PER CENT IS MORE THAN 100. $1107.05 is what per cent of $632.60? * NOTE.—The above problem may be solved as a similar problem is solved on page 125, Operation No. 1. $1107.05 is 1197.05 of $632.60. Perform the division indicated carrying out to hundredths only. The quotient will be 1.75 or 178 = 175%. PROBLEMS. 1. What per cent of 845 is 2112.5? (a) Find the sum of the 5 answers. Bernie's money 6. Reuben has $2420; Bernie has $4961. equals how many per cent (hundredths) of Reuben's money? 7. A certain house cost $6425. The lot upon which it stands cost $2325. (a) The cost of the house equals how many per cent (hundredths) of the cost of the lot? (b) The cost of the lot equals how many per cent (hundredths) of the cost of the house? * See "Operation and Explanation, No. 4," page 125. Percentage. 225. MISCELLANEOUS PROBLEMS. 1. Find %* of 632; of 356; of 272. (a) Find the sum of the nine results. 4. Find 3% of 496; of 532; of 720. 7. What part of 94 is 11? What per cent? (c) Find the sum of the three *This means of 1 per cent. This means find 25 hundredths of 1 per cent. Answer with a common fraction in its lowest terms. § If it is 15 per cent less than the number it is 85 per cent of the number. |