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" Find the value of one of the unknown quantities, in terms of the other and known quantities... "
An Elementary Treatise on Algebra, Theoretical and Practical ... - Σελίδα 146
των James Ryan - 1835 - 361 σελίδες
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The British Encyclopedia, Or Dictionary of Arts and Sciences ..., Τόμος 1

William Nicholson - 1809
...only one of the unknown quantities, by any of the following methods: 1" Method. In either equation, find the value of one of the unknown quantities in terms of the other and known quantities, and for it substitute this value in the other equation, which will then only contain one nuknown quantity,...

The Elements of Algebra: Designed for the Use of Students in the University

James Wood - 1815 - 305 σελίδες
...only one of the unknown quantities, by any of the following methods : 1" Method. In either equation, find the value of one of the unknown quantities in terms of the other and known quantities, and for it substitute this value in the other equation, which will then only contain one unknown quantity,...

American Edition of the British Encyclopedia: Or, Dictionary of ..., Τόμος 1

William Nicholson - 1819
...only one of the unknown quantities, by any of the following methods : 1st Method. In either equation find the value of one of the unknown quantities in terms of the other and known quantities, and for it substitute this value in the other equation, which will then only contain one unknown quantity,...

Geometrical Problems Deducible from the First Six Books of Euclid, Arranged ...

Miles Bland - 1821 - 438 σελίδες
...equation by 5, and the second by 2, and then, subtracting the second from the first. 2. By substitution. Find the value of one of the unknown quantities, in...obtained in which there is only one unknown quantity. Thus in the first of the preceding examples ; from the second equation, x = 16 — 4 у ; substituting...

Algebraical Problems, Producing Simple and Quadratic Equations, with Their ...

Miles Bland - 1824 - 383 σελίδες
...equation by 5, and the second by 2, and then subtracting the second from the first. 2. By substitution. Find the value of one of the unknown quantities, in...obtained in which there is only one unknown quantity. Thus in the first of the preceding examples ; from the second equation, x = 16 — 4y ; substituting...

An Elementary Treatise on Algebra, Theoretical and Practical ...

James Ryan - 1824 - 516 σελίδες
...it may be more convenient to solve one ot both of the equations first ; that is, to find the values of one of the unknown quantities, in terms of the other and known quantities, as before ; when the rules for eliminating unknown quantities, (§ I. Chap. IV). may be more easily...

Elements of Arithmetic, Algebra, and Geometry

George Lees - 1826
...Now, x - sy^~L?—™^H- 12 - « * •— g — g "~ 2 ~~ 86. METHOD 3d, In either equation, Jind a value of one of the unknown quantities, in terms of the other and known quantities ; substitute this value for the unknown quantity in the second equation, there will thence arise an...

The student's algebra

John Darby (teacher of mathematics.) - 1829
...Indeterminate Analysis. CASE I. When the given equation contains two unknown quantities. RULE. 1 . Find the value of one of the unknown quantities in terms of the rest, as in step first, in the first example. _ 2. Divide the numerator by the denominator, if divisible,...

A Practical System of Algebra: Designed for the Use of Schools and Private ...

Peter Nicholson - 1831 - 309 σελίδες
...the possible values of x and y in integer numbers, suppose the numbers a, b, c, prime to each other. Find the value of one of the unknown quantities in terms of the other. Thus, if the equation be by-lc ax—by=c, then z= — ; Or, ax+by=c, then x= — - — • Increase...

An Elementary Treatise on Algebra, Theoretical and Practical: With Attempts ...

John Radford Young - 1839
...each unknown quantity may be obtained by either of the three following methods. First Method. (54.) Find the value of one of the unknown quantities in terms of the other and the known quantities, from the first equation, by the method already given. Find the value of the same...




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