Mathematics for Common Schools: A Manual for Teachers, Including Definitions, Principles, and Rules and Solutions of the More Difficult ProblemsD.C. Heath & Company, 1895 - 113 σελίδες |
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Σελίδα 50
... cipher from each term : this should be insisted upon whenever the divisor ends in a cipher . In No. 4 , either 74 or 7450 50 should be accepted . If the work in No. 7 takes the form 75 ) $ 27.00 , the answer should be $ .36 ; if the ...
... cipher from each term : this should be insisted upon whenever the divisor ends in a cipher . In No. 4 , either 74 or 7450 50 should be accepted . If the work in No. 7 takes the form 75 ) $ 27.00 , the answer should be $ .36 ; if the ...
Σελίδα 53
... ciphers to be employed to fill out all the numbers to three decimal places . 555. The above suggestions apply here . 559. In the product of .36 by 3 , pupils will naturally place the decimal point where it belongs , as they will in ...
... ciphers to be employed to fill out all the numbers to three decimal places . 555. The above suggestions apply here . 559. In the product of .36 by 3 , pupils will naturally place the decimal point where it belongs , as they will in ...
Σελίδα 54
... ciphers in the multiplier . 561. In giving the quotient of No. 11 , a pupil may write 932. If called upon to read this answer , he will see that 9.32 expresses the same result . He will readily understand that 1860 is also written .086 ...
... ciphers in the multiplier . 561. In giving the quotient of No. 11 , a pupil may write 932. If called upon to read this answer , he will see that 9.32 expresses the same result . He will readily understand that 1860 is also written .086 ...
Σελίδα 55
... cipher in the answer , .02 , to 8 ) .16 . From the inspection of a few examples of this kind , they will understand ... ciphers in the dividend in order to obtain the result . The answer to No. 22 can be derived by a bright scholar from ...
... cipher in the answer , .02 , to 8 ) .16 . From the inspection of a few examples of this kind , they will understand ... ciphers in the dividend in order to obtain the result . The answer to No. 22 can be derived by a bright scholar from ...
Σελίδα 64
... ciphers and to divide by 4. In mental work espe- cially , the annexation of the ciphers confuses some scholars by giving them a larger dividend than is really required . The product of 25 times 19 may be obtained more easily by taking ...
... ciphers and to divide by 4. In mental work espe- cially , the annexation of the ciphers confuses some scholars by giving them a larger dividend than is really required . The product of 25 times 19 may be obtained more easily by taking ...
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12 rods 9 rd Aids to Number Algebra amount annex answer Arithmetic Badlam's Bank Discount Boards BOSTON bushels cancellation cards CHICAGO ciphers colleges column common denominator common fraction contains cost D. C. HEATH decimal fractions decimal point denominate number denominate units divide dividend division draft drills employed English English Language equal equation examples exercises find the Interest Geometry give grades grammar school greatest common divisor Half leather high schools History improper fractions least common multiple Lessons Manual method minuend mixed numbers multiplicand multiply NOTES ON CHAPTER number of square obtained operations Organic Chemistry Paper payment percentage pints pounds practice prime factors PRINCIPLES problems quarts quotient figure rectangles reduce remainder result rods RULE scholars sight subtract subtrahend teacher teaching term of credit text-book whole numbers written yards
Δημοφιλή αποσπάσματα
Σελίδα xxii - In any proportion the product of the means is equal to the product of the extremes.
Σελίδα v - RULE. Divide the given number by any prime factor ; divide the quotient in the same manner, and so continue the division until the quotient is a prime number.
Σελίδα viii - A Complex Fraction is one having a fraction in its numerator, or in its denominator, or in both. A Mixed Number is a whole number and a fraction written together.
Σελίδα ix - To reduce a mixed number to an improper fraction, — RULE : Multiply the whole number by the denominator of the fraction, to the product add the numerator, and write the result over the denominator.