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" Multiply the principal by the rate per cent and divide the product by 100 ; the quotient will be the interest for one year. "
The principles of arithmetic - Σελίδα 240
των Daniel O'Sullivan - 1883 - 423 σελίδες
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A New System of Mercantile Arithmetic: Adapted to the Commerce of the United ...

Michael Walsh - 1807 - 274 σελίδες
...is the sum per cent.-agreed on. Amount, is the principal and interest added together. GENERAL RULE. Multiply the principal by the rate per cent, and divide the product by 100, and the quotient is the answer for one year.. EXAMPLES. 1 . What is the interest of ¿£.496 for one...

A New and Plain System of Arithmetic: Containing the Several Rules of that ...

Elijah H. Hendrick - 1810 - 204 σελίδες
...Simple and Compound.!, SIMPLE INTEREST is that which arifes from the principal only. General Rule. I. Multiply the principal by the rate per cent, and divide the product by loo, (or, which is the fame, cut-off two right hand figures in the pounds, which mint be reduced to...

The Teachers Assistant. Or, A System of Practical Arithmetic: Wherein the ...

1811 - 198 σελίδες
...CASE*1!. When the time is one year, and the rate per cent, is pounds or dollars only. * • RULE.» Multiply the principal by the rate per cent, and divide the product by 100. PROOF. , , By the Single Rule of Three. EXAMPLES. 1. What is the interest of 525 L. for 1 year, at...

Daboll's Schoolmaster's Assistant: Improved and Enlarged, Being a Plain ...

Nathan Daboll - 1815 - 240 σελίδες
...principal and interest added together. CASE I. To find the interest of any given sum for one year. RULE. Multiply the principal by the rate per cent, and divide the product by 100 ; the quotient will be the answer. EXAMPLE!. 1. What is the interest of 39Z. lls. 8id. for one year...

Daboll's Schoolmaster's Assistant: Improved and Enlarged. Being a Plain ...

Nathan Daboll - 1823 - 240 σελίδες
...principal and interest added together. CASE I. To find the interest of any given sum for one yeai» RULE. Multiply the principal by the rate per cent. and divide the product by 100 ; the quotient will be the answer. EXAMPLES. 1. What is the interest of S9/. Us. 8itI. for one year,...

The Teachers' Assistant: Or a System of Practical Arithmetic

1824 - 198 σελίδες
...1. To find the interest when the time is one year, and the rate per cent. is pounds or dollars only. Multiply the principal by the rate per cent. and divide the product by 100: the quotient will be the interest for 1 year. PROOF. By the Single Rule of Three. EXAMPLES. 1. What...

Daboll's Schoolmaster's Assistant, Improved and Enlarged

Nathan Daboll - 1825 - 240 σελίδες
...principal and interest addeâ together. CASE i. Vb find {he interest of any given sum for one ysar. RULE. Multiply the principal by the rate per cent. and divide the product by 100 ; the quotient will be the answer. EXAMPLES. 1. What is the interest of 391. 11s. SJd. for one year....

The American Arithmetic: Adapted to the Currency of the United States. To ...

Oliver Welch - 1826 - 227 σελίδες
...1.60 21 226 32 292 10 1.05 11 106 22 2.32 33 298 11 1.055 SIMPLE I.VTEHEST IN LAWFUL MOSEY. RULE. — Multiply the principal by the rate per cent., and divide the product dy 100, the quotient is T year's interest; if months and days are mentioned in the time, find 1 year's...

The American Tutor's Assistant, Improved: Or, A Compendious System of ...

Zachariah Jess - 1827 - 211 σελίδες
...time is any number of years, and the rate per cenv pounds or dollars only ; . ' RULE THE COMMON WAY. Multiply the principal by the rate per cent, and divide the product by 100, the quotient will be the interest for one year, which multiply by the years given. RULE DECIMALLY....

The Common School Manual: A Regular and Connected Course of Elementary ...

Montgomery Robert Bartlett - 1828
...SIMPLE INTEREST. Simple Interest is that which accrues on the principal on!) ^ for a given time. Rule. Multiply the Principal by the rate per cent, and divide the Product by 100, the Quotient will be the answer.— Thus:— CASE 1. tVhen the given time is one year. (1) What is...




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