of $50. In a few places, the price is quoted as 48, meaning $48 per share. In the examples given in the Arithmetic, the rate always means the per cent of the par value. 1. (87) % of ($10 x 240). = 2. Brokerage 1% of ($100 × 120) = $30. = $11460-$30-$11430; value per share = $95.25. 3. Let x 150) = 5265; Value of stock $11430 ÷ 120 par value per share. Then (87+)% of (x × x × 150 × 873_ x x 150 x 351 5265. Using the cancellation method, x = 4. 1% of $27500. 5. 1024% of ($ 25 × 200) = selling price. Deduct therefrom 1% of ($25 × 100). 6. His income is 18% of the par value ($100 × 60) = $1080. His investment is 450% of ($100 × 60) = $27000. $1080 is 4% (Ans.) of $27000. = Or, irrespective of number of shares, 18% 44%. Ans. 7. The stock = $50 × 4000 $200000. The rate of dividend = $20000 $200000 10%. Ans. 10% ÷ 1.75= 55%. Ans. = = + 8. $10000 interest must be paid to the bondholders, leaving ($47500-$10000) $37500 to be paid as dividends on $1000000 of stock. 37500 ÷ 1000000 = .0375 33%. 9000 (168+x) = 1517625; etc. 10. Let x amount of brokerage. 1073% of (100 x 250)-x=26875; 26937.50 x= x = 26875; 62.50; brokerage = $62.50. Ans. Etc. 11. $35050 +1.75 $20000 = par value of stock; 74% of $20000 $1500. Ans. = 12. Mr. Tower receives $30 interest, and $100, the face value of the bond, in six years, $130 in all. His investment was $104, on which he has received $130-$104, or $26 interest in 6 yr., or $4.33 per year. 4 104.041 41%. Ans. = 1093. 1. A corporation is an association of a number of persons legally empowered to transact business as a single individual. The charter specifies the name of the corporation, the amount of capital, the business it is authorized to carry on, the powers and privileges conferred, etc. The stock is the money invested in the business of the corporation; a share is one of the equal parts into which the stock is divided; a shareholder is the owner of one or more shares; a stockbroker is a person engaged in the business of buying and selling stocks on commission; a dividend is a pro rata division of profits among the stockholders; an assessment is a sum levied upon stockholders to meet some unexpected expenses, losses, etc. = 2. Income from bonds 6% of $125 × 109 ÷ 1.09 = 6% of $12500-$750, an increase of $ 68.75 over the previous income of $681.25. 3. Sum loaned = $59.57÷= $59.57 × 6. 4. In 3 yr. at 7%, $1 will amount to $1.21; i.e. a payment of $1.21 in 3 yr. is considered equal to a cash payment of $1. The "present worth" of the delayed payment = $ 4235 ÷ 1.21 = $3500, which is a loss of $3675 - $3500 $175. Ans. = 5% ÷ (.981 + .001) = 5 ÷ .981; on The cost of a $100 5% bond is $98.25 + 25 brokerage = $98.50; the interest on the bond is 5% of $100=$5; the rate is, therefore, 5%.981; etc. 6. The time of the place being 1 hr. later than the time of the starting-point, the traveler is 15° east of the latter place. 8. As the note is stated to be due in 3 mo., which may be assumed to include days of grace where allowed, the date of its maturity is Sept. 20. The amount of the note for 92 da., at 9%, $2455.20. The discount on this sum at 6% from Aug. 8 to Sept. 20, 43 da. $17.60. Proceeds === $2437.60. Ans. = $2455.20 $17.60 = 10. $4800 less 63 days' interest, $50.40, $4749.60. = ($4797.58 less 60 days' interest, $47.98, $4749.60.) 1097. 4. Having found that V.10.316+, the pupils should see that V.1.316+. In pointing off, begin at the units' place, pointing off two places to the right or the left. 7. 1.6 is made 1.60. See 10. 1098. 7. Find the amount of $467.50 at 6% from July 5, 1881, to Dec. 19, 1885. 8. Amount stolen = 18 of $523.25; the second, to 8 of $523.25; etc. 9. THE UNITED STATES $650. The first sender is entitled to To Services, Nov. 19-30, 12 da. $12.50 Stage Fare St'mb't Fare Telegraph 33 15 = $126 80 10. The account for the first quarter, exclusive of box rents, is $124.96. On $50, the commission allowed $50. On the remaining $74.96, the commission is 60% = $44.98. Total = $77+$50+$44.98 $171.98. $171.98 +$194.01+$174.08 +$167.87 1099. Base2+ perpendicular2 = hypotenuse'; H=√B2+ P2. 1. 22564x2; x2 = 289; x = 17, hypotenuse. 2. 1225+ x2 1369; x2=1369 – 1225 = 144; x = 12, perpendicular. 3. x2+225=1521; x2=1521 - 225 = 1296; x 36, base. 1100. 11. Let x = perpendicular. Area = (200+160) × 450; 15x450-300=150; x= 10. 13. † (x + x + 6) × 10 = (x + 3) × 10 = 10 x + 30 = 150; 10 x= 15030= = 120; x = 12, x + 6 = 18. 12 rd. and 18 rd. Ans. 14. The base = 7 rd.; the altitude, or perpendicular, = 24 rd. Area (24 x 7) sq. rd. 15. Number of stones (28 × 12). 16. The angle of 90° Hypotenuse = 20 chains. +20=48. 1 chain = 66 4 = 192. 17. A perpendicular let fall from the upper right corner would form a right-angled triangle, whose perpendicular is 40 ft., base 30 ft., making the hypotenuse = √1600+ 900 ft. = 50 ft., the fourth side. = The number of yards of fence (40+ 70+ 50+100) × 51. Area in acres · [1⁄2 of (70 + 100) × 40] ÷ 160. = 18. The diagonal is the hypotenuse of a right-angled triangle whose other sides measure, respectively, 90 yd. and 120 yd. The 27 chains 36 chains 63 chains. 19. The diagonal = √1296 + 729 chains 45 chains. distance by the road The saving is 18 chains, of 22 yd. each. = 20. A 40-acre field contains 6400 sq. rd. Each side measures √6400 rd. 80 rd. The diagonal√80+802. 1101. 1. The loss is of the cost, $300. 2. If 3 boys solve 3 problems in 3 min., 1 boy will solve 1 problem in 3 min., and 6 boys will solve 6 problems in 3 min. Or, 3 boys will solve 6 problems in 6 min., therefore 6 boys will solve 6 problems in 3 min. 3. The 3 boys eat 12 cakes, 4 each; for which the third boy pays 12, or 3 apiece. The boy that brought 7 cakes supplies 3; for which he should receive 94. The other boy furnishes 1, and is entitled to 34. 4. The cost of the article is 50; a sale for $2.00 is a gain of $1.50, or 300%. 6. A 6-ft. fence needs 2 posts, one at each end; a 12-ft. fence, 3 posts; a 30-ft. fence, 6 posts. 7. One half is profit, the other half is the cost. The profit equals the cost, and is 100%. 8. 1x × x= 2x2 = 60; 3x2 = 1200; x2 = 400; x=20. 10. The difference between 28 and 75, inclusive, =(75 — 28) +1. 1102. 2. The quantity of provisions for each man = 21 lb. X 20=45 lb. To last 24 da., the allowance should be 45 lb. ÷ 24 = 17 lb. = 1 lb. 14 oz. = 5. 80 min. x 112÷ 46. Cancel. 6. See Arithmetic, Arts. 821, 822. The second 7. First beam contains (66 × 10 × 8) cu. in. contains (x 12 × 12) cu. in. The contents of the latter = times the contents of the former. 3024 = 924 |