Mathematics for Common Schools: A Manual for Teachers, Including Definitions, Principles, and Rules and Solutions of the More Difficult Problems1896 |
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Σελίδα 114
... altitude ) , the area of the latter is equal to base altitude . For definitions of quadrilaterals see Art . 1265 . 6. The area of the first is equal to the area of the rectangle , ( 50 × 60 ) , plus the area of the triangle , of ( 50 ...
... altitude ) , the area of the latter is equal to base altitude . For definitions of quadrilaterals see Art . 1265 . 6. The area of the first is equal to the area of the rectangle , ( 50 × 60 ) , plus the area of the triangle , of ( 50 ...
Σελίδα 177
... altitude , or perpendicular , = 24 rd . Area ( 24 x 7 ) sq . rd . 15. Number of stones ( 28 × 12 ) . 16. The angle of 90 ° Hypotenuse = 20 chains . + 20 = 48 . 1 chain = 66 4 = 192 . - - ( 84 × 36 ) ÷ ( 6 × 3 ) . Cost $ 14 × indicates a ...
... altitude , or perpendicular , = 24 rd . Area ( 24 x 7 ) sq . rd . 15. Number of stones ( 28 × 12 ) . 16. The angle of 90 ° Hypotenuse = 20 chains . + 20 = 48 . 1 chain = 66 4 = 192 . - - ( 84 × 36 ) ÷ ( 6 × 3 ) . Cost $ 14 × indicates a ...
Σελίδα 181
... altitude of a triangular field . On this account , a method of determining the area when the lengths of the sides are given , is useful , even though the underlying principles be not understood . A pupil can satisfy himself as to its ...
... altitude of a triangular field . On this account , a method of determining the area when the lengths of the sides are given , is useful , even though the underlying principles be not understood . A pupil can satisfy himself as to its ...
Σελίδα 182
... altitude AC , Fig . 2 , Arithmetic , Art . 1263 , of an isosceles triangle divides the base into two equal parts , BC 15 yd . AC2 - The area - = = AB2 - BC2 = 625-225 = 400 ; AC = 20 yd . of 600 sq . rd . = 300 rd . The area by the ...
... altitude AC , Fig . 2 , Arithmetic , Art . 1263 , of an isosceles triangle divides the base into two equal parts , BC 15 yd . AC2 - The area - = = AB2 - BC2 = 625-225 = 400 ; AC = 20 yd . of 600 sq . rd . = 300 rd . The area by the ...
Σελίδα 194
... altitude . Area = 1⁄2 ( 60+ 130 ) × altitude . 18. See 4 , Measurements , Art . 1107 . 19. The altitude = √302 — 152 . 20. Find the area as in 1 , Measurements , Art . 1107. Divide the area by one - half the base to obtain the altitude ...
... altitude . Area = 1⁄2 ( 60+ 130 ) × altitude . 18. See 4 , Measurements , Art . 1107 . 19. The altitude = √302 — 152 . 20. Find the area as in 1 , Measurements , Art . 1107. Divide the area by one - half the base to obtain the altitude ...
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acres algebraic altitude amount angle Annual interest apothem Arithmetic ascertain base bisecting calculate Cancel cent chord circle circumference commission construct contains convex surface cost days of grace decimal deducting diagonal diameter difference Divide dividend divisor draft draw drawn equal equation factors figure frustum gain given gives greatest common divisor hypotenuse Improper Fraction inches intersecting least common multiple length longitude loss March 17 marked price measure method minuend mixed numbers Multiply number of days number of degrees number of square obtain par value payment percentage perpendicular principal problems Proceeds profits protractor pupils quotient radius rectangle remaining rhombus right-angled triangle rods RULE scholars selling price side slant height solve subtract subtrahend teacher term vertex whole number William Simms yards
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Σελίδα 173 - A corporation is an association of a number of persons legally empowered to transact business as a single individual. The charter specifies the name of the corporation, the amount of capital, the business it is authorized to carry on, the powers and privileges conferred, etc. The stock is the money invested in the business of the corporation ; a share is one of the equal parts into which the stock is divided ; a shareholder is the owner of one or more shares ; a stockbroker is a person engaged in...
Σελίδα xix - Multiply each payment by its term of credit, and divide the sum of the products by the sum of the payments ; the quotient will be the average term of credit.
Σελίδα viii - Reduce the fractions to a common denominator and divide the numerator of the dividend by the numerator of the divisor.
Σελίδα ii - I. Write the divisor at the left of the dividend, with a line between them.
Σελίδα vi - Multiplying or dividing both terms of a fraction by the same number does not alter the value of the fraction.
Σελίδα 126 - Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area.
Σελίδα vii - To reduce a mixed number to an improper fraction, — RULE : Multiply the whole number by the denominator of the fraction, to the product add the numerator, and write the result over the denominator.
Σελίδα iii - RULE. Divide the given number by any prime factor ; divide the quotient in the same manner, and so continue the division until the quotient is a prime number.