Εικόνες σελίδας
PDF
Ηλεκτρ. έκδοση

Miscellaneous Exercises on Props. I. to XXVI. 1. M is the middle point of the base BC of an isosceles triangle ABC, and N is a point in AC. Shew that the difference between MB and MN is less than that between AB and AN.

2. ABC is a triangle, and the angle at A is bisected by a straight line which meets BC at D; shew that BA is greater than BD, and CA greater than CD.

3. AB, AC are straight lines meeting in A, and D is a given point. Draw through D a straight line cutting off equal parts from AB, AC.

4. Draw a straight line through a given point, to make equal angles with two given straight lines which meet.

5. A given angle BAC is bisected ; if CA be produced to G and the angle BAG bisected, the two bisecting lines are at right angles.

6. Two straight lines are drawn to the base of a triangle from the vertex, one bisecting the vertical angle, and the other bisecting the base. Prove that the latter is the greater of the two lines.

7. Shew that Prop. XVII. may be proved without producing a side of the triangle.

8. Shew that Prop. XVIII, may be proved by means of the following construction : cut off AD=AB, draw AE, bisecting

BAC and meeting BC in E, and join DE.

9. Shew that Prop. xx. can be proved, without producing one of the sides of the triangle, by bisecting one of the angles.

10. Given two angles of a triangle and the side adjacent to them, construct the triangle.

11. Shew that the perpendiculars, let fall on two sides of a triangle from any point in the straight line bisecting the angle contained by the two sides, are equal.

We conclude Section I. with the proof (omitted by Euclid) of another case in which two triangles are equal in all respects.

PROPOSITION E. THEOREM. If two triangles have one angle of the one equal to one angle of the other, and the sides about a second angle in each equal : then, if the third angles in each be both acute, both obtuse, or if one of them be a right angle, the triangles are equal in all respects.

In the as ABC, DEF, let 2 BAC= . EDF, AB=DE, BC=EF, and let 28 ACB, DFE be both acute, both obtuse, or let one of them be a right angle.

Then must As ABC, DEF be equal in all respects.

[ocr errors]
[ocr errors]

I. A.

For if AC be not =DF, make AG=DF; and join BG.
Then in As BAG, EDF,
::: BA=ED, and AG=DF, and . BAG= _ EDF,
.:. BG=EF and LAGB= LDFE.

I. 4.
But BC=EF, and .:. BG=BC;

.. LBCG= L BGC. First, let ACB and 2 DFE be both acute,

then . AGB is acute, and .. 2 BGC is obtuse ; I. 13. .: LBCG is obtuse, which is contrary to the hypothesis. Next, let ACB and 2 DFE be both obtuse,

then LAGB is obtuse, and ... BGC is acute; I. 13. ... BCG is acute, which is contrary to the hypothesis.

I. A.

Lastly, let one of the third angles ACB, DFE be a right angle. If LACB be a rt. 1,

then _ BGC is also a rt. 2; .:28 BCG, BGC together=two rt. 28, which is impossible.

I. 17. Again, if DFE be a rt. 1, then AGB is a rt. , and ... BGC is a rt. 6.

I. 13. Hence - BCG is also a rt. L. .. 28 BCG, BGC together=two rt. 28, which is impossible.

I. 17. Hence AC is equal to DF, and the A8 ABC, DEF are equal in all respects.

Q. E. D.

COR. From the first case of this proposition we deduce the following important theorem :

If two right-angled triangles have the hypotenuse and one side of the one equal respectively to the hypotenuse and one side of the other, the triangles are equal in all respects.

NOTE. In the enunciation of Prop. E, if, instead of the words if one of them be a right angle, we put the words both right angles, this case of the proposition would be identical with I. 26.

SECTION II.

The Theory of Parallel Lines.

INTRODUCTION. We have detached the Propositions, in which Euclid treats of Parallel Lines, from those which precede and follow them in the First Book, in order that the student may have a clearer notion of the difficulties attending this division of the subject, and of the way in which Euclid proposes to meet them.

We must first explain some technical terms used in this Section.

If a straight line EF cut two other straight lines AB, CD, it makes with those lines eight angles, to which particular names are given.

[blocks in formation]

The angles numbered 1, 4, 6, 7 are called Interior angles.

2, 3, 5, 8

Exterior... The angles marked 1 and 7 are called alternate angles. The angles marked 4 and 6 are also called alternate angles.

The pairs of angles 1 and 5, 2 and 6, 4 and 8, 3 and 7 are called corresponding angles.

NOTE. From I. 13 it is clear that the angles 1, 4, 6, 7 are together equal to four right angles.

PROPOSITION XXVII. THEOREM.

If a straight line, falling upon two other straight lines, make the alternate angles equal to one another ; these two straight lines must be parallel.

[merged small][merged small][merged small][merged small][ocr errors][merged small][merged small]

Let the st. line EF, falling on the st. lines AB, CD,

make the alternate 28 AGH, GHD equal.

Then must AB be || to CD.

For if not, AB and CD will meet, if produced, either towards B, D, or towards A, C.

Let them be produced and meet towards B, D in K.
Then GHK is a ^ ;

and , LAGH is greater than 4 GHD. I. 16. But LAGH=4GHD,

Нур. which is impossible.

.. AB, CD do not meet when produced towards B, D. In like manner it may be shewn that they do not meet when produced towards A, C. .: AB and CD are parallel.

Def. 26.

Q. E, D.

« ΠροηγούμενηΣυνέχεια »