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DEFINITIONS.

XXVII. A PARALLELOGRAM is a

four-sided figure whose opposite

sides are parallel.

D

For brevity we often designate a parallelogram by two letters only, which mark opposite angles. Thus we call the figure in the margin the parallelogram AC.

XXVIII. A Rectangle is a parallelogram, having one of its angles

a right angle.

Hence by I. 29, all the angles of a rectangle are right angles.

XXIX. A RHOMBUS is a parallelogram, having its sides equal.

XXX. A SQUARE is a parallelogram, having its sides equal and one of its angles a right angle.

Hence, by I. 29, all the angles of a square are right angles.

XXXI. A TRAPEZIUM is a four-sided figure of which two

sides only are parallel.

XXXII. A DIAGONAL of a four-sided figure is the straight line joining two of the opposite angular points.

XXXIII. The ALTITUDE of a Parallelogram is the perpendicular distance of one of its sides from the side opposite, regarded as the Base.

The altitude of a triangle is the perpendicular distance of one of its angular points from the side opposite, regarded as the base.

Thus if ABCD be a parallelogram, and AE a perpendicular let fall from A to CD, AE is the altitude of the parallelogram, and also of the triangle ACD.

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If a perpendicular be let fall from B to DC produced, meeting DC in F, BF is the altitude of the parallelogram.

EXERCISES.

Prove the following theorems:

1. The diagonals of a square make with each of the sides an angle equal to half a right angle.

2. If two straight lines bisect each other, the lines joining their extremities will form a parallelogram.

3. Straight lines bisecting two adjacent angles of a parallelogram intersect at right angles.

4. If the straight lines joining two opposite angular points of a parallelogram bisect the angles, the parallelogram is a rhombus.

5. If the opposite angles of a quadrilateral be equal, the quadrilateral is a parallelogram.

6. If two opposite sides of a quadrilateral figure be equal to one another, and the two remaining sides be also equal to one another, the figure is a parallelogram.

7. If one angle of a rhombus be equal to two-thirds of two right angles, the diagonal drawn from that angular point divides the rhombus into two equilateral triangles.

PROPOSITION XXXIV. THEOREM.

The opposite sides and angles of a parallelogram are equal to one another, and the diagonal bisects it.

D

Let ABDC be a □, and BC a diagonal of the O.
Then must AB=DC and AC=DB,

and

and

▲ BAC= 2 CDB, and ▲ ABD= 4 ACD

▲ ABC

ADCB.

For AB is to CD, and BC meets them,

.. ABC alternate DCB;

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and AC is to BD, and BC meets them,

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I. 29.

I. 29.

** 2 ABC= 2 DCB, and ▲ ACB= 2 DBC,

and BC is common, a side adjacent to the equal ▲ s in each; .. AB=DC, and AC=DB, and ▲ BAC= 2 CDB,

Also

and ▲ ABC= ▲ DCB.

ABC= 4 DCB, and ▲ DBC= ▲ ACB,

.. Ls ABC, DBC togethers DCB, ACB together,

I. B.

that is,

=

L ABD LACD.

Q. E. D.

Ex. 1. Shew that the diagonals of a parallelogram bisect each other.

Ex. 2. Shew that the diagonals of a rectangle are equal.

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Parallelograms on the same base and between the same parallels are equal.

DE

Let the Os ABCD, EBCF be on the same base BC. and between the same s AF, BC.

Then must ☐ ABCD=□ EBCF.

CASE I. If AD, EF have no point common to both,

Then in the As FDC, EAB,

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ABCD with ▲ FDC=□ EBCF with ▲ EAB;

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CASE II. If the sides AD, EF overlap one another,

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CASE III. If the sides opposite to BC be terminated in the same point D,

W

B

the same method of proof is applicable,
but it is easier to reason thus:

Each of the Os is double of a BDC;

.. ABCD=□ DBCF.

I. 34.

Q. E. D.

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Parallelograms on equal bases, and between the same parallels, are equal to one another.

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Let the Os ABCD, EFGH be on equal bases BC, FG, and between the same Is AH, BG.

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...they are on the same base BC and between the same ||s ;

and

EBCH=□EFGH,

I. 35.

they are on the same base EH and between the same ||s; ..ABCDEFGH.

Q. E. D.

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