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(55.) A horse in his furniture is worth £52 10s.; out of it, £24 10s. 6d. ; how much does the price of the furniture exceed that of the horse?

(56.) What sum added to £11 14s. 94d., will make £133 11s. 9 d.?

(57.) A tradesman, failing, was indebted to A £105 19s. 11d., to B 150 guineas, to C 34 18s. 10d., to D £500 19s., to E £700 14s. 9d. When this happened, he had cash by him to the amount of £50, goods to the amount of £350 14s. 9d., his household furniture was worth £24 11s. his book-debts amounted to £94 148. 8d. If these things were faithfully given up to his creditors, what did they lose by him?

(58.) The great bell at Oxford, the heaviest in England, weighs 7t. 11cwt. 3qr. 4lb., St. Paul's bell at London weighs 5t. 2cwt. 1qr. 22lb., and Tom of Lincoln weighs 4t. 16cwt. 3qr. 18lb. How much are these bells, together, inferior in weight to the great bell at Moscow, the largest in the world, which weighs 198t. 2cwt. 1qr.? (59.) An apprentice, who is 14 years, 11 months, 13 weeks, 14 days, 15 hours, 38 minutes old, is to serve his master till he is 21 years of age. How long has he to serve?

(60.) What are the difference of latitude and longitude between Calcutta in the East Indies (Lat. 22° 34′ N., Long. 88° 34′ E.), and Lima in South America (Lat. 12° 1' S., Long. 76° 44′ W.)

COMPOUND MULTIPLICATION.

Definition.-Compound Multiplication is a rule by which we find the amount of any given number, of different denominations, by repeating it any proposed num

ber of times.

Proposition 1. When the multiplier does not exceed 12.

Rule. Multiply the lowest denomination by it, divide the product by the number making one of the next higher denomination; set down the remainder, and carry the quotient to the product of the next higher denomination : proceed thus till all the denominations are multiplied.

Prop. 2. If the multiplier exceeds 12, and is a composite number.

Rule. Multiply successively by the component parts instead of the whole number at once.

Prop. 3. When the multiplier cannot be produced by the multiplication of two, or more, small numbers.

the

Rule. Find two, or more, numbers that compose nearest number to the multiplier; then multiply by the component parts, as before, and add or subtract, the odd parts, as you find occasion.

Prop. 4. If the multiplier be four, five, or more, hundreds.

Rule. Multiply the given price, or quantity, by 10, and that product by 10, and so on for 10, 100, or 1000 times the price or quantity: then multiply each product by the number of thousands, hundreds, and tens, and the first line by as many as make up the number of things, or multiplier, and the sum of the products will be the answer.

Prop. 5. If the multiplier be a whole number with parts annexed.

Rule. When you have multiplied by the whole number, for †,†, i, j, or, &c. divide the top line by 2, 3, 4, 5, or 6, &c.; but, if the numerator of the fractional part be greater than 1, multiply the top line by it, and divide the product by the denominator; add this quotient to the product, or value, obtained by multiplying with the whole number.

Note. The upper figure is called the numerator, and the lower one the denominator. Thus 5 Numerator.

7 Denominator.

Examples to Proposition 1.

(1.) What cost 4 yards of cloth || (3.) 6 yards at 68. 9d.

at 7s. 6d. per yard?

76

£1 10 2 Answer.

(2.) 5 bushels at 58. 10d.

(4.) 7 ells at 58. 114d.
(5.) 8oz. at 78. 10d.
(6.) 9lb. at 7s. 5td.
(7.) 10 gallons at 16s, 44d.
(8.) 11cwt. at 17. 98. 104d.
(9.) 12 sheep at 17. 178. 9d.

(10.) In 9 pieces of Kersey, each 14yds. 3qrs, 2n., how many yards?

(11.) What is the weight of 12 tankards, each weighing 11oz. 10dwt. 19gr.?

(12.) In 11 pieces of cloth, each 17yds. 3qrs. 3n., how many yards?

Examples to Prop. 2.

(15.) What cost 15 gallons of wine, at 58. 34d. per gallon? 5 5x315.

1 6 34 price of 5.

£3 19 44 price of 15. Ans. (14.) 16hhds, at 37. 148, 5d.

(15.) 24 yards at 78. 5d.
(16.) 35cwt. at 11. 14s. 8d.
(17.) 36tns. at 57. 15s. 114d.
(18.) 84chal. at 17. 16s. 9 d.
(19.) 108 bushels at 78. 9 d.
(20.) 132 ells at 188. 91d.
(21.) 144bts. at 57. 19s. 9 d.

(22.) In 32 wedges of gold, each 2lb. 7oz. 14gr., how many pounds?

(23.) In 21 fields, each 3a. 2r. 19p., how many acres?

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Examples to Prop. 3.

(24.) What cost 23 yards of cloth at 14s. 9d. per yard.

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(25.) 31 yards at 12s. 74d. || (29.) 111 sacks of flour at

(26.).39 dozen at 6s. 74d.
(27.) 139 pair at 4s. 91d.
(28.) 86lb. of silk at 19s. 4d.

11. 4s. 9d.

(30.) 156cwt. at 4l. 9s. 6d.

(31.) In 57 years, each 13m. 1 day, 6hrs., how many months?

(32.) What is the weight of 29hhds. of sugar, each 7cwt. 2qr. 18lb. ?

(33.) In 67 parcels of tea, each 25lb. 7oz. 13drs., how many cwts., &c. ?

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(45.) 1788 gallons at 6s. 4d.

(46) 3714 cwt. at 47. 11s. 9d.

(47.) 71493 chaldrons at 17. 14s. 9d.

(48.) 547 lasts at 51. 5s.

(49.) 1749 firkins at 14s. 91d.

(50.) 754 cwt. at 17s. 51d.

Note. Should the preceding examples be thought insufficient to complete the scholar in this useful rule, recourse may be had to the bills of parcels, Part III. Class 1.-If the teacher approve it, he may omit this proposition till the scholar has learnt compound division.

COMPOUND DIVISION.

Definition.-Compound Division teaches us to find how often one given number is contained in another of different denominations; or, to divide a given compound number into any proposed number of equal parts.

RULE.

Place the divisor to the left-hand of the dividend. Divide the highest denomination of the dividend by the divisor, and bring the remainder, if any, into the next inferior denomination, adding thereto the parts of that name in the dividend: divide this number as above, and so on till the whole is finished. If the divisor be large,

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