 | Adrien Marie Legendre - 1838 - 372 σελίδες
...BC2=AB2+AC2. Cor. 1. Hence the square of one of the sides of a right angled triangle is equivalent to the square of the hypothenuse diminished by the square of the other side ; which is thus expressed : AB2=BC2— AC2. Cor. 2. It has just been shown that the square AH is equivalent... | |
 | James Bates Thomson - 1844 - 268 σελίδες
...1. Hence, by transposition, the square of one of the sides of a right-angled triangle is equivalent to the square of the hypothenuse diminished by the square of the other side ; which is thus expressed, ABS=BC2 — AC2. Cor. 2. It has just been shown that the square AH is equal... | |
 | Nathan Scholfield - 1845 - 894 σελίδες
...BC"=AB'-fAC2. Cor. 1. Hence the square of one of the sides of a right angled triangle is equivalent to the square of the hypothenuse diminished by the square of the other side; which is thus expressed : AB2=BC2— AC:. Cor. 2 It has just been shown that the square AH is equivalent... | |
 | Elias Loomis - 1849 - 252 σελίδες
...squares ABFG, ACIH, described on the two other sides; that is, BC'=AB'+AC'. triangle, is equivalent to the square of the hypothenuse, diminished by the square of the other side ; that is, AB'=BC'—AC'. Cor. 2. The square BCED, and the rectangle BKLD, having the same altitude,... | |
 | Charles Davies - 1849 - 372 σελίδες
...BC 2 ^AB < ' Cor. 1. Hence the square of one of the sides of a right angled triangle is equivalent to the square of the hypothenuse diminished by the square of the other side ; which is thus expressed : AB 2 =BC 2 —AC 2 . Cor. 2. It has just been shown that the square AH... | |
 | Charles Davies - 1850 - 238 σελίδες
...the other two sides. Cor. Hence, the square of either side of a right angled triangle is equivalent to the square of the hypothenuse diminished by the square of the other side. That is, in the right angled triangle ABC or Bl?=A(?-AT?. Sch. The last theorem may be illustrated... | |
 | Charles Davies - 1850 - 218 σελίδες
...the other two sides. Cor. Hence, the square of either side of a right angled triangle is equivalent to the square of the hypothenuse diminished by the square of the other side. That is, in the right angled triangle ABC *=;AC*— Iff Sch. The last theorem may be illustrated by... | |
 | James B. Dodd - 1852 - 410 σελίδες
...be expressed thus : AC2=:AB2 + BC2. Hence also the square on either of the two perpendicular sides, is equal to the square of the hypothenuse diminished by the square of the other side ; that is, AB2=AC3 — BC3: and BC - - AC 3 — AB2. On these principles, any one side of a right angled... | |
 | Charles Davies - 1886 - 340 σελίδες
...the other 1wo sides. Cor. Hence, the square of either side of a right angled triangle is equivalent to the square of the hypothenuse diminished by the square of the other side. That is, in the right angled triangle ABC or BC=O= Sch. The last theorem may be illustrated by describing... | |
 | Adrien Marie Legendre - 1852 - 436 σελίδες
...of the squares BALH, CIKA, described on the two other sides ; that is, angled triangle is equivalent to the square of the hypothenuse diminished by the square of the other side; thus, Cor. 2. If from the vertex of the right angle, a perpendicular be let fall on the hypothenuse,... | |
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Also the square of either of the two sides which form the right angle is equal to the square of the hypothenuse diminished by the square of the other side. 
