... the first term of the quotient ; multiply the divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor... A Treatise on Algebra - Σελίδα 38των Elias Loomis - 1858 - 359 σελίδεςΠλήρης προβολή - Σχετικά με αυτό το βιβλίο
| William Smyth - 1830 - 278 σελίδες
...dividend with reference to the powers of the same letter, 1°. Divide the first term of the dividend by the first term of the divisor, the result will be the first term of the quotient ; 2°. multiply the whole divisor by the term of the quotient just found,... | |
| Bourdon (M., Louis Pierre Marie) - 1831 - 446 σελίδες
...quotient; multiply the divisor by this term, and subtract the product from the dividend. Then divide the first term of the remainder by the first term of the divisor, which gives the second term of the quotient ; multiply the divisor by this second term, and subtract... | |
| Peter Nicholson - 1831 - 326 σελίδες
...root. W Raise this quotient to the given power, and subtract it from the dividend ; then divide the first term of the remainder by the first term of the divisor, and it will give the next term of the quotient, proceed in a similar manner till the whole is finished.... | |
| Bourdon (M., Louis Pierre Marie) - 1831 - 326 σελίδες
...dividend by the first term on the left of the divisor, and the first term of the quotient is found ; multiply the divisor by this term, and subtract the product from the dividend. Divide the first term of this remainder by the first term of the divisor, and the second... | |
| Charles Davies - 1835 - 378 σελίδες
...have the following RULE. on the left of the divisor, the result is the first term of the quotient ; multiply the divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the fast term of the divisor, which gives... | |
| 1836 - 352 σελίδες
...term in the dividend by the first in the divisor, and write the result as the first in the quotient ; multiply the divisor by this term, and subtract the product from the dividend ; proceed to deal with the remainder, if any, in the same way. 43. By applying the same reasoning... | |
| Charles Frederick Partington - 1838 - 1116 σελίδες
...multiply the whole divisor by this term, and subtract the product from the whole dividend. Then divide the first term of the remainder by the first term of the divisor, and the result will be the second term of the quotient ; multiply this term by the divisor, and subtract... | |
| 1838 - 372 σελίδες
...multiply the• divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor, which gives the second term of the quotient ; multiply the divisor by this second term, and subtract... | |
| Charles Davies - 1839 - 264 σελίδες
...multiply the divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor, which gives the second term of the quotient ; multiply the divisor by the second term, and subtract... | |
| Andrew Bell (writer on mathematics.) - 1839 - 500 σελίδες
...the first term of the dividend by that of the divisor, the result is the first term of the quotient. Multiply the divisor by this term, and subtract the product from the dividend. Consider the remainder as a new dividend, arrange its terms, and proceed as before ; and... | |
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