 | Augustus De Morgan - 1831 - 108 σελίδες
...exponent of c. Thus c>xc3 = c7. To divide a term of the second series by one which comes before it, subtract the exponent of the divisor from the exponent of the dividend, and make this difference the exponent of c. Thus, c1 -> = <?' c4 These rules are intelligible for all... | |
 | 1836 - 352 σελίδες
...exponent of c. Thus c4xc3 = c7. To divide a term of the second series by one which comes before it, subtract the exponent of the divisor from the exponent of the dividend, and make this difference the exponent of c. Thus26 These rules are intelligible for all terms of the... | |
 | John H. Harney - 1840 - 298 σελίδες
...quotient of a2 by a? a4 by tfi? ai6 by aV2? In order to obtain the quotient of one power of a by another, subtract the exponent of the divisor from the exponent...of the dividend. The remainder is the exponent of a in the quotient. 3. Divide a4 by a Лпз. a». 4. a8 by a2 5. aз by a2 6. ai0 by a2 7. ai6 by ai5... | |
 | Ebenezer Bailey - 1840 - 270 σελίδες
...required to divide a power of any letter, as a5, by another power of the same letter, as a3, we must subtract the exponent of the divisor from the exponent of the dividend, and the remainder icill be the exponent of the quotient. 2. Divide a6 by a3. ANs. a3. 3. Divide a3... | |
 | Frederick Emerson - 1846 - 318 σελίδες
...the third power, and the product again by the third power gives the ninth power; as 23 X 23 X 23=29. Division being the reverse of multiplication, it is...the quotient. For example, if we divide the fifth po.wsr by the third power, the quotient is the second power; as 35-i-33=32: if we divide the ninth... | |
 | Elias Loomis - 1846 - 376 σελίδες
...EXPONENTS IN DIVISION. In order to divide quantities expressed by different powers of the same letter, subtract the exponent of the divisor from the exponent of the dividend. EXAMPLES. Divide a8 a* 6e ce A7 xg yii By a3 a3 b3 с4 А4 ж3 у8 Quotient a" Let it be required to... | |
 | Charles William Hackley - 1846 - 542 σελίδες
...general RULE FOR EXPONENTS IN DIVISION. In order to divide quantities expressed ly the same letter, subtract the exponent of the divisor from the exponent of the dividend, whatever may be the nature of the exponents. This is the same rule as that established in (Art. 17)... | |
 | Elias Loomis - 1846 - 380 σελίδες
...in some cases to negative exponents. Thus, let it be required to divide a3 by a5. We are directed to subtract the exponent of the divisor from the exponent of the dividend. We thus obtain But a3 divided by a5 may be written — ; and since the value Ct of a fraction is not... | |
 | Thomas Tate (mathematical master.) - 1847 - 138 σελίδες
...required to divide a5 by a2. Here we have, g!=axaxaxaxa=qxaxa=a\ In this a? ax a case it will be seen that we subtract the exponent of the divisor from the exponent of the dividend to obtain the exponent of the quotient. Thus, we have generally, -=a«-"' ..... (1) a" v ' Let m—n... | |
 | Frederick Emerson - 1849 - 304 σελίδες
...as 23 X 23 X 23=29. Division being the reverse of multiplication, it is evident, that if we/subtract the exponent of the divisor from the exponent of the...dividend, the remainder is the exponent of the quotient J For example, if we divide the fifth power by the third power, the quotient is the second power; as... | |
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Division being the reverse of multiplication, it is evident, that if we subtract the exponent of the divisor from the exponent of the dividend, the remainder is the exponent of the quotient. 
