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A TABLE
Showing the Expansion of Water by Heat.

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F.

R.

To reduce any number of degrees of Temperature on

Pahrenheits Scale, to the number of degrees of an equal Temperature on Reaumer's Scale; and also to the number of degrees of an equal Temperature on the Centigrade Scale, or otherwise.

1.- Above the Freezing Point. Any number of degrees of Fahrenbeit, minus 32, multiplied by 4 and divided by 9 = Reaumur.

45 x 4 Thus, 77 – 32 = 45, and

= 20.

9
R.

20 x 9
Or, = 45, and 45 + 32 = 77.

4

2.-Below the Freezing Point. Any number of degrees of Fahrenheit, plus 32, multiplied by 4 and divided by 9 = Reaumur.

54 x 4

R. Thus, 22 + 32 = 54, and

= 24

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F.

9

R.

F.

Or,

24 x 9

= 54, and 54 - 32 = 22. 4

3.- Above the Freezing Point.

Any number of degrees of Fahrenheit, minus 32, multiplied by 5 and divided by 9 = Centigrade.

F.

135 x 5

C. Thus, 167 – 32 = 135, and

= 75. 9

F.

Or,

C.
75 x 9

= 135, and 135 + 32 = 167.
5

4.-Below the Freezing Point.

Any number of degrees of Fahrenheit, plus 32, multiplied by 5 and divided by 9 = Centigrade

F.

45 x 5

C. Thus, 13 + 32 = 45, and

= 25. 9

F.

Or,

C.
25 x 9

= 45, and 45
5

32 = 13.

A TABLE

Shewing the Quantity and Weight of a Superficial Foot

of Brick-work, from half a brick, to two and a half bricks in thickness.

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A TABLE

Of the Specific Gravities of those Bodies chiefly used

in Machinery, Building, &c. showing, in Avoirdupois Ounces and Pounds, the Weight of a Cubic Foot of each Body; also the Weight of a Cubic Inch, and the number of Cubic Inches in a Pound, with Multipliers to each, for finding the Weight when the Dimensions are given.

Weight

of a Cubic Foot.

Weight of a
Cubic Inch.

No. of Cubic

Inches in a Pound.

Multipliers

Names of Bodies.

...... 7271

............

OZ.

lb.
Copper, cast 8788549.25
Copper, sheet... 8915 557.18
Brass, cast 8396 524.75
Iron, cast

454.43
Iron, bar......... 7631 476.93
Lead

11344 709.00
Steel, soft 7833 489.56
Steel, hard 7816 488.50
Zinc, cast

7190

449.37 Tin, cast .........

7292 455.75 Bismuth

9880 619.50 Gun metal 8784 549.00 Sand

1520 95.00 Coal...

1250 78.12 Brick

2000 125.00 Stone, paving... 2416 151.00 Slate

2672 167.00 Marble

2742 171.37 White lead....... 3160 197.50 Glass

2880 180.00 Tallow

945 59.06 Cork

240

15.00 Larch

544

34.00 Elm......... 556 34.75 Pine, pitch

OZ.
5.086 3.146
5.159 3.103
4.852 3.293
4.203 3.802
4.410 3.623
6.456 2.437
4.527 3.530
4.517 3.537
4.156 3.845
4.215 3.790
5.710 2.789
5.0775 3.147
.8785 18.190
.7225 22.120
1.156 13.824
1.396 11.443
1.544 10.347
1.585 10.083
1.826

8.750
1.664 9.600
.5462 29.258
.138

115.200 .315 50.823 .321

660 41.25

49.726 .382 41.890

.3178 .3225 .3037 .263 .276 .4103 2833 .2827 .26 .2636 .3585 .3177 055 *0452 .0723 .0873 .0967 .0991 .1143 .1042 .9342 .0087 .0197 .0201 .024

A TABLE

Of Specific Gravities, &c.---(continued)

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The 1st, 2nd, 3rd, and 4th columns require no farther explanation than the titles they bear; the fifth column is to find the weight of any number of cubic inches, in avoirdupois pounds, of any of the different bodies required.

Example 1.-Suppose a piece of cast iron to be 563 inches long, 16 inches broad, and $ of an inch in thickness, required its weight.

56.75 x 16.5 x .75 = 702.28125 cubic inches, X.263 = 184.7 lbs. nearly. EXAMPLE 2.- Required the weight of an imperial gallon of proof spirits.

277.274 x .03352 = 9.294 lbs. nearly.

EXAMPLE 3.—Required the thickness of metal for a concave copper ball, 8 inches diameter without, so as to sink to its centre in common water.

83 x .5236 = 268.0832 cubic inches in the ball, ; 2 = 134.0416 cubic inches to be immersed, or cubic inches of water to be removed. -Then 134.0416 x .578 weight of a cubic inch of water = 77.4760448 ounces weight of water displaced, or, the weight of the copper ball ; which divide by 5.159, the weight of a cubic inch of copper, = 15.0176 cubic inches of copper in the ball.

Again, 82 x .7854 x 4 = 202.0624 square inches, the superficies of the ball; and 15.0176 • 202.0624 = .0743 inches, the required thick

ness of the copper nearly. EXAMPLE 4.-Required the weight necessary to counterpois a float of paving-stone proper for a steam-engine boiler, &c., the float being 14 inches diameter and 24 inches thick.

142 x .7854 x 2.5 = 384.846 cubic inches. Then 384.846 x .0873 = 33.597 lbs. the weight of the stone. And, 384.846 x .03617 = 13.919 lbs. weight of water displaced; then, 33.597 — 13.919 = 19.678 lbs. difference between the weight of the stone and weight of the water; and, 19.678 ; 2= 9.839 lbs. for a counterpoise, leaving the float in the water with a tendency to fall equal to 9.839 lbs. nearly.

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