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102. There are other methods of contracting the operations in multiplication, which, in certain cases, may be resorted to with advantage. Some of the most useful are the following.

44. How many gallons of water will a hydrant discharge in 13 hours, if it discharges 2325 gallons per hour?

Operation.
2325 × 13
6975

Multiplying by the 3 units, we set the first figure of the product one place to the right of the multiplicand. Now, since Ans. 30225 gallons. multiplying by 1 is taking the multiplicand once, (Art. 82,) we add together the multiplicand and the partial product already obtained, and the result is the answer. PROOF.-2325×13=30225 gallons, the same as above. Hence,

103. To multiply by 13, 14, 15, &c., or 1, with either of the other digits annexed to it.

Multiply by the units' figure of the multiplier, and write each figure of the partial product one place to the right of that from which it arises; finally, add the partial product to the multiplicand, and the result will be the answer required.

Note. This method is the same, in effect, as if we actually multiplied by the 1 ten, and placed the first figure of the partial product under the figure by which we multiply. (Art. 87. II.)

45. Multiply 3251 by 14.

47. Multiply 25039 by 16.

46. Multiply 4028 by 17. 48. Multiply 50389 by 18.

49. If 21 men can do a job of work in 365 days, how long will it take 1 man to do it?

Operation.

365X21

730

Ans. 7665 days.

We first multiply by the 2 tens, and set the first product figure in tens' place, then adding this partial product to the multiplicand, we have 7665, for the answer. PROOF.-365X21=7665 days, the same as above. Hence, 104. To multiply by 21, 31, 41, &c., or 1 with either of the other significant figures prefixed to it.

Multiply by the tens' figure of the multiplier, and write the first

figure of the partial product in tens' place; finally, add this partial product to the multiplicand, and the result will be the answer required.

Note. The reason of this method of contraction is substantially the same as that of the preceding.

50. Multiply 4275 by 31.

52. Multiply 38256 by 61.

51. Multiply 7504 by 41.

53. Multiply 70267 by 81.

54. How much will 99 carriages cost, at 235 dollars apiece?

(Art.

Operation. 23500 price of 100 C.

235

66 of 1 C.

23265

"" of 99 C.

Analysis. Since 1 carriage costs 235 dollars, 100 carriages will cost 100 times as much, which is 23500 dollars. 99.) But we wished to find the cost of 99 carriages only. Now 99 is 1 less than 100; therefore, if we subtract the price of 1 carriage from the price of 100, it will give the price of 99 carriages. Hence,

105. To multiply by 9, 99, 999, or any number of 9s.

Annex as many ciphers to the multiplicand as there are 9s in the multiplier; from the result subtract the given multiplicand, and the remainder will be the answer required.

Note. The reason of this method is obvious from the fact that annexing as many ciphers to the multiplicand as there are 9s in the multiplier, multiplies it by 100, or repeats it once more than is required; (Art. 99;) consequently, subtracting the multiplicand from the number thus produced, must give the true

answer.

55. Multiply 4791 by 99. 57. Multiply 7301 by 999.

56. Multiply 6034 by 999. 58. Multiply 463 by 9999.

59. What is the product of 867 multiplied by 84?

Analysis. We first multiply by 4 in the usual way. Now, since 8=4×2, it is plain, if the partial product of 4 is multiplied by 2, it will give the partial product of 8. But as 8 denotes tens, the first figure of its product will also be tens. (Art. 86.) The sum of the two partial products will be the answer required.

Operation. 867

84 3468 X 2

6936

72828 Ans.

Note. For the sake of convenience in multiplying, the factor 2 is placed at the right of the partial product of 4, with the sign X, between them.

60. What is the product of 987 by 486?

Operation.

987

486

Since 48=6X8, we multiply the partial product of 6 by 8, and set the first product figure 5922X8 in tens' place as before. (Art. 86.)

47376

479682 Ans.

PROOF.-987×486=479682, the same as above.

Hence,

106. When part of the multiplier is a composite number of which the other figure is a factor.

First multiply by the figure that is a factor; then multiply this partial product by the other factor, or factors, taking care to write the first figure of each partial product in its proper order, and their sum will be the answer required. (Art. 86.)

OBS. When the figure in thousands, ten thousands, or any other column, is a factor of the other part, or parts of the multiplier, care must be taken to place the first figure of its product under the factor itself, and the first figure of each of the other partial products in its own order. (Art. 86.)

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63. Multiply 665 by 82. 65. Multiply.876 by 396. 67. 324325 X 54426.

(62.) 256841

85632

2054728 X7X4

14383096

8218912

21993808512 Ans.

64. Multiply 783 by 93.
66. Multiply 69412 by 95436.
68. 256721 X 85632.

69. What is the product of 63 multiplied by 45?

Note.-By multiplying the figures which produce the same order, and adding the results mentally, we may obtain the answer without setting down the partial products.

Operation.

63

45

2835 Ans.

First, multiplying the units into units, we set down the result and carry as usual. Now, since the 6 tens into 5 units, and 3 units into 4 tens will both produce the same order, viz: tens, (Art. 86,) we multiply them and add their products men

tally.

Thus, 6×5=30, and 3×4=12; now, 30+12=42, and 1 (to carry) makes 43. Finally, 6X4=24, and 4 (to carry) make 28. PROOF.-63 X 45=2835, the same as before. Hence,

107. To multiply any two numbers together without setting down the partial products.

First multiply the units together; then multiply the figures which produce tens, and adding the products mentally, set down the result and carry as usual. Next multiply the figures which produce hundreds, and add the products, &c., as before. In like manner, perform the multiplications which produce thousands, ten thousands, &c., adding the products of each order as you proceed, and thus continue the operation till all the figures are multiplied. 70. What is the product of 23456789 into 54321? Analytic Operation.

2 3 4 5 6 7 8 9

[blocks in formation]

2X13X14X15X16X17X18X19X1

2X23×24×25×26×27×28×29×2

2X33X34X35X36X37X38×39X3 |

2X43X44X45X46X47X48X49X4 2X53X54X55×56×57×58X59X5

12 7 4 1 9 6 2 3 5 2 6 9

Explanation. Having multiplied by the first two figures of the multiplier, as in the last example, we perceive that there are three multiplications which will produce hundreds, viz: 7×1, 8×2, and 9×3; (Art. 86;) we therefore perform these multiplications, add their products mentally, and proceed to the next order. Again, there are four multiplications which will produce thousands, viz: 6 × 1, 7×2, 8×3, and 9×4. (Art. 86.) We perform these multiplications as before, and proceed in a similar manner through all the remaining orders. Ans. 1274196235269.

Note.--1. In the solution above, the multiplications of the different figures are arranged in separate columns, that the various combinations which produce the same order, may be seen at a glance. In practice it is unnecessary to denote these multiplications. The principle being understood. the process of

multiplying and adding may easily be carried on in the mind, while the final product only is set down.

2. When the factors contain but two or three figures each, this method is very simple and expeditious. A little practice will enable the student to apply it with facility when the factors contain six or eight figures each, and its application will afford an excellent discipline to the mind. It has sometimes been used when the factors contain twenty-four figures each; but it is doubtful whether the attempt to extend it so far, is profitable.

71. Multiply 25×25.

73. Multiply 81×64.

75. Multiply 194×144.

77. Multiply 4825×2352.

72. Multiply 54×54.

74. Multiply 45×92.
76. Multiply 1234 X 125.
78. Multiply 65215312.

108. By suitable attention, the critical student will discover various other methods of abbreviating the processes of multiplication.

Solve the following examples, contracting the operations when practicable.

79. 42634X63.

80. 50035 X 56.

81. 72156×1000.

82. 42000 X 40000.

83. 80000X25000.

84. 2567345×17.

85. 4300450×19. 86. 9803404 X 41.

87. 6710045×71.

88. 3456710X18.

89. 7000541×91. 90. 4102034 × 99. 91. 42304X999. 92. 50421X 9999. 93. 67243×99999. 94. 7856393.

95. 34054×639.

96. 52156X756. 97. 41907X54486.

98. 26397 X 24648.

99. 12900X14000.
100. 64172×42432.
101. 26815678×81.
102. 85X85.

103. 256X256.
104. 322X325.
105. 5234X2435.

106. 48743000X637.
107. 31890420 X 85672.
108. 80460000 × 2763.
109. 23647938485672.
110. 1256702 X 999999.
111. 684000591X61.
112. 45067034×17×51.
113. 788031245 X 81X16.
114. 61800000×23000.
115. 12563000X4800000.
116. 91300203 × 1000000.
117. 680040000 × 1000000.
118. 4000000000 × 1000000.

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