Higher Arithmetic, Or, The Science and Application of Numbers: Combining the Analytic and Synthetic Modes of Instruction : Designed for Advanced Classes in Schools and AcademiesM.H. Newman & Company, 1848 - 422 σελίδες |
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Σελίδα 51
... product is 14046 dollars . 83. The product of any two numbers will be the ... partial products . OBS . 2. The reason for placing the first figure of the ... multiplication is 3 ART . 83. ] 51 MULTIPLICATION .
... product is 14046 dollars . 83. The product of any two numbers will be the ... partial products . OBS . 2. The reason for placing the first figure of the ... multiplication is 3 ART . 83. ] 51 MULTIPLICATION .
Σελίδα 52
... multiplication is the same as in addition , and may be illustrated in a similar manner . ( Art . 53. ) Thus ... partial products , so that the same orders shall stand under each other ... product of 5690 into 52 [ SECT . IV MULTIPLICATION .
... multiplication is the same as in addition , and may be illustrated in a similar manner . ( Art . 53. ) Thus ... partial products , so that the same orders shall stand under each other ... product of 5690 into 52 [ SECT . IV MULTIPLICATION .
Σελίδα 53
... products in separate lines , placing the first figure of each line di- rectly under the figure by which you multiply . ( Art . 83. Obs . 2. ) Finally , add the several partial products together , and the sum will be the whole product ...
... products in separate lines , placing the first figure of each line di- rectly under the figure by which you multiply . ( Art . 83. Obs . 2. ) Finally , add the several partial products together , and the sum will be the whole product ...
Σελίδα 61
... partial product already obtained , and the result is the answer . PROOF . - 2325 × 13 = 30225 gallons , the same as ... partial product one place to the right of that from which it arises ; finally , add the partial product to the ...
... partial product already obtained , and the result is the answer . PROOF . - 2325 × 13 = 30225 gallons , the same as ... partial product one place to the right of that from which it arises ; finally , add the partial product to the ...
Σελίδα 62
... partial product in tens ' place ; finally , add this par- tial product to the multiplicand , and the result will be the answer required . Note . The reason of this method of contraction is substantially the same as that of the preceding ...
... partial product in tens ' place ; finally , add this par- tial product to the multiplicand , and the result will be the answer required . Note . The reason of this method of contraction is substantially the same as that of the preceding ...
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Συχνά εμφανιζόμενοι όροι και φράσεις
acres amount annexed answer required Arithmetic avoirdupois bank discount barrels bbls bought bushels called canceling ciphers CIRCULATING DECIMALS common fraction composite number compound numbers contained cost cube decimal figures decimal places denotes difference Divide the given dividend division dollars dolls Dry Measure equal expressed farthings Federal Money gallons gals given fractions given number greatest common divisor Hence hhds hundred hundredths improper fraction insured interest of $1 least common denominator least common multiple mills mixed number months multiplicand Multiply number of days numerator and denominator Operation partial product payable pence period pound premium present worth prime factors prime number principal quotient rate per cent ratio reduce the given remainder rods root shillings simple fraction sold square subtract tenths thousandths Troy Troy weight units usury weight whole number wine measure yards
Δημοφιλή αποσπάσματα
Σελίδα 371 - The square described on the hypothenuse of a rightangled triangle is equal to the sum of the squares described on the other two sides.
Σελίδα 113 - To reduce an improper fraction to a whole, or mixed number. Divide the numerator by the denominator, and the quotient will be the whole, or mixed number required.
Σελίδα 113 - To reduce a mixed number to an improper fraction. Multiply the whole number by the denominator of the fraction, and to the product add the given numerator.
Σελίδα 99 - The greatest common divisor of two or more numbers, is the greatest number which will divide them without a remainder. Thus 6 is the greatest common divisor of 12, 18, 24, and 30.
Σελίδα 261 - The rule for casting interest, when partial payments have been made, is to apply the payment, in the first place, to the discharge of the interest then due. " If the payment exceeds the interest, the surplus goes towards discharging the principal, and the subsequent interest is to be computed on the balance of principal remaining due.
Σελίδα 263 - Compute the interest to the time of the first payment ; if that be one year or more from the time the interest commenced, add it to the principal, and deduct the payment from the sum total. If there be after payments made, compute the interest on the balance due to the next payment, and then deduct the payment as above; and in like manner from one payment to another, till all the payments are absorbed; provided the time between one payment and another be one year or more.
Σελίδα 66 - The number to be divided is called the dividend. The number by which we divide is called the divisor.
Σελίδα 270 - Finally, subtract the given principal from the last amount, and the remainder will be the compound interest.
Σελίδα 394 - These are usually accounted six in number, viz. the Lever, the Wheel and Axle, the Pulley, the Inclined Plane, the Wedge, and the Screw.
Σελίδα 368 - Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.