Exercises on the geometry and measurement of plane figures, being solutions of the theorems, problems and questions in 'Wormell's Modern geometry'.Thomas Murby, 1883 - 192 σελίδες |
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Σελίδα 12
... Example 10 it is proved that the straight line which joins A with the middle point of B C is perpendicular to B C ; and in Example 8 it is proved that only one perpendicular can be drawn from A to B C. Hence the perpen- dicular from A ...
... Example 10 it is proved that the straight line which joins A with the middle point of B C is perpendicular to B C ; and in Example 8 it is proved that only one perpendicular can be drawn from A to B C. Hence the perpen- dicular from A ...
Σελίδα 13
Richard Wormell. Example 10 , that AD is perpendicular to BC and bisects BAC . But from the point D in B C it is only ... Example 10 , B E is perpendicular to A C at the point E. E Similarly , if we join D , E , the line D E will be ...
Richard Wormell. Example 10 , that AD is perpendicular to BC and bisects BAC . But from the point D in B C it is only ... Example 10 , B E is perpendicular to A C at the point E. E Similarly , if we join D , E , the line D E will be ...
Σελίδα 19
... Example 20 , if the points A B be joined and the line A B be produced to meet E F in a point N , then the dis- tances of the point N from A and B make the same angle with E F , but their sum is then greater than the sum of any other ...
... Example 20 , if the points A B be joined and the line A B be produced to meet E F in a point N , then the dis- tances of the point N from A and B make the same angle with E F , but their sum is then greater than the sum of any other ...
Σελίδα 22
... Example 6 ) . Continue CD to B , making DB DC ; then △ ABD = △ A CD , △ B = ≤ C , and △ BAD = / CAD ; .. BAC = 2 / DAC = C. = Consequently A BAC is equilateral , and AC = CB2C D. 27. In any triangle , A B C , two lines , A D , A E ...
... Example 6 ) . Continue CD to B , making DB DC ; then △ ABD = △ A CD , △ B = ≤ C , and △ BAD = / CAD ; .. BAC = 2 / DAC = C. = Consequently A BAC is equilateral , and AC = CB2C D. 27. In any triangle , A B C , two lines , A D , A E ...
Σελίδα 23
... ( Example 22 ) , and will there- fore intersect and form angles equal respectively to those formed by E F and G H. ( Example 25. ) D B But the angles included by EF and GH are equal to those formed by A B and CD ; for , con- sider any one ...
... ( Example 22 ) , and will there- fore intersect and form angles equal respectively to those formed by E F and G H. ( Example 25. ) D B But the angles included by EF and GH are equal to those formed by A B and CD ; for , con- sider any one ...
Συχνά εμφανιζόμενοι όροι και φράσεις
A B and C D ABCD adjacent angles bisect the angle centre chord circum circumference common tangents Consequently Construct a triangle DAB+ Decagon describe a circle diagonals diameter equal to half equilateral triangle Find the area given angle given circle given radius given side given straight line gonals greater Hence hypothenuse inscribed circle isosceles triangle joining the middle LADC line joining line parallel middle line middle point opposite angles parallel to A B parallelogram pendicular pentagon perimeter perpendicular bisector perpendicular to A B point of intersection polygon quadrilateral R₁ radii radius a circle rectangle regular polygon required circle respectively equal rhombus right angle right-angled triangle square tangent touch a given triangle A B D triangle required vertex
Δημοφιλή αποσπάσματα
Σελίδα 91 - If a straight line be divided into any two parts, the square on the whole line is equal to the squares on the two parts, together with twice the rectangle contained by the parts.
Σελίδα 98 - Three times the sum of the squares on the sides of a triangle is equal to four times the sum of the squares of the lines joining the middle point of each side with the opposite angles.
Σελίδα 53 - To prove that the exterior angle of a triangle is equal to the sum of the two interior opposite angles (see fig.
Σελίδα 40 - Thus, of all straight lines drawn from a given point to a given straight line, that which is perpendicular to the given line is a minimum.
Σελίδα 78 - To construct a circle which shall pass through two given points and touch a given straight line.
Σελίδα 90 - Two triangles are equal when they have two sides and the included angle of the one, respectively equal to two sides and the included angle of the other.
Σελίδα 159 - A field in the form of a right-angled triangle is to be divided between two persons, by a fence made from the right angle meeting the hypothenuse perpendicularly, at the distance of 880 links from one end ; required the area of each person's share, the length of the division-fence being 660 links. Ans. 2a. 3r.
Σελίδα 9 - If from any point within a triangle, two straight lines be drawn to the extremities of either side, their sum will be less than Hie sum of the two other sides of the triangle.
Σελίδα 30 - Any line drawn through the point of intersection of the diagonals of a parallelogram divides it into two equal quadrilaterals.
Σελίδα 46 - Ft, and to Dd. 23. The common intersection of the three lines divides each into two parts, one of which is double of the other, and this point is the vertex of three triangles which have lines drawn from it to the bisection of the bases. Apply Euc. n. 12, 13. 24. Apply Theorem 3, p.