Elements of Geometry: With Practical Applications Designed for BeginnersD. Appleton, 1853 - 320 σελίδες |
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Σελίδα 32
... A B C D required , since the three sides are equal to the three lines A , B , C. Scholium . It is obvious that the arcs described from D and F as centres , will intersect in two points G and H , thus giving two triangles , DGF and DHF ...
... A B C D required , since the three sides are equal to the three lines A , B , C. Scholium . It is obvious that the arcs described from D and F as centres , will intersect in two points G and H , thus giving two triangles , DGF and DHF ...
Σελίδα 33
... A B C D DFH and KGH , we see that DH and FH of the one are respect- ively equal to KH and GH of the other , being sides of equilateral triangles ; the angle FHG is equal to DHK , each being an angle of an equilateral triangle , ( Prop ...
... A B C D DFH and KGH , we see that DH and FH of the one are respect- ively equal to KH and GH of the other , being sides of equilateral triangles ; the angle FHG is equal to DHK , each being an angle of an equilateral triangle , ( Prop ...
Σελίδα 44
... ABCD / FG will be a convex polygon , having the same number of sides as the original polygon . And it is moreover obvious that the sum of all the interior angles of this convex A D ' F polygon is the same as the sum of all the angles of ...
... ABCD / FG will be a convex polygon , having the same number of sides as the original polygon . And it is moreover obvious that the sum of all the interior angles of this convex A D ' F polygon is the same as the sum of all the angles of ...
Σελίδα 46
... ABCD be a parallelo- gram , of which the diagonal is AC ; then will its opposite sides and angles be equal to each other , and the diagonal will divide it into two equal triangles . A D C B angle DCA , hence the two equal to two For ...
... ABCD be a parallelo- gram , of which the diagonal is AC ; then will its opposite sides and angles be equal to each other , and the diagonal will divide it into two equal triangles . A D C B angle DCA , hence the two equal to two For ...
Σελίδα 47
... ABCD be a quadrilateral , having the opposite sides equal , namely , the side AB equal to DC , and AD equal to BC ; then will these equal sides be also parallel , and the figure will be a parallelogram . с For , let the diagonal AC be ...
... ABCD be a quadrilateral , having the opposite sides equal , namely , the side AB equal to DC , and AD equal to BC ; then will these equal sides be also parallel , and the figure will be a parallelogram . с For , let the diagonal AC be ...
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Elements of Geometry With Practical Applications George R Perkins Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2023 |
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a+b+c altitude angle ABC angle ACD angle BAC bisect centre chord circ circular sector circumference circumscribed polygon coincide cone consequently convex surface cylinder diagonal diameter distance draw equal and parallel equiangular equilateral triangle equivalent exterior angle ference figure formed given line greater half the arc hypothenuse inscribed circle intersection isosceles join less Let ABC line CD lines drawn magnitude measured by half meet multiplied number of sides opposite angles parallel lines parallelogram parallelopipedon pendicular perimeter perpen perpendicular plane MN point G prism PROBLEM produced Prop proportional PROPOSITION pyramid radii radius rectangle regular polygon respectively equal right-angled triangle Sabc Schol Scholium scribed semicircle semicircumference side AC similar solid angle sphere spherical polygon square straight line suppose tangent THEOREM three sides triangle ABC triangular prism vertex VIII