Elements of Geometry: With Practical Applications Designed for BeginnersD. Appleton, 1853 - 320 σελίδες |
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Σελίδα 23
... Prop . III :) consequently the angle DGB is equal to the angle DGF : but DGF is equal to the opposite angle AGC , ( Prop . 11 :) hence the angle BGD is equal to AGC . Which is necessary , that the angle of incidence and the angle of ...
... Prop . III :) consequently the angle DGB is equal to the angle DGF : but DGF is equal to the opposite angle AGC , ( Prop . 11 :) hence the angle BGD is equal to AGC . Which is necessary , that the angle of incidence and the angle of ...
Σελίδα 24
... ( Prop . 111 , ) the triangle FBD is equal to FCD : consequently FB is equal to FC . The solution is ef- fected in the same way when the tree is supposed to stand upon an inclined sur- F face , as upon the side of a hill . D F B A B ( 34 ...
... ( Prop . 111 , ) the triangle FBD is equal to FCD : consequently FB is equal to FC . The solution is ef- fected in the same way when the tree is supposed to stand upon an inclined sur- F face , as upon the side of a hill . D F B A B ( 34 ...
Σελίδα 27
... ( Prop . II ; ) therefore these two triangles are equal in all respects , ( Prop . 111 , ) and we have the angle ACF equal to the angle GBF ; consequently the exterior angle CBD , being greater than GBF , is greater than the interior ...
... ( Prop . II ; ) therefore these two triangles are equal in all respects , ( Prop . 111 , ) and we have the angle ACF equal to the angle GBF ; consequently the exterior angle CBD , being greater than GBF , is greater than the interior ...
Σελίδα 29
... ( Prop . v . ) In like manner , in the triangle BCD , since BC is equal to BD , we have the angle BCD equal to the angle BDC . Hence the angle ACB , which is the sum of ACD and BCD , is equal to the angle ADB , which is the sum of ADC and ...
... ( Prop . v . ) In like manner , in the triangle BCD , since BC is equal to BD , we have the angle BCD equal to the angle BDC . Hence the angle ACB , which is the sum of ACD and BCD , is equal to the angle ADB , which is the sum of ADC and ...
Σελίδα 23
... Prop . 11 :) consequently the angle DGB is equal to the angle DGF : but DGF is equal to the opposite angle AGC , ( Prop . II :) hence the angle BGD is equal to AGC . Which is necessary , that the angle of incidence and the angle of ...
... Prop . 11 :) consequently the angle DGB is equal to the angle DGF : but DGF is equal to the opposite angle AGC , ( Prop . II :) hence the angle BGD is equal to AGC . Which is necessary , that the angle of incidence and the angle of ...
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Elements of Geometry With Practical Applications George R Perkins Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2023 |
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a+b+c altitude angle ABC angle ACD angle BAC bisect centre chord circ circular sector circumference circumscribed polygon coincide cone consequently convex surface cylinder diagonal diameter distance draw equal and parallel equiangular equilateral triangle equivalent exterior angle ference figure formed given line greater half the arc hypothenuse inscribed circle intersection isosceles join less Let ABC line CD lines drawn magnitude measured by half meet multiplied number of sides opposite angles parallel lines parallelogram parallelopipedon pendicular perimeter perpen perpendicular plane MN point G prism PROBLEM produced Prop proportional PROPOSITION pyramid radii radius rectangle regular polygon respectively equal right-angled triangle Sabc Schol Scholium scribed semicircle semicircumference side AC similar solid angle sphere spherical polygon square straight line suppose tangent THEOREM three sides triangle ABC triangular prism vertex VIII