Elements of Geometry: With Practical Applications Designed for BeginnersD. Appleton, 1853 - 320 σελίδες |
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Σελίδα 49
... altitude of the parallelogram ABCD . 5. The altitude of a trapezoid is the perpendicular drawn be- tween its two parallel sides ; thus , FG is the altitude of the trapezoid ABCD . F G DF A G 6. A rectangle is said to be con- D tained 5 ...
... altitude of the parallelogram ABCD . 5. The altitude of a trapezoid is the perpendicular drawn be- tween its two parallel sides ; thus , FG is the altitude of the trapezoid ABCD . F G DF A G 6. A rectangle is said to be con- D tained 5 ...
Σελίδα 50
... altitude ; then will they be equivalent . D F G D B Since they have the same altitude , their upper bases will be in the same line GC , parallel to the common base AB . We have BC equal to AD , and BF equal to AG ; we also have DC equal ...
... altitude ; then will they be equivalent . D F G D B Since they have the same altitude , their upper bases will be in the same line GC , parallel to the common base AB . We have BC equal to AD , and BF equal to AG ; we also have DC equal ...
Σελίδα 51
... altitude , are equivalent . Let the two triangles ABC , ABD have the same base AB , and the same altitude ; then will they be equivalent . A G F their vertices will be Draw AF parallel to Since they have the same altitude , the line CD ...
... altitude , are equivalent . Let the two triangles ABC , ABD have the same base AB , and the same altitude ; then will they be equivalent . A G F their vertices will be Draw AF parallel to Since they have the same altitude , the line CD ...
Σελίδα 52
... altitude , or being situated between the same parallels , are equivalent . ( 44. ) PROBLEM . To find a triangle that shall be equivalent to a given polygon . Let ABCDF be the given polygon . Draw the diagonal CF , cutting off the ...
... altitude , or being situated between the same parallels , are equivalent . ( 44. ) PROBLEM . To find a triangle that shall be equivalent to a given polygon . Let ABCDF be the given polygon . Draw the diagonal CF , cutting off the ...
Σελίδα 53
... altitude ; then will the triangle be half the parallelogram . B For , draw the diagonal BD of the parallelogram , di- viding it into two equal parts , ( B. I , Prop . xxvii . ) Now , since the triangles ABF , ABD have the same base and ...
... altitude ; then will the triangle be half the parallelogram . B For , draw the diagonal BD of the parallelogram , di- viding it into two equal parts , ( B. I , Prop . xxvii . ) Now , since the triangles ABF , ABD have the same base and ...
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Elements of Geometry With Practical Applications George R Perkins Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2023 |
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a+b+c altitude angle ABC angle ACD angle BAC bisect centre chord circ circular sector circumference circumscribed polygon coincide cone consequently convex surface cylinder diagonal diameter distance draw equal and parallel equiangular equilateral triangle equivalent exterior angle ference figure formed given line greater half the arc hypothenuse inscribed circle intersection isosceles join less Let ABC line CD lines drawn magnitude measured by half meet multiplied number of sides opposite angles parallel lines parallelogram parallelopipedon pendicular perimeter perpen perpendicular plane MN point G prism PROBLEM produced Prop proportional PROPOSITION pyramid radii radius rectangle regular polygon respectively equal right-angled triangle Sabc Schol Scholium scribed semicircle semicircumference side AC similar solid angle sphere spherical polygon square straight line suppose tangent THEOREM three sides triangle ABC triangular prism vertex VIII