 | John Bonnycastle - 1811 - 230 σελίδες
...and multiply the remainder by the number itself, the product shall be 21. Ans. 7 or 3. 11. To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 12. It is required to divide the number 24 into two such parts, that their product may be equal to... | |
 | Charles Butler - 1814 - 528 σελίδες
...lew ; v by theprob.x1 4 -- =ic,'.-i=^/ -- ,bx <2x = 12, and— =—=8. a 3 28. Divide the number 25 into two such parts, that the sum of their square roots may be 7. Let o=25, fc=7. x=one part, then a—x=the other, v by theprob. ^x+ ^/a—x=b; square both sides,... | |
 | Thomas Simpson - 1821 - 426 σελίδες
...y== 1,and y = 4 + \/ | ; consequently o; (1+J/) =! + \/£• PROBLEM LI. To divide the number 100 (a} into two such parts, that the sum of their square roots may be 14 (bJ * Let the greater part be x, and the lesser will be a — x ; therefore, ly the problem, \/ x +... | |
 | Charles Tayler - 1824 - 350 σελίδες
...numbers is 10, and the sum of their squares is 52. What are the numbers ? ANS, 6 and 4. 8. Divide 89 into two such parts that the sum of their square roots may be 13. ANs. 64 and 25. 9. There are two numbers, whose difference' is to the difference of their square... | |
 | Silvestre François Lacroix - 1825 - 404 σελίδες
...of two numbers being given ; to find the numbers. Ans. a — v6 — o* and a + V6 — o» . 141. Tn divide the number 100 into two such parts, that the...multiplied into the third, may be equal to 63 ; and the sum of the second and third, multiplied into the first equal to 28 ; also, that the sum of the first... | |
 | Peter Nicholson - 1825 - 1046 σελίδες
...was 50l. more than A.'s, was in trade five months ; what was A.'s stock ? Ans. 1 00l. 18. To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. IQ. A and В distribute 12001. each among a certain number of persons ; A relieves 40 persons more... | |
 | Bourdon (M., Louis Pierre Marie) - 1831 - 446 σελίδες
...and multiply the remainder by the number itself, the product shall be 21. Ans. 1or 3. 19. To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 2Q. It is required to divide the number 24 into two such parts, that their product may be equal to... | |
 | Charles Davies - 1835 - 378 σελίδες
...difference, multiplied by the lesser, is equal to 12 ? Ans. 4 and 7, or fv/2 and y ^2. 3. To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 4. It is required to divide the number 24 into two such parts, that their product may be equal to 35... | |
 | Silas Totten - 1836 - 320 σελίδες
...the difference of their squares, may all be equal to one another. Ans. ^ ± J V5, and f ± \ V5. 17. Divide the number 100 into two such parts, that the...sum of their square roots may be 14. Ans. 64 and 36. 18. Divide the number 40 into two such parts, that twice their product shall be equal to the cube of... | |
 | 1838 - 372 σελίδες
...difference, multiplied by the lesser, is equal to 12 ? Ans. 4 and 7, or •§ v/2 and y V'23. To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 4. It is required to divide the number 24 into two such parts, that their product may be equal to 35... | |
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To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36 14. 
