A Manual of the Protracting Trigonometer: With Its Application to Rectilinear Draughting and Plotting, Trigonometry, and SurveyingSheldon, 1862 - 77 σελίδες |
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Σελίδα 26
... opposite side then of course becomes SOUTH , the right hand EAST , and the left hand WEST . If after the Trigonometer and Board are rightly adjusted , the former be set at its Meridian , and placed in contact with the North or South ...
... opposite side then of course becomes SOUTH , the right hand EAST , and the left hand WEST . If after the Trigonometer and Board are rightly adjusted , the former be set at its Meridian , and placed in contact with the North or South ...
Σελίδα 27
... opposite angles , the INNER reading on the Protractor limb is used ; and the instrument with the graduated face UPWARD , is applied either to the NORTH or SOUTH borders of the board . It should however be particularly observed , that ...
... opposite angles , the INNER reading on the Protractor limb is used ; and the instrument with the graduated face UPWARD , is applied either to the NORTH or SOUTH borders of the board . It should however be particularly observed , that ...
Σελίδα 33
... opposite side of the paper ; and after that side is disposed of like the first , a third and fourth is successively taken . The operation of sticking down should be performed expe- ditiously , so as to prevent the paper becoming too dry ...
... opposite side of the paper ; and after that side is disposed of like the first , a third and fourth is successively taken . The operation of sticking down should be performed expe- ditiously , so as to prevent the paper becoming too dry ...
Σελίδα 34
... opposite quadrant with the changing angle , take their sum ; but if in adjacent quadrants , take their DIFFERENCE for the CHANGED BEARING . THIRDLY . If the sum exceeds 90 ° , subtract it from 180 ° ; and both in this case , and ...
... opposite quadrant with the changing angle , take their sum ; but if in adjacent quadrants , take their DIFFERENCE for the CHANGED BEARING . THIRDLY . If the sum exceeds 90 ° , subtract it from 180 ° ; and both in this case , and ...
Σελίδα 40
... opposite the base 47 ° 51 ' ; required the hypothenuse and the Ans . Base S Hypothenuse = 288.5 . base . = 213.9 . CASE IV . ( 36. ) The base and perpendicular being given , to find the hypothenuse and the angles . RULE . Draw one of ...
... opposite the base 47 ° 51 ' ; required the hypothenuse and the Ans . Base S Hypothenuse = 288.5 . base . = 213.9 . CASE IV . ( 36. ) The base and perpendicular being given , to find the hypothenuse and the angles . RULE . Draw one of ...
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A Manual of the Protracting Trigonometer: With Its Application to ... Josiah Lyman Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2018 |
A Manual Of The Protracting Trigonometer: With Its Application To ... Josiah Lyman Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2023 |
A Manual Of The Protracting Trigonometer: With Its Application To ... Josiah Lyman Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2023 |
Συχνά εμφανιζόμενοι όροι και φράσεις
10th side accuracy acres adjacent angle adjusting lines angles and distances angular point assumed point base Brass Instruments carry the zero centimetres clamped coincide convenient corresponding courses and distances degrees divide twice divisor Double Longitude Draughting Board East or West edge EF² equal error find the angles following courses following example GABF German silver given angle given area given distance given side Given the following hypothenuse indefinite length India Ink instrument Latitude Meridian line running Longitude column method middle side North or South obtained operation opposite paper parallel of latitude parallelogram pencil perpendicular plate Plot the field PROBLEM Protractor Vernier required side right angles scale Scale-Plate sliding square chains subtract survey surveyor three adjacent sides tract of land Trapezium trapezoid unconnected ends unit grooves unit line Vernier Guide Yale College zero grooves
Δημοφιλή αποσπάσματα
Σελίδα 14 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds.
Σελίδα 55 - To find the area of a trapezoid. RULE. Multiply half the sum of the two parallel sides "by the perpendicular distance between them : the product will be the area.
Σελίδα 15 - After remarking that the mathematician positively knows that the sum of the three angles of a triangle is equal to two right angles...
Σελίδα 68 - AC 16.25 ch., and the distance of a point P in the side AB, from the angle A 8.50 ch. ; it is required to find the distance AG of a point G in the line AC, so that a line drawn from P to G may cut off a triangle APG containing 3 acres. Ans. 9.25 ch. PROBLEM VIII. The area and base of a triangle being given, to cut off a triangle containing a given area by a line running parallel to one of the sides.
Σελίδα 13 - The diameter of a circle is a straight line passing through its center and terminated at both ends by the circumference.
Σελίδα 73 - B sin 6 2. Given the bearings of three adjacent sides of a tract of land, and the length of the middle side, to cut off, by a line running a given course, a trapezium of a given area.
Σελίδα 67 - Аь the rectangle of the given side and sine of the given angle, Is to twice the given area ; So is radius, To the other side adjacent to the given angle. Then having two sides and the included angle given, the other angles and side, if required, may be found by trig...
Σελίδα 15 - All the meridians passing through a survey of moderate extent, are considered as straight lines parallel to each other. The bearing or course of a line is the angle which it makes with a meridian passing through one end ; and it is reckoned from the north or south point of the horizon, toward the east or west. Thus, if NS represent a meridian, and the angle NAB is 40°, then the bearing of AB from the point A is 40° to the west of north, and is written N. 40° W., and read north forty degrees west....
Σελίδα 73 - To the square of the ordinate add f of the square of the abscissa, and twice the square root of the sum will be the length of the curve required.
Σελίδα 15 - В = 36° 43' ..... log. 9.776598 sum. • CASE II. 5. Wben two sides and the included angle are given, the solution may be effected by means of propositions 3 and 4. Thus, take the given angle from 180° ; the remainder will be the sum of the other two angles. Then, by proposition 3, — As the sum of the given sides is to their difference, So is the tangent of half the sum of the remaining angles to the tangent of half their difference. Half the sum of the remaining angles added to half their difference...