 | William Nicholson - 1809 - 716 σελίδες
...reduced to one which involves only one of the unknown quantities, by any of the following methods: 1" Method. In either equation, find the value of one...the other equation, which will then only contain one nuknown quantity, whose value may be found by the rules before laid down. Trom the1 first equat. *... | |
 | William Nicholson - 1819 - 432 σελίδες
...reduced to one which involves only one of the unknown quantities, by any of the following methods : 1st Method. In either equation find the value of one of...will then only contain one unknown quantity, whose VOL. I. 2J Methad. Find an expression for one of the unknown quantities in each equation ; put these... | |
 | Miles Bland - 1821 - 898 σελίδες
...equation by 5, and the second by 2, and then, subtracting the second from the first. 2. By substitution. Find the value of one of the unknown quantities, in terms of the other and known quantities, in the more simple of the two equations ; and substitute this value instead of the quantity itself... | |
 | James Ryan - 1824 - 550 σελίδες
...Ex. 20. Given ^+^=6, 64 I to find the values o / , . x and y. and += Ans. a; =12, and #=16. KULE II. Find the value of one of the unknown quantities, in terms of the other and known quantities, in the more simple of the two equations ; and substitute this value instead of the quantity itself... | |
 | James Ryan, Robert Adrain - 1824 - 542 σελίδες
...20. Given 1+1=6, V'to ^ ;, , x , v { x and vand — |-i=5|, I Ans. **=:12,. andy=16. RULE II. 248. Find the value of one of the unknown quantities, in terms of the other and known quantities, in the more simple of the two equations ; and substitute this value instead of the quantity itself... | |
 | Miles Bland - 1824 - 404 σελίδες
...equation by 5, and the second by 2, and then subtracting the second from the first. 2. By substitution. Find the value of one of the unknown quantities, in terms of the other and known quantities, in the more simple of the two equations ; and substitute this value instead of the quantity itself... | |
 | George Lees - 1826 - 276 σελίδες
...Now, x - sy^~L?—™^H- 12 - « * •— g — g "~ 2 ~~ 86. METHOD 3d, In either equation, Jind a value of one of the unknown quantities, in terms of the other and known quantities ; substitute this value for the unknown quantity in the second equation, there will thence arise an... | |
 | John Darby (teacher of mathematics.) - 1829 - 212 σελίδες
...Indeterminate Analysis. CASE I. When the given equation contains two unknown quantities. RULE. 1 . Find the value of one of the unknown quantities in terms of the rest, as in step first, in the first example. _ 2. Divide the numerator by the denominator, if divisible,... | |
 | Peter Nicholson - 1831 - 326 σελίδες
...the possible values of x and y in integer numbers, suppose the numbers a, b, c, prime to each other. Find the value of one of the unknown quantities in terms of the other. Thus, if the equation be by-lc ax—by=c, then z= — ; Or, ax+by=c, then x= — - — • Increase... | |
 | John Radford Young - 1839 - 332 σελίδες
...each unknown quantity may be obtained by either of the three following methods. First Method. (54.) Find the value of one of the unknown quantities in terms of the other and the known quantities, from the first equation, by the method already given. Find the value of the same... | |
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Find the value of one of the unknown quantities, in terms of the other and known quantities... 
