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.. quotient=197, rem. 4×1+3, or 197, rem. 7.

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6. (26 × 26-15 × 15)÷(26 +15)=(676 - 225)÷41=451÷÷41

=11=26-15.

Divisor (537523-323)÷158=537200÷158,

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8. No. of pounds=25000÷70=2500÷7=357, rem. 1, .. 358 pounds must be spun.

9. (250+173) × (250 – 173)=423 × 77=32571, .. quotient=32571÷47=693.

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11. No. of men in regiment=945-45=900, No. of men to each officer-900-45=20.

12. Since (64272-48)÷48, or 64224÷48=1338,

and,

85260-70=1218,

.. each policeman in the former has 1338-1218, or 120 persons more to look after than in the latter.

13. Sum of the ages of children

=(4×6+6×2+3 × 8 +5 × 4) years

=

= (24+12+24+20)=80 years.

No. of children in the School

6+2+8+4=20,

.. average age of the children=80 years÷20=4 years.

14. Average daily attendance

=(127+109+130 +128 +131)÷5
=625-5125.

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(3) 84fr.=(84 x 100)c. = 8400c.

=

8400c. (8400÷100)fr.=84fr.

1760fr. 5d. (1760 × 10+5)d.=17605d. (17605 × 10)c.

=176050c.

=

176050c.=(176050÷10)d.=17605d. =(17605÷10)fr.
=1760fr. 5d.

43fr. 6c.=(43 × 100+6) c. 4306c.

=

4306c.=(4306÷10)d.=430d. 6c.=(430÷10)fr. 6c.

=43fr. 6c.

(4) 57fr. 4d. 5c.=(570+4)d. 5c.=574d. 5c.=(5740+5)c. =5745c.

(5)

5745c. (5745÷10)d.=574d. 5c.=(574÷10)fr. 5c. =57fr. 4d. 5c.

66173fr. 14c. (6617300+14)c. = 6617314c.
6617314c. (6617314÷100) fr. = 66173fr. 14c.
8760fr.=(8760 x 100)c. = 876000c.
876000c. (876000÷100) fr.=8760fr.

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d.

19 41

12

228+ 4 or 232d.

2

464+1, or 465 half-pence.

£ 8. d.

35 4 6

20

half-pence

2 465

12 232 rem. d.

19 rem. 4d.

Ans. 198. 41d.

128454

2,0

d.

70,4 rem. 6d.

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7048. 12

35 rem. 48.

Ans. £35. 4s. 6d.

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q.

16

4 74713

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10063fr. 2c.=(10063 × 100+2)c. = (1006302)c.

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1006302c. (1006302÷10)d.=100630d. 2c.

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