 Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the...  Putnam's Arithmetic - Σελίδα 196των Rufus Putnam - 1849 - 264 σελίδεςΠλήρης προβολή - Σχετικά με αυτό το βιβλίο
 | A. Melrose (Teacher) - 1795 - 140 σελίδες
...divifor, thus increafed, by the laft. figure placed iu the root : Subtract the produft from the drwdend, and to the remainder annex the next period for a new dividend ; with which proceed in the fame manner, and'fo on,. till all the periods are ufed. I Required the... | |
 | John Davidson, Robert Scott (writing master) - 1818 - 190 σελίδες
...divisor. The tum of these three parts will be the complete divisor, which multiply by the last figure of the root, subtract the product from the dividend, and to the remainder bring down the next part for a new dividend. Proceed in the same manner as before to find the divisor... | |
 | Samuel YOUNG (of Manchester.) - 1833 - 272 σελίδες
...both in the root and on the right of the Disisor; also by it multiply the Divisor thus completed, and subtract the Product from the Dividend, and to the...Remainder annex the next period for a new Dividend. To the completed Divisor add the figure last put in the root ; the sum is a new Divisor, with which... | |
 | Benjamin Peirce - 1837 - 300 σελίδες
...be placed at the right of the divisor. Multiply the divisor, thus augmented, by the last figure of the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Double' the root now found for a new divisor and continue... | |
 | Benjamin Peirce - 1837 - 302 σελίδες
...be placed at the right of the divisor. Multiply the divisor, thus augmented, by the last figure of the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Double the root now found for a new divisor and continue... | |
 | John Radford Young - 1839 - 332 σελίδες
...divisor's place, and the divisor will be completed. Multiply the complete divisor by the last term of the root, subtract the product from the dividend, and to the remainder connect the three next terms, and proceed as before. For (by Art. 37,) the cube of a+b is a»+ 3a2¿>... | |
 | George Leonard (Jr.) - 1839 - 362 σελίδες
...the root already found, and also at the right of the divisor. Multiply the divisor thus increased, by the last figure in the root, subtract the product from the whole dividend, and bring down the two next figures, and so on ; but if the product be greater than... | |
 | John Husband (math. master, Berwick.) - 1841 - 126 σελίδες
...to the right ; add together these two lines for the complete divisor; multiply the sum by the second figure in the root ; subtract the product from the dividend, and to the remainder annex the third period for a new dividend. Place the square of the second figure of the root under the complete... | |
 | George Roberts Perkins - 1841 - 274 σελίδες
...the result will be the TRUE DIVISOR. Multiply the true divisor by this second figure of the root, and subtract the product from the dividend, and to the remainder annex the next period,for a SECCUD DIVIDEND. . ft IV. To the last TRUE DIVISOR, add the Jastfgure of the root, for... | |
 | George Leonard (jr.) - 1841 - 352 σελίδες
...the root already found, and also at the right of the divisor. Multiply the divisor thus increased, by the last figure^ in the root, subtract the product from the whole dividend, and bring down the two next figures, and so on ; but if the product be greater than... | |
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