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" ... =5,64 gallons. 359 If the square of the diameter of any circle be multiplied by ,7854 the product is the area. EXAMPLE. If the diameter of a circle be 45 inches, what is the area? 45X45=2025X,7854=1590 inches, and at one inch deep the content or capacity... "
The Art of Gauging Made Easy: Containing All the Principal Rules which are ... - Σελίδα 40
των Peter Jonas - 1804 - 124 σελίδες
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Mercantile Arith

Michael Walsh - 1831 - 348 σελίδες
...diameter, «nd one inch deep, what is its content in ale gallons? 45X43=2025 1 =5,64 gallons. 359 If the square of the diameter of any circle be multiplied by ,7854 the product is the area. EXAMPLE. If the diameter of a circle be 45 inches, what is the area? 45X45='2025X,7854=1590...

The Merchant and Seaman's Expeditious Measurer ...

Blunt, Edmund & George William, firm, publishers, N.Y. - 1833 - 232 σελίδες
...of a circle, which has unity for its diameter, is .7854 decimal parts thereof, it follows, that it the square of the diameter of any circle be multiplied by .7854, the product will be the area of that circle ; hence .7854 is a constant quantity, the logarithm of which is 9.89509.* If the area...

The Mercantile Arithmetic: Adapted to the Commerece of the United States, in ...

Michael Walsh - 1838 - 346 σελίδες
...inches diameter, and one inch deep, what is its content in ale gallons? 45X45=2025 =5,64 gallons. 359 If the square of the diameter of any circle be multiplied by ,7854 the product is the area. EXAMPLE. If the diameter of a circle be 45 inches, what is the area? 45X45=2025X,7854=1590...

The Merchant and Seaman's Expiditious [sic] Measurer: Containing a Set of ...

1846 - 218 σελίδες
...of a circle, which has unity for its diameter, is .7854 decimal parts thereof, it follows, that ¡I the square of the diameter of any circle be multiplied by .7854, the product will be the area of that circle ; hence .7854 is a constant quantity, the logarithm of which is 9.89509.4 1f the area...

The American Arithmetic: In which the Principles of Numbers are Explained ...

James Robinson - 1850 - 342 σελίδες
...pjf the diameter X by one fourth of 3. 14 16 = the area. And 3.141.6 X .! or .85 = .7854 ; hence, if the square of the diameter of any circle be multiplied by .7854, the product will be the area. And 1 -;- .7854 = 1 .2732 ; hence, if the square of the diameter of any circle be divided by 1.2736,...




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