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1

1 (3.) Tan A

cot A = cot A'

tan A Further

PM? AM? PM? + AM? (4.) Sin? A + cos2 A

+
AP2 АР

AP
AP2

1.

AP2 Hence also, transposing and taking the square root(5.) Sin A = VI - cos? A. (6.) Cos A = 1 - sino A. And again,

AP2

AM? + PM? PM? (7.) Sec A

1+ AMP AM?

1 + tan’ A.

AM
AP2 PM2+ AM?

AM (8.) Cosec A =

1 +
PM
PM?

PM = 1 + cot? A.

PM PM AM (9.) Tan A =

sin A ; cos A AM AP

AP sin A

=

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The student must make himself thoroughly master of the results in this article.

7. To express the trigonometrical ratios in terms of the sine. (1.) Cos A

1 – sino A, by Art. 6 (6.)

sin A (2.) Tan A

by Art. 6 (9.),

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Ex. If sin A , find the other trigonometrical ratios. We have, cos A = 1

(3)

= V1 - 5 = 4.
sin A
tan A =

• 중

= d.

cOS A 8. To express the trigonometrical ratios in terms of the cotangent.

1

1 (1.) Sin A =

by Art. 6 (8.) cosec A

v1 + cot A 1

1
(2.) Cos A =

by Art. 6 (7.)
1 + tan’ A
1

cot A
1 Jcot' A + 1
1 +

cot? A

1 (3.) Tan A

cot A

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sec A

=

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1

cot A (4.) Sec A

1 ;
cot? A + 1

by (2.) above, Ncot? A + 1

cot A (5.) Cosec A

V1 + coť A, by Art. 6 (8.) And in the same way the trigonometrical ratios may be expressed in terms of any one of them.

Ex. II. 1. Given sin A = 13, find the other trigonometrical ratios.

2. Given tan A = 44, find the remaining trigonometrical ratios.

1 3. If cot A = 0, show that sin A =

v1 + a

126 - 6 4. If vers A 6, then tan A

1-6 5. Construct by scale and compass an angle (1.) whose cosine is *; (2.) whose tangent is 3; (3.) whose secant is 72; (4.) whose cotangent is 2 + 13.

Prove the following identities :6. (Sin A + cos A)+ (sin A cos A)2 = 2. 7. Sec? A + cos2 B. cosec B = cosec B + sino A. sec A. 8. Sec? A.cosecA sec? A + cosec A. 9. Sec A . cosec A = tan A t cot A. 10. Sin A cos A (sin A - cosa A) (sin A + cos* A). Sec A + tan A

cosec B cot B Cosec B + cot B

tan A

sino A + sin? A cos? A + cos* A 12. 1 t sin A cos A =

1 - sin A cos A 13. (x cos 0 + y sin o) (sino + y cos 0) – (oc cos – y sin o) (a sin 0-y coso)

sec A

=

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COS A.

14. (a sin o cos + r cos 6 cos p) (6 sin o sin $ + r sin o cos o) - (6 sin o coso ro sin o sin o) (a sino sin • + r cos o sin o)

= r sin o (r cos 0 + a sin o). 15. If a = r sin 0 cos , Y = r sin o sin $, % = r cos 0, show that aca + y + za

goo 16. If a = b cos C+ c cos B, b = a cos + c cos A, c = a cos B + b cos A, show that a? + 62 - ca 2 ab cos C. 17. Given sin? A + 3 sin A 1, find sin A. 18. Given cos A - sin A find

1 19. Solve sin A

for sin A.

72 20. Find tan A, when tan A + 1 = N. sec A. 21. Given a cos A b sin A + a, find cot A. 22. Given tan’ A 7 tan A + 6 0, find tan A. 23. Show that v1 + 2 sin A cos A + V1 – 2 sin A cos A

2 cos A or 2 sin A, according as A is between 0° and 45°, or between 45° and 90°. 24. Given m sin’ A + n sinB = a cos? A,

m cos* A + n cosa B b sino A, find sin A and sin B.

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CHAPTER III.

in

B

CONTRARIETY OF SIGNS.-CHANGES OF MAGNITUDE AND SIGN OF THE TRIGONOMETRICAL RATIOS THROUGH THE FOUR QUADRANTS. 9. We have explained at some length the meaning and

use of the signs + and
algebra. They have a similar
interpretation in trigonometry.

1. Lines.-Draw the horizontal A

line A 'A, and draw BB' at right angles, meeting it in 0.· Then considering O as origin,

(1.) All lines drawn to the right parallel to A 'A are called positive, and all lines drawn to the left parallel to A'A are called negative.

All lines drawn upwards parallel to B'B are called positive, and all lines drawn downwards parallel to B'B are called negative.

(3.) Lines drawn in every other direction are considered positive, as is therefore the revolving line by which angles may be conceived to be generated.

2. Angles.-A similar convention is made forangles. Let OA be an initial line, and let a revolving line about the centre O take up the positions

P OP and OP'. Then

(1.) That direction of revolution is considered positive which is contrary to that of the hands of a watch, and the angle generated is a positive angle.

(The positive direction is then upwards.) Thus, AOP is a positive angle.

(2.) The negative direction of revolution is the same as that of the hands of a watch, and the angle thus generated is a negative angle.

(The negative direction is then downwards.)

Thus, AOP is a negative angle.

P2 Hence, if the angles

P2 AOP and AOP' be of the same magnitude, and We have

A ZAOP A, then ZAOP'= - A. 10. We will now

P3 examine the trigono metrical ratios for angles greater than a right angle, and for negative angles.

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N4

P4

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