Arithmetic on the Productive System: Accompanied by a Key and Cubical BlocksJ.B. Lippincott & C. - 311 σελίδες |
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Σελίδα 17
... cubes ; that is , so many solid inches , and all in the form of a perfect cube , for the whole pile would be 12 inches long , 12 inches wide , and 12 inches thick . 59. Then as 12 inches are equal to 1 foot , the above cube would be 1 ...
... cubes ; that is , so many solid inches , and all in the form of a perfect cube , for the whole pile would be 12 inches long , 12 inches wide , and 12 inches thick . 59. Then as 12 inches are equal to 1 foot , the above cube would be 1 ...
Σελίδα 24
... cube of 3 ? What is the cube of 4 ? 30. What is the cube root of 8 , and why ? 2 are 4 , and 2 times 4 are 8 . A. 2 , because 2 times 31. What is the cube root of 27 of 125 of 1000 ? 32. What is the length of each side of a cubical ...
... cube of 3 ? What is the cube of 4 ? 30. What is the cube root of 8 , and why ? 2 are 4 , and 2 times 4 are 8 . A. 2 , because 2 times 31. What is the cube root of 27 of 125 of 1000 ? 32. What is the length of each side of a cubical ...
Σελίδα 212
... cube or 3d power of 5 ; and 5 × 5 × 5 × 5 or 625 , the 4th power of 5 , and so on , every power being named from the number of times the given number is used as a factor . 38. Proportionals , we have seen , may be multiplied by ...
... cube or 3d power of 5 ; and 5 × 5 × 5 × 5 or 625 , the 4th power of 5 , and so on , every power being named from the number of times the given number is used as a factor . 38. Proportionals , we have seen , may be multiplied by ...
Σελίδα 231
... cube ; and so on , as follows- Thus 3 3x3 = 3 , 1st power , or root . 9 , 2d power , or square . 3 × 3 × 3 = 27 , 3d power , or cube . 3 × 3 × 3 × 3 81 , 4th power , or biquadrate . * 3 × 3 × 3 × 3 × 3 = 243 , 5th power . 4. The INDEX ...
... cube ; and so on , as follows- Thus 3 3x3 = 3 , 1st power , or root . 9 , 2d power , or square . 3 × 3 × 3 = 27 , 3d power , or cube . 3 × 3 × 3 × 3 81 , 4th power , or biquadrate . * 3 × 3 × 3 × 3 × 3 = 243 , 5th power . 4. The INDEX ...
Σελίδα 232
... cubes of all the prime numbers between 1 and 20 . A. 15,803 . 31. Suppose there is a pile of wood , whose dimensions , that is , its length , breadth , and depth , are each 17 feet ; how many cords does the pile contain ? A. 38c . 49ft ...
... cubes of all the prime numbers between 1 and 20 . A. 15,803 . 31. Suppose there is a pile of wood , whose dimensions , that is , its length , breadth , and depth , are each 17 feet ; how many cords does the pile contain ? A. 38c . 49ft ...
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50 cents acres amount of $1 amount of $200 angles annexing annuity barrels of flour bought breadth bushels called ciphers circumference common difference common divisor compound interest contain cube root deduct denominator diameter discount Divide dividend dollars equal example factors federal money feet long Find the amount Find the sq frustrum gain gallons given number given sum greatest common divisor Hence hogshead hundred hundredths improper fraction inches indorsed least common multiple length less merchant miles million mills mixed number molasses months Multiply number of terms payable payment pence pounds present worth principal quantity quotient quotient figure rate per cent ratio Reduce remainder Repeat the Table repetend rule for finding Rule of Three shillings sold solid feet square rods square root subtract subtrahend Suppose third term thousand units vulgar fraction whole number yards of cloth
Δημοφιλή αποσπάσματα
Σελίδα 117 - Find a common measure, by dividing the greater term by the less, and this divisor by the remainder, and so on, always dividing the last divisor by the last remainder, till nothing remains; the last divisor is the common measure.* 2. Divide both of the terms of the fraction by the common measure, aud the quotients will make the fraction required. * To find the greatest common measure...
Σελίδα 118 - Mnltiple of two or more numbers is the least number that can be divided by each of them without a remainder ; thus 30 is the least common multiple of 10 and 15.
Σελίδα 123 - Multiply the numerators together for a new numerator, and the denominators together for a new denominator.
Σελίδα 39 - This is no denial of the mathematical proposition that the whole is equal to the sum of all its parts...
Σελίδα 5 - ... time He received $25 : now how many days did he work, and how many days was he idle 1 • A.
Σελίδα 211 - Lastly, multiply the third term by the continued product of the second terms, and divide the result by the continued product of the first terms, and the quotient will be the fourth term, or answer required.
Σελίδα 126 - Multiply each numerator into all the denominators except its own for a new numerator, and all the denominators together for a common denominator.
Σελίδα 182 - A Promissory Note is a written promise to pay a certain sum of money at a specified time.
Σελίδα 3 - Sixty days after sight of this first of exchange (second and third unpaid), pay to the order of ourselves £1,600 sterling value received, and charge the same to account of as advised. "Dana Land and Lumber Company. "To Messrs. Geo. Shadbolt & Son, London.
Σελίδα 121 - An Improper Fraction is one whose numerator is equal to or greater than its denominator ; as, f , -J.